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Re: Regarding Globalization

Eddy Vluggen13-Oct-09 3:10

13-Oct-09 3:10

vijaylumar wrote:
is there any another way that if we select a language then the label text should change to the selected language

Windows can't automatically translate texts. You could use an online translation-service to do the translations, but those aren't nearly as accurate as you want them to be.

For inspiration on automated translations, start with this[^] CodeProject article.

I are Troll Smile | :)

Smile | :)

Simulation mobile users in network

trungtin13-Oct-09 0:10

13-Oct-09 0:10

Hi,
I have a set of mobile users, I need to simulate this MUs in the network, this MUs transfer data to each other, one MU can search for information from other MUs.
After that measure the response time when has result.
I don’t know how to set up.
I have ideas but I do not know how to set up
Thanks.

arkiboys12-Oct-09 23:40

12-Oct-09 23:40

Hi,
Assuming I have an xml file which looks something like:

<main>
<field1>
<table>
<columns>
<column>
<ElementName>1234</ElementName>
<ElementValue>uyt</ElementValue>
</column>
...
</columns>
</table>
</field1>
...
<field2>

<table>
<columns>
<column>
<ElementName>654322</ElementName>
<ElementValue>xyz</ElementValue>
</column>
...
</columns>
</table>
...
</field2>
...
...
</main>

The code below retrieves the values for
ElementName>654322</ElementName> and
<ElementValue>xyz</ElementValue> as shown:

private void ModifyXML()
{
XmlDocument doc = new XmlDocument();
doc.Load(strPath);

// Retrieve all prices.
XmlNodeList nodeList = doc.GetElementsByTagName("ElementName");

foreach (XmlNode node in nodeList)
{
string strValue = node.ChildNodes[0].Value.ToString();
if (strValue.ToLower() == "654322")
{
ListBox1.Items.Add(node.OuterXml);
ListBox1.Items.Add(node.NextSibling.OuterXml);
ListBox1.Items.Add("");

//Console.WriteLine(node.ChildNodes[0].Value);
//Console.WriteLine(node.NextSibling.InnerXml);
}
}
}

Question:

Please note that I do not want to use xpath or linq or database. Just the xmlDocument for business reasons

Using this code below, how can I add a column element i.e.

Thanks

<column>
<ElementName>newValue</ElementName>
<ElementValue>newdata</ElementValue>
</column>

OR

delete one of the above column elements i.e. to remove:
<column>
<ElementName>654322</ElementName>
<ElementValue>xyz</ElementValue>
</column>

Re: xmlDocument

SeMartens12-Oct-09 23:55

12-Oct-09 23:55

Hi,

you could use the AppendChild and RemoveChild methods of the XmlNode-class. For this navigate to the node you want to remove and call

nodeToRemove.ParentNode.RemoveChild(nodeToRemove)

To add a new node call

node.AppendChild(newNode)

Have a look here for the full documentation

http://msdn.microsoft.com/en-us/library/system.xml.xmlnode_members.aspx[^]

Regards
Sebastian

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

Re: xmlDocument

arkiboys13-Oct-09 0:43

13-Oct-09 0:43

Hi,
I have been looking at msdn samples.
It seems I am having problems with .Append
How do I append something like:
<column>
<ElementName>654322</ElementName>
<ElementValue>xyz</ElementValue>
</column>

Re: xmlDocument

SeMartens13-Oct-09 0:46

13-Oct-09 0:46

You have to create a new node column. Then create nodes for elementname and elementvalue. Append these nodes to the column node. Last step is to append the column node to the node in your document.

Btw, if you want to create nodes, use the CreateNode method of your XmlDocument.

