ASP.NET

auto. generated code for Dataset

7-Jun-09 17:41

welcome! let me know if any other issue.

Thank you.

cheers,
Abhijit
CodeProject MVP
Web Site:abhijitjana.net

bolly-816-Jun-09 11:35

bolly-81

6-Jun-09 11:35

can't see automatic generated code (Cs file) for Dataset object .

any help

Re: auto. generated code for Dataset

AlexeiXX36-Jun-09 12:27

AlexeiXX3

6-Jun-09 12:27

To see the autogenerated code
Select the project and click the "Show all files" option at the top of the solution explorer, then expand the dataset in the solution explorer
Any changes you make to that code will be overwritten if you chnge something in the dataset
Instead you should use a partial class

Alexei Rodriguez

Re: auto. generated code for Dataset

bolly-817-Jun-09 4:55

bolly-81

7-Jun-09 4:55

Hola Rodriguez .
I don't find any Show all files icon in the Solution Explorer tab ,
I only have ( from left to right)

-properties
-refresh
-nest related files
-view class diagram
-copy website
-asp .net configuration

I even tried what i found in a forum about this problem :
Tools/import and export settings / reset all settings

Still doesn't work ..any suggestions ?

how to make a gridview editable [modified]

ashutosh_karna6-Jun-09 9:46

ashutosh_karna

6-Jun-09 9:46

I made a simple gridview in asp.net using the code written below. Now I want to make it editable so that at run time user can enter some data. Also,I dont want to put a thing like "edit button" ,i.e a user can simply edit a cell as he does in an excel spreadsheet. Can anybody tell me which event make the gridview editable ( I am not using any database) ?

If possible, please give some code to help me understand.

protected void Page_Load(object sender, EventArgs e)
{
dt = new DataTable();
Char[] alpha = { '#', 'A', 'B', 'C', 'D', 'E'};

for (int i = 0; i < alpha.Length; i++)
{

dt.Columns.Add(alpha[i].ToString());

}

for (int i = 0; i < 1000; i++)
{

DataRow dr = dt.NewRow();

dr[0] = i + 1;

dt.Rows.Add(dr);
}

GridView1.BorderColor = System.Drawing.Color.FromArgb(0, 0, 0);

GridView1.DataSource = dt;

GridView1.DataBind();

}

modified on Saturday, June 6, 2009 3:56 PM

Re: how to make a gridview editable

Manoranjan Sahoo7-Jun-09 17:13

Manoranjan Sahoo

7-Jun-09 17:13

Create one gridview with all template field and set textbox for that template field when it displays the data it will display in textbox so that you can edit those field without click edit button.

Then you can access those textbox value when you click on a button.

Look at the following code to do so...

<asp:GridView ID="GridView1" runat="server" Style="z-index: 106; left: 93px; position: absolute;
            top: 283px" Width="575px" EditIndex="1" AutoGenerateColumns="False">
            <Columns>
                <asp:TemplateField>
                <ItemTemplate>
                <asp:TextBox ID="txt1" runat="server" MaxLength="3" Style="position: static" CssClass ="gv" text = '<%# Eval("slNo") %>'
                 AutoPostBack ="false" TabIndex ="0"  Width="25px"  Height ="15px" Visible ="true" ></asp:TextBox>
                </ItemTemplate>
                </asp:TemplateField>
                <asp:TemplateField>
                <ItemTemplate>
                <asp:TextBox ID="txt2" runat="server" MaxLength="3" Style="position: static" CssClass ="gv" text = '<%# Eval("Name") %>'
                   AutoPostBack ="false" TabIndex ="0"  Width="250px"  Height ="15px" Visible ="true" ></asp:TextBox>
                </ItemTemplate>
                </asp:TemplateField>
                <asp:TemplateField>
                <ItemTemplate>
                <asp:TextBox ID="txt3" runat="server" MaxLength="3" Style="position: static" CssClass ="gv" text = '<%# Eval("Address") %>'
                   AutoPostBack ="false" TabIndex ="0"  Width="150px"  Height ="15px" Visible ="true" ></asp:TextBox>
                </ItemTemplate>
                </asp:TemplateField>
                
            </Columns>
        </asp:GridView>

Then Place the following code in the button click event

for (int i = 0; i <GridView1.Rows.Count; i++)
{
     GridViewRow gvr = GridView1.Rows[i];
     string str1 = ((TextBox)gvr.FindControl("txt1")).Text;
     string str2 = ((TextBox)gvr.FindControl("txt2")).Text;
     string str3 = ((TextBox)gvr.FindControl("txt3")).Text;
}

after this you can use that string value to store into database or do further process.

