access databse into datagridview - Visual Basic Discussion Boards

My guess would be that you'll have to write your own custom openfiledialog (that inherits from the standard one)

see if these can't help:
Extend OpenFileDialog and SaveFileDialog the easy way[^]

Customizing OpenFileDialog in .NET[^]

Myprogram run very slow. I see process(Sqlservr.exe) in task manager occupy space very hight(> 1 Ghz). How to refresh SQL server in VB.NET code.

hello

your best bet is to write more efficient SQL. You may want to also get a more up to date database server, and perhaps buy some RAM

Christian Graus

Driven to the arms of OSX by Vista.

"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

myram about 2.0 Ghz but important i want question why space of SQL very hight and more increase.

hello

Because your SQL sucks, like I said.

Christian Graus

Driven to the arms of OSX by Vista.

"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

I figured I would check in to see if there were any decent questions to read/answer today - I instantly got a headache after reading the OPs question.

Any suggestions, ideas, or 'constructive criticism' are always welcome.

"There's no such thing as a stupid question, only stupid people." - Mr. Garrison

ROTFL - I know just what you mean

Christian Graus

Driven to the arms of OSX by Vista.

"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

Hello everyone,
I just wonder what's wrong with my code. Actually I want to use openfiledialog to locate an access database file and then display it in datagridview. I used following connection string:

Dim sConnectionString As String = "Provider=Microsoft.Jet.OLEDB.4.0;Extended Properties=;Data Source=" & fi.DirectoryName

and following to call the table

Dim objCmdSelect As New OleDbCommand("select * from table1" & fi.Name, objConn)

But I get the famous error: "the microsoft jet database engine cannot open the file. it is already opened exclusively by another user or you need permission to view its data."

But neither by database is open nor its password protected.

Please help me resolving this problem

I suggest you google for a tool which tells you what process has a file open. I know such a tool exists. It's plain the file is open, you need to work out why.

Christian Graus

Driven to the arms of OSX by Vista.

"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

thanks for your suggestions but I think you misunderstood my problem. Following is complete code and its not working:

If OpenFileDialog1.ShowDialog(Me) = DialogResult.OK Then
               Dim fi As New FileInfo(OpenFileDialog1.FileName)
               Dim sConnectionString As String = "Provider=Microsoft.Jet.OLEDB.4.0;Extended Properties=;Data Source=" & fi.DirectoryName
               Dim objConn As New OleDbConnection(sConnectionString)
               Dim objDataSet As DataSet = New DataSet()
               objConn.Open()
               Dim objCmdSelect As New OleDbCommand("select * from [Joint Restraint Assignments]" & fi.Name, objConn)
               Dim objAdapter1 As New OleDbDataAdapter
               objAdapter1.SelectCommand = objCmdSelect
               objAdapter1.Fill(objDataSet, "test")
               DataGridView1.DataSource = objDataSet.Tables(0).DefaultView
               objConn.Close()
           End If

I just wonder what's wrong with this code, in particular when i want to read access database file.

Ok, why do you need a fileinfo object ? I suspect that's what's locking your file. I did not misunderstand, your file is locked, if you like it or not.

Christian Graus

Driven to the arms of OSX by Vista.

"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

thanks.
what can be an alternative to fileInfo?

you have the path already, use System.IO.Path.GetDirectoryName and Path.GetFileName to get the pieces of the file path that you seem to need.

Christian Graus

Driven to the arms of OSX by Vista.

"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

sorry I didn't get it. Could you please give me an example?

In the System.IO namespace:

Path.GetDirectory("c:\documents\word.doc")

will return c:\documents

Path.GetFileName("c:\documents\word.doc")

will return word.doc.

The Path class is full of methods for manipulating and examining file paths

Christian Graus

Driven to the arms of OSX by Vista.

"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

but my file location is not fixed. I want users to select the access database file and display a table from it into datagridview.

*sigh*

Dim fi As New FileInfo(OpenFileDialog1.FileName)
Dim sConnectionString As String = "Provider=Microsoft.Jet.OLEDB.4.0;Extended Properties=;Data Source=" & fi.DirectoryName
Dim objConn As New OleDbConnection(sConnectionString)
Dim objDataSet As DataSet = New DataSet()
objConn.Open()
Dim objCmdSelect As New OleDbCommand("select * from [Joint Restraint Assignments]" & fi.Name, objConn)

So, you take the filename from the openfiledialog and use the FileInfo object to extract the directory name and the filename. Instead, you can use the methods I gave you, to get those values from the filename property of the file dialog, directly. I am at a loss how you think what I have been saying takes away from your using a dynamic filename. If the filename was fixed, you'd type in the values in your code, not use methods to work them out, surely ?

Christian Graus

Driven to the arms of OSX by Vista.

"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

that means my no need to establish a connection. Do you mean to do something like:
Dim fi As New FileInfo(OpenFileDialog1.FileName)
path.GetFileName(&fi.name)
Dim objCmdSelect As New OleDbCommand("select * from [Joint Restraint Assignments]" .....)

???

or,

path.getfilename(openfiledialog1.filename)
Dim objCmdSelect As New OleDbCommand("select * from [Joint Restraint Assignments]" .....)

i think i got it. But I am confused about the data source to be use in oledbconnection:

Path.GetFileName(OpenFileDialog1.FileName) 
Dim con As OleDbConnection = New OleDbConnection("Provider=Microsoft.jet.oledb.4.0;data source=???")

Dim path as String =Path.GetFileName(OpenFileDialog1.FileName)

will give you the path in a variable. Just calling GetFileName without storing the result, does nothing.

Christian Graus

Driven to the arms of OSX by Vista.

"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )

thanks i got it. so what should be the data source in:

Dim path1 As String = Path.GetFileName(OpenFileDialog1.FileName)
  Dim con As OleDbConnection = New OleDbConnection("Provider=Microsoft.jet.oledb.4.0;data source=???")

Dim con As OleDbConnection = New OleDbConnection("Provider=Microsoft.jet.oledb.4.0;data source=" & path1 & "")

above code works. Thank you very very much

Are you viewing the contents of table1 in MS Access while debugging? If so, MS Access is the one that's locking the database Frown | :(

I are troll Smile | :)

thanks.
no i m not. the access database as well as the table is not open.