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

Re: xmlDocument

arkiboys13-Oct-09 0:51

13-Oct-09 0:51

Not sure what you mean.
How is this possible to tell the system where exactly in the hierarchy to place this elelemnt within the file?
Are you able to write a test sample based on the xml I gave before?
Thanks

Re: xmlDocument

SeMartens13-Oct-09 1:02

13-Oct-09 1:02

Well I will try (without intellisense)...

private void ModifyXML()
{
   XmlDocument doc = new XmlDocument();
   doc.Load(strPath);

    // Retrieve all prices.
    XmlNodeList nodeList = doc.GetElementsByTagName("ElementName");

    foreach (XmlNode node in nodeList)
    {
        string strValue = node.ChildNodes[0].Value.ToString();
        if (strValue.ToLower() == "654322")
        {
            ListBox1.Items.Add(node.OuterXml);
            ListBox1.Items.Add(node.NextSibling.OuterXml);
            ListBox1.Items.Add("");
          
            // create new column node
            XmlNode columnNode = doc.CreateElement("column");
            // create elementName
            XmlNode elementNameNode = doc.CreateElement("elementName");
            // create elementValue
            XmlNode elementValueNode = doc.CreateElement("elementValue");
            // set values
            elementNameNode.InnerText = "foo";
            elementValueNode.InnerText = "bar";
            // append to column node
            columnNode.AppendChild(elementNameNode);
            columnNode.AppendChild(elementValueNode);
            // append column node to current node
            node.ParentNode.AppendChild(columnNode);
 
           

         }
     }
}

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

Re: xmlDocument

arkiboys13-Oct-09 1:19

13-Oct-09 1:19

Hi,
I tried it with a bit of adjustments.
But I get this:

<column>
<ElementName>1234</ElementName>
<ElementValue>uyt</ElementValue>
<column>
<ElementName>newKey</ElementName>
<ElementValue>newValue</ElementValue>
</column>
</column>

instread of:

<column>
<ElementName>1234</ElementName>
<ElementValue>uyt</ElementValue>
<column>
<column>
<ElementName>newKey</ElementName>
<ElementValue>newValue</ElementValue>
</column>

-----------
This is the code:

Thanks

private void LoadXMLmodify()
{
XmlDocument doc = new XmlDocument();
doc.Load(strPath);

// Retrieve all prices.
XmlNodeList nodeList = doc.GetElementsByTagName("mapKey");

foreach (XmlNode node in nodeList)
{
string strValue = node.ChildNodes[0].Value.ToString();
if (strValue.ToLower() == "0024007")
{
if (node.NextSibling.InnerXml.Trim() == "1")
{
string strMapValue = node.NextSibling.InnerXml.Trim();

//Remove element...
//Debug.WriteLine("mapKey : " + strValue + " and mapValue : " + strMapValue + " removed.");
//node.RemoveChild(node.FirstChild);

//Add element...
XmlNode columnNode = doc.CreateElement("Mapping");
XmlNode elementKeyNode = doc.CreateElement("mapKey");
XmlNode elementValueNode = doc.CreateElement("mapValue");

elementKeyNode.InnerText = strValue;
elementValueNode.InnerText = "999";

columnNode.AppendChild(elementKeyNode);
columnNode.AppendChild(elementValueNode);

node.ParentNode.AppendChild(columnNode);

//string strMapValue = node.NextSibling.InnerText;
//Debug.WriteLine("mapValue changed from : " + strMapValue + " to : " + "newValue");
//node.NextSibling.InnerText = "newVlaue";

//doc.Save(strPath);
}
}
}

doc.Save(strPath);

}

Re: xmlDocument

SeMartens13-Oct-09 1:25

13-Oct-09 1:25

okay, try node.parentnode.parentnode

You are appending the new column node to an existing column node, but it must be the node above the existing column node.

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

Re: xmlDocument

arkiboys13-Oct-09 1:29

13-Oct-09 1:29

Error:
In my code I sent you it gives an error on the line:
foreach(XmlNode node in nodeList)

It says: The element list has changed. The enumeration operation failed to continue.
Thanks

Re: xmlDocument

SeMartens13-Oct-09 1:32

13-Oct-09 1:32

As the error message is saying a list can not be changed during the iteration. Convert the XmlNodeList to an array and use this array to iterate through the nodes.

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

Re: xmlDocument

arkiboys13-Oct-09 1:35

13-Oct-09 1:35

The xml has many many elements and subelements...
How can This be converted to array?
And may be I should not be in the loop to save?
Thanks

Re: xmlDocument

SeMartens13-Oct-09 1:38

13-Oct-09 1:38

Build a new list or array containing the elements of the XmlNodeList.