Manoranjan Sahoo
Vist My Blog : Manoranjan's Blog

[Message Deleted]

valmirpaixao6-Jun-09 4:02

valmirpaixao

6-Jun-09 4:02

[Message Deleted]

Re: WebControl isn't working at all. Please help me. I have tryed it for several days..

ScottM16-Jun-09 4:19

ScottM1

6-Jun-09 4:19

You need to use the Ajax timer control.
TimerControlTutorials[^]

Reposting doesn't help

Not Active6-Jun-09 4:22

Not Active

6-Jun-09 4:22

Reposting your question each day will not help you get any reponses.

Rather that just throw out the code with vague message that it doesn't work, you should describe what the problem is. Not everyone has the time or desire to copy your code compiled it and debug it for you.

only two letters away from being an asset

Some images cannot display in IE6

smraj15036-Jun-09 2:58

6-Jun-09 2:58

Hi...
In my website uploaded some images and it will be successfully uploaded into the site.
But images cannot display in IE6 it will shows a white box with left hand side having a Red 'X' in this image spaces. But i will run in firefox it will display images...anybody give solution to this problem...

Thanks in Advance...

ais076-Jun-09 3:04

ais07

6-Jun-09 3:04

If you are using javascript then there are some property which IE doesn't support.You have to check for thos property.

smraj15036-Jun-09 3:07

6-Jun-09 3:07

Hi..
I will retrieve image path from database to show the images iam didnt use any java script to display iamges... give any ideas

Thanks

Aman Bhullar6-Jun-09 3:11

Aman Bhullar

6-Jun-09 3:11

can you send me the link where the images are displayed.
It will assist me to check the problem

Regards
Aman Bhullar
www.arlivesupport.com[^]

smraj15036-Jun-09 3:31

6-Jun-09 3:31

www.subhamalai.com then goto quicksearch search the male it will displays

Aman Bhullar7-Jun-09 2:55

Aman Bhullar

7-Jun-09 2:55

hi,

i was unable to generate any search results from the site. But i read your code, try removing brackets from the image path you specified.

Regards
Aman Bhullar
www.arlivesupport.com[^]

ais076-Jun-09 3:31

ais07

6-Jun-09 3:31

What you are using to retrieve Images from database.Can you paste some code here.

