C / C++ / MFC

Re: .lib mystery and headache

6-Mar-09 21:02

there isn't(or I couldn't find it out)plus,this is really very confused reading, can you give me some acrtiles on what each sentence in this lib mean? thanks!

Eytukan6-Mar-09 21:29

Eytukan

6-Mar-09 21:29

This[^] may help you. But I don't understand, why do you need to check them. You may want to DUMPBIN the contents of the DLL rather?

He never answers anyone who replies to him. I've taken to calling him a retard, which is not fair to retards everywhere.-Christian Graus

message associted with number?

sam_psycho6-Mar-09 6:42

sam_psycho

6-Mar-09 6:42

Hi All,
I have implemented a simple application, the WndProc method handle all messages, but when I debug the application I could see only numbers,
How can i know which message is associted with that perticular number?
more precisely I want know which number(message) WndProc handles when I minimize the application?

Re: message associted with number?[modified]

Eytukan6-Mar-09 6:52

Eytukan

6-Mar-09 6:52

WM_SIZE & SIZE_MINIMIZED.

winuser.h

If you want to know all the definitions, just right click on any of the windows Constant. like WM_SIZE, then go to definition. You'll land up in the junkyard of windows definitions WinUser.h. But it'll be in Hex as you can see.So don't search for the exact number that you get in your WndProc.

Sorry I'm editing the text for the zillionth time.- You should check for SIZE_MINIMIZED in wParam of the message.

He never answers anyone who replies to him. I've taken to calling him a retard, which is not fair to retards everywhere.-Christian Graus

modified on Friday, March 6, 2009 12:59 PM

Left Mouse Click and Hold

Software20076-Mar-09 6:26

Software2007

6-Mar-09 6:26

I would like to do the click and Hold on the mouse, I would like to have this so I can move a gauge on a graph as long as the mouse click is down. I got some feedback from this forum to use OnMouseMove, but wouldn't this only work if you actually move the mouse..I want it to wok even if I left click and hold without actually moving the mouse... Any ideas of how I can do this?

Thanks

sft

Jonnie White6-Mar-09 6:30

Jonnie White

6-Mar-09 6:30

Set a flag in OnLButtonDown() and move your gauge in the graph while flag is true (until OnLButtonUp(), where you reset the flag).

Hope that helps,

Jonnie

Software20076-Mar-09 6:50

Software2007

6-Mar-09 6:50

Thanks for the response: I tried something like this, but seems to get stuck in a loop and never move the gauge:

void CGraph::OnLButtonDown(flags,point){
m_Flag = 1;
  while(m_Flag)
   {
     //move gauge
     }
}

void CGraph::OnRButtonDown(flags,point){
    m_Flag = 0;
}

sft

Code-o-mat6-Mar-09 8:23

Code-o-mat

6-Mar-09 8:23

In OnLButtonDown, set a flag as someone else already suggested and use SetCapture[^] (Or CWnd::SetCapture) to capture the mouse input. Then in your WM_MOUSEMOVE handler, if the flag is set, perform the drag operation or whatever you need to do. In OnLButtonUp, clear the flag and use ReleaseCapture[^] to let the mouse go. Also, make a handler for WM_CAPTURECHANGED[^] and if it indicates that your window is loosing the capture, check the flag and if it is set, you know that something happened that took the mouse capture from your window while there was a drag operation in progress (for example another window was popped up) and clear the flag and do whatever else needs to do.

> The problem with computers is that they do what you tell them to do and not what you want them to do. <
> Life: great graphics, but the gameplay sux. <

Software20076-Mar-09 8:49

Software2007

6-Mar-09 8:49

Thanks - I did something close to what you suggested in concept and it worked fine.

Thanks

sft

A tricky way of manipulating memory allocation [modified]

David Crow6-Mar-09 10:15

David Crow

6-Mar-09 10:15

Software2007 wrote:
...I want it to wok even if I left click and hold without actually moving the mouse...

If the mouse is supposed to move the gauge, how would the gauge move if the mouse wasn't? In other words, what is the gauge supposed to be doing if the mouse's button is clicked but the mouse is not moving?

"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown

"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons

JackPuppy6-Mar-09 4:25

6-Mar-09 4:25

fifth Edition
in Chapter 19, there is one note:

Note: It is important to realize that a single address space consists of one executable module and several DLL modules. Some of these modules can link to a static version of the C/ C++ run-time library, some of these modules might link to a DLL version of the C/C++ run-time library, and some of these modules (if not written in C/C++) might not require the C/ C++ run-time library at all. Many developers make a common mistake because they forget that several C/C++ run-time libraries can be present in a single address space. Examine the following code:

VOID EXEFunc() {
PVOID pv = DLLFunc();
// Access the storage pointed to by pv...
// Assumes that pv is in EXE's C/C++ run-time heap
free(pv);
}

PVOID DLLFunc() {
// Allocate block from DLL's C/C++ run-time heap
return(malloc(100));
}

So, what do you think? Does the preceding code work correctly? Is the block allocated by the DLL's function freed by the EXE's function? The answer is: maybe. The code shown does not give you enough information. If both the EXE and the DLL link to the DLL C/C++ run-time library, the code works just fine. However, if one or both of the modules link to the static C/C++ run-time library, the call to free fails. I have seen developers write code similar to this too many times, and it has burned them all.