List<XmlNode> myNodes = new List<XmlNode>(doc.GetElementsByTagName("ElementName"));

Then iterate through myNodes.

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

Re: xmlDocument

arkiboys13-Oct-09 1:41

13-Oct-09 1:41

I guess I do not have to be in the loop when I add a new row?
Don't you think?

Re: xmlDocument

SeMartens13-Oct-09 1:47

13-Oct-09 1:47

Yes that is correct. But sometimes the logic just needs to be done within a loop. If you can avoid doing all this within the loop -> do it.

Smile | :)

Smile | :)

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

Re: xmlDocument [modified]

arkiboys13-Oct-09 1:59

13-Oct-09 1:59

I have modified the loop so that as soon as there is an addition to the xml, then save the file and then break; this way it comes out of the loop.

Question:
I can see the xml I added is in there, so I now try to remove it as follows:
Do you see what is wrong here because i get an error on line with ????? it says object reference not set to an instance of an object.
Not that this error does not always happen. It seems I have to close the file and then re-open it to work correctly. Is this the way it should be?

Thanks

private void LoadXMLRemove()
{
XmlDocument doc = new XmlDocument();
doc.Load(strPath);

// Retrieve all .
XmlNodeList nodeList = doc.GetElementsByTagName("mapKey");

foreach (XmlNode node in nodeList)
{
//?????
string strValue = node.ChildNodes[0].Value.ToString();
//???????
if (strValue.ToLower() == "0024007")
{
if (node.NextSibling.InnerXml.Trim() == "1")
{
string strMapValue = node.NextSibling.InnerXml.Trim();

//Remove element...
Debug.WriteLine("mapKey : " + strValue + " and mapValue : " + strMapValue + " removed.");
node.RemoveChild(node.FirstChild);

doc.Save(strPath);
break;
}
}
}
}

modified on Tuesday, October 13, 2009 8:05 AM

Re: xmlDocument

SeMartens13-Oct-09 2:09

13-Oct-09 2:09

It seems that the node you doesn't have a childnode. Did you try to debug?

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

Re: xmlDocument

arkiboys13-Oct-09 2:16

13-Oct-09 2:16

this error does not always happen. It seems I have to close the file and then re-open it to work correctly. Is this the way it should be?

Thanks

Re: xmlDocument

arkiboys13-Oct-09 4:23

13-Oct-09 4:23

hi,
This list requires int
How is this code corrected please?
Thanks

Re: xmlDocument

SeMartens13-Oct-09 4:27

13-Oct-09 4:27

which list?

It's not a bug, it's a feature!

Check out my CodeProject article Permission-by-aspect.

Me in Softwareland.

Re: xmlDocument

arkiboys13-Oct-09 5:00

13-Oct-09 5:00

Hi,
Any way, I am now using a string such that i transfer the xml into a string, then replace, delete what I want.
This seems to work.
Do you think it is ok to use a string as explained?
Thanks

Re: xmlDocument

Mirko198012-Oct-09 23:56

12-Oct-09 23:56

Please note that I do not want to use xpath or linq or database. Just the xmlDocument for business reasons

Why? I can understand you don't want to upgrade to .NET 3.5 to use LINQ, but SelectNodes (that uses XPath to get child nodes) is always been available in XmlDocument.

Said that, look at the XmlNode members, and you will find these two methods: AppendChild and RemoveChild.

printing 2 document to same file/ preview

samy10012-Oct-09 23:39

12-Oct-09 23:39

hi,

i am using a grid that have its own print method.
i am using in my application this grid several times.

i want to print all the grids in 1 time (i can do grid1.print , grid2.print but than i can't preview them both in one time)

is there any way to make a virual pritner that all the prints will go to it and than i wiil be able to preview it once and see all the output(and select copies,and the real printer that i want to print to)?

thanks,
Samy

Re: printing 2 document to same file/ preview

Henry Minute13-Oct-09 1:35

13-Oct-09 1:35

You could create a PrintDocument and print your grids one per page, or if they are small enough fit two or more onto the page. You will then be able to preview them all at once.

Henry Minute

Do not read medical books! You could die of a misprint. - Mark Twain
Girl: (staring) "Why do you need an icy cucumber?"
“I want to report a fraud. The government is lying to us all.”

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