smraj15036-Jun-09 3:36

6-Jun-09 3:36

<asp:DataList ID="DListSearch" runat="server" ShowFooter="true"
Width="100%" GridLines="Horizontal" ShowHeader="False" OnItemCommand="DListSearch_ItemCommand" Font-Names="Times New Roman" OnSelectedIndexChanged="DListSearch_SelectedIndexChanged" Height="100%">
<ItemTemplate>
<asp:Panel ID="Panel2" runat="server" BorderColor="#6699cc" BorderWidth="1px"
Width="100%" Height="100%">
<table style="height: 217px; color: activecaption;" width="100%">
<tr>
<td colspan="1" rowspan="1" style="text-align: left; border-right: #6699cc 1px solid; border-top: #6699cc 1px solid; border-left: #6699cc 1px solid; border-bottom: #6699cc 1px solid; background-color: #6699cc; width: 290px; height: 20px;">
<asp:LinkButton ID="lnkbtnUserName" runat="server" Text='<%# DataBinder.Eval(Container.DataItem,"username") %>' OnClick="lnkbtnUserName_Click" ForeColor="White" ></asp:LinkButton>
  ID :
<asp:Label ID="Label3" runat="server" Font-Bold="True" ForeColor="#FFFFFF" Text='<%# DataBinder.Eval(Container.DataItem,"memberid") %>'></asp:Label></td>
<td colspan="3" rowspan="1" style="text-align: right; border-right: #6699cc 1px solid; border-top: #6699cc 1px solid; font-weight: bold; border-left: #6699cc 1px solid; color: white; border-bottom: #6699cc 1px solid; background-color: #6699cc; height: 20px;">
 <asp:Label ID="lblPartAge" runat="server" Text='<%# DataBinder.Eval(Container.DataItem,"age") %>' Font-Bold="True"></asp:Label>
years old</td>
</tr>
<tr>
<td rowspan="7" style="width: 290px; text-align: center">
<a href="javascript:Openpopup('Image_Detail.aspx?PId=<%# ("~/Images/")+DataBinder.Eval(Container.DataItem,"imgview") %>')">
<asp:Image ID="ImgView" runat="server" Height="116px" Width="128px" ImageUrl='<%# ("~/Images/")+DataBinder.Eval(Container.DataItem,"imgview") %>'/></a></td>
<td style="text-align: justify; font-weight: bold; width: 283px;">
City:     </td>
<td style="text-align: justify; width: 304px;">
<asp:Label ID="lblPartLoc" runat="server" Text='<%# DataBinder.Eval(Container.DataItem,"City") %>'></asp:Label>
   </td>
</tr>
<tr>
<td style="text-align: justify; width: 283px;">
Religion:</td>
<td style="text-align: justify; width: 304px;">
<asp:Label ID="lblPartRel" runat="server" Text='<%# DataBinder.Eval(Container.DataItem,"religion") %>'></asp:Label></td>
</tr>
<tr>
<td style="width: 283px; text-align: justify">
Caste:</td>
<td style="width: 304px; text-align: justify">
<asp:Label ID="Label2" runat="server" Text='<%# DataBinder.Eval(Container.DataItem,"sub_religion") %>'></asp:Label></td>
</tr>
<tr>
<td style="text-align: justify; width: 283px;">
Ethnicity:</td>
<td style="text-align: justify; width: 304px;">
<asp:Label ID="lblPartEthn" runat="server" Text='<%# DataBinder.Eval(Container.DataItem,"ethnicity") %>'></asp:Label></td>
</tr>
<tr>
<td style="text-align: justify; width: 283px; height: 30px;">
Height:</td>
<td style="text-align: justify; width: 304px; height: 30px;">
<asp:Label ID="lblPartHeight" runat="server" Text='<%# DataBinder.Eval(Container.DataItem,"height") %>'></asp:Label></td>
</tr>
<tr>
<td style="text-align: justify; width: 283px;">
Complexion:</td>
<td style="text-align: justify; width: 304px;">
<asp:Label ID="lblPartComplex" runat="server" Text='<%# DataBinder.Eval(Container.DataItem,"complexion") %>'></asp:Label></td>
</tr>
<tr>
<td style="text-align: justify; width: 283px; height: 30px;">
Body Type:</td>
<td style="text-align: justify; width: 304px; height: 30px;">
<asp:Label ID="lblPartBodType" runat="server" Text='<%# DataBinder.Eval(Container.DataItem,"body_type") %>' Width="112px"></asp:Label></td>
</tr>
</table>
 </asp:Panel>
                       
                       
                       
                       
                       
       
</ItemTemplate>
<HeaderTemplate>
 
</HeaderTemplate>
</asp:DataList>

Abhijit Jana6-Jun-09 3:39

6-Jun-09 3:39

So, you are uploading the image into your server and stroing the image path into database want to show the image in the image box.

smraj1503 wrote:
I will retrieve image path from database to show the images iam didnt use any java script to display iamges..

Right click on the Image icon and check that path is valid or not?
Where did you write the code for upload and display? can you please put the code ?

cheers,
Abhijit
CodeProject MVP
Web Site:abhijitjana.net

smraj15036-Jun-09 3:42

6-Jun-09 3:42

Hi..
Right click on the Image icon and check that path is valid the path display the images but the same images display in firefox...

Abhijit Jana6-Jun-09 3:58

Information about Dynamic Data website...

6-Jun-09 3:58

smraj1503 wrote:
Right click on the Image icon and check that path is valid the path display the images but the same images display in firefox...

check the image url. This is problem with "/" in url.

cheers,
Abhijit
CodeProject MVP
Web Site:abhijitjana.net

sarang_k5-Jun-09 22:49

sarang_k

5-Jun-09 22:49

Hi all,

Can any one give me a good example of Dynamic data website,i.e., i want to create a login page using it and redirect to another page.

Thanks in advance

Re: Information about Dynamic Data website...

Abhijit Jana5-Jun-09 23:10