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Hi all,
I have a C++ dll which I can use for communication with an external device. Which works fine with one device. But when I want to get access to more than one devices it fails. But I can make it work by executing my program several times. What can I do to get it work inside of one program?
Thanks,
Ralph
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Create multiple application domains that reference the dll, so you load it seperately each time ?
Christian Graus
Please read this if you don't understand the answer I've given you. If you're still stuck, ask me for more information.
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I haven't seen your code, but from your description it sounds like you may not be completely re-initializing your DLL variables between devices.
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I created a GroupBox(groupBox1) that contains textBox and buttons(i created this with the design option on the Form).groupBox1 is on a Tab that i created it also on the design option.
After Clicking on a specific button(no matter where) the app opens a new Tab.
i want that the new Tab(tab2) will has the same groupbox1(a copy of the first-not a reference)..How can i do it?
I tried this:
GroupBox g = new GroupBox();
Thank you for your attention
G.
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i think u need to add these controls run time to the collection of controls of tab.
rahul
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Marking an answer as bad because you're not able to understand it, is not a good way to get people to want to help you.
Christian Graus
Please read this if you don't understand the answer I've given you. If you're still stuck, ask me for more information.
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i'll try to help with simple solution
1. create user control contains your groupbox
2. in the form designer, place that user control in your tab
3. if the specific button you mention before clicked, add new tab, create new instance of user control described above, place that control in your new tab
4. if you don't understand what i talk about you must :
- understand what is OOP
- understand how to create and place control in parent control at runtime
dhaim
program is hobby that make some money as side effect 
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You can't actually have a reference, a control can only be in one place at a time, so you've got no problem there.
Like people have said, you will need to create a new instance of the controls and add these new controls to the tab.
To see how you can create, setup, and add controls, just check the designers generated code.
My current favourite word is: I'm starting to run out of fav. words!
-SK Genius
Game Programming articles start - here[ ^]-
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Guys i m having access database connected in windows application
and i want to sort a table in that by the values in last column(4th) in ascending when some1 clicks on sort button
any idea??
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You have a database, run SQL against it that sorts your data.
Christian Graus
Please read this if you don't understand the answer I've given you. If you're still stuck, ask me for more information.
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u can create dataview from ur dataset and can sort the data runtime.
rahul
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if u want it handled by database server, use requery, otherwise if u want it handled by your aplication use DataView
dhaim
program is hobby that make some money as side effect 
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Hi
i am creating log file and started to add New line
i user stream write class
<br />
StreamWriter objWriter = new StreamWriter(path);<br />
if (!File.Exists(path))<br />
File.Create(path);<br />
objWriter.WriteLine("[" + DateTime.Now.ToString() + "] "+ Header + Message);<br />
<br />
objWriter.Close();<br />
when i compile the program and it start maintaining the Log and after closing the Programme i check the log file there is one one line written which the last activity that i logged.
wasim khan
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WriteLine should do it, although I am confused how this code works in general. I doubt that the if (!File.Exists code ever runs.
Environment.NewLine is how you write a new line.
Christian Graus
Please read this if you don't understand the answer I've given you. If you're still stuck, ask me for more information.
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What you want to do is to open the file for append. Instead of letting the StreamWriter create the FileStream, open the FileStream yourself so that you can use FileMode.Append when you open it.
If you want to check if the file exists, you have to do that before opening it.
Despite everything, the person most likely to be fooling you next is yourself.
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Hi i got the answere
<br />
StreamWriter objWriter = new StreamWriter(path,true);<br />
StreamWriter Contructor pass two parameter
so the path specify the File and "true" means to append the File
wasim khan
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It's overall simpler to use File.AppendText, File.WriteAllText, etc.
Christian Graus
Please read this if you don't understand the answer I've given you. If you're still stuck, ask me for more information.
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I am with a C#.net Inventory application in one of my form there is a datetimepicker whose value my change according to some selections how can I set the datetimpicker value back to current datetime on a buttion click. I put like datetimepicker1.Text=DateTime.Now.Date.ToString(); but its text is not getting the current datetime
Thanks In advance
Regarda
Anu Palavila
Thanks & Regards
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dateTimePicker1.Value = DateTime.Now.AddHours(-24);
and 24*265 hours will be equal to one year
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dateTimePicker1.Value = DateTime.Now.AddHours(-24);
and 24*365 hours will be equal to one year
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ali zaidi wrote: and 24*365 hours will be equal to one year
No.....
Christian Graus
Please read this if you don't understand the answer I've given you. If you're still stuck, ask me for more information.
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Hi,
Try
dateTimePicker1.Value = DateTime.Now.Date; . If this is not working, check whether there is any other event that is getting fired.
Hope this helps,
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I have created a window application in c# and Sqlserver 2005.
Now on my server the connection string is working properly, but on client machine my databse is not conecting.
my connection string is :
server=192.168.1.88;Data Source=NZN-7FC996E32D7\SQLEXPRESS;Database=HungerLine;Integrated Security=true
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