===========================================================================

At first one thing the starup() function do is to initialize a heap used by malloc and free and low-level IO manipulation use in CRT, so when there is two copies CRT liberary in one process adress and there will be two heaps for two groups of malloc and free, and that one block memory grabed by malloc can only be freed by the very free() function in the same copy.

but what free() is?

in fact free()'s source code is like this:

void free(void *ptr)
{
struct mem_control_block *free;
free = ptr - sizeof(struct mem_control_block);
free->is_available = 1;
return;
}

every malloc()function return pointer to a block,however there are some bytes ahead the block conserved for system information, and this information is stored in a struct mem_control_block, so indeed the pointer malloc()function returned points to the byte after the mem_control_block.

struct mem_control_block {
int is_available; //a flag that specify whether this block can be used by any other application
int size; //the size of the block
};

finnally, it seems no error in these code:

VOID EXEFunc() {
PVOID pv = DLLFunc();
// Access the storage pointed to by pv...
// Assumes that pv is in EXE's C/C++ run-time heap
free(pv);
}

PVOID DLLFunc() {
// Allocate block from DLL's C/C++ run-time heap
return(malloc(100));
}

if the system doesn't allow a free() to free a block in heap of another copy of CRT, then how the system is able to forbid？？？？？

Thanks for your help.
I'm struggle reading win via c/c++

Jack

modified on Friday, March 6, 2009 11:13 AM

Eytukan6-Mar-09 4:59

Eytukan

6-Mar-09 4:59

Thanks for sharing the information! lol Big Grin | :-D

He never answers anyone who replies to him. I've taken to calling him a retard, which is not fair to retards everywhere.-Christian Graus

JackPuppy6-Mar-09 5:17

6-Mar-09 5:17

Can somebody tell me what's wrong with the code?

I see no error in it, especially after i found out what free()is.

Perisic, Aleksandar6-Mar-09 6:10

6-Mar-09 6:10

Send e-mail to get answer.

JackPuppy6-Mar-09 8:49

6-Mar-09 8:49

Hey man, thanks a lot, that's what I want.
But it is still lacking of more explanation in deep, any way, it's enough.
Any more clear in-depth explanation will be appreciated!

Jack

Perisic, Aleksandar6-Mar-09 10:04

6-Mar-09 10:04

Send e-mail to get answer.

modified on Tuesday, March 10, 2009 10:16 AM

JackPuppy6-Mar-09 10:54

6-Mar-09 10:54

do you know what "ertain types of objects" are created using CRT heap? and why is a necessary?
Further, it seems unecessary to allocate a heap per CRT copy, in stead of let all CRTs use exe. heap, which is what heap meant to be.

So if the CRT heap exists, it must have a good reason. The reason lies on the data stored in the heap, what data and why stored there?

JackPuppy6-Mar-09 10:59

6-Mar-09 10:59

"d now there matching everything as if the object was created at the local heap" this is odd, then there is no need to allocate a heap for CRT.

is all this back-compatible consideration? the original CRT developers use this mechanism for some specific reason that is rarely used today but for compatible's sake Microsoft still maintain this feature?

Perisic, Aleksandar6-Mar-09 11:24

6-Mar-09 11:24

Send e-mail to get answer.

modified on Tuesday, March 10, 2009 10:16 AM

Perisic, Aleksandar6-Mar-09 12:48

6-Mar-09 12:48

Send e-mail to get answer.

modified on Tuesday, March 10, 2009 10:17 AM

JackPuppy6-Mar-09 23:08

6-Mar-09 23:08

Gorgeous! The best answer i have ever got since I have started asking for help in the internet! And I spend almost an hour to chew this answer. Thanks a ton! To make sure I've understood what you are saying,are you saying if each dll's referred CRT copy's version are the same, their would be no problem creating an object in this dll and deleting in another because they use the same allocator the same allocating algorithm??

Perisic, Aleksandar7-Mar-09 3:16

7-Mar-09 3:16

Send e-mail to get answer.

JackPuppy7-Mar-09 9:58

7-Mar-09 9:58

Hehe, I got it.

And I'm waiting for the moment I have to allocate-deallocate memory across dll boundries in my job, before that I may be follow the rule: if you get a pointer to newly created memory by a dll, then you have to use a function in this dll and past this pointer as a parameter to it to delete( release indeed) the memory.

Perisic, Aleksandar7-Mar-09 10:59

7-Mar-09 10:59

Send e-mail to get answer.

modified on Tuesday, March 10, 2009 10:17 AM

JackPuppy10-Mar-09 2:00