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You even made the correct typo by writing AndSixMilliseconds and then adding 12ms! 
Regards,
mav
--
Black holes are the places where God divided by 0...
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Why not just exit out of it? Freezing a form for 5 minutes is ugly and will guarantee that the user either kills it with task manager, reboots or calls for help.
At the very least, you should display some sort of message to let them know it's locked.
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Probably what actually will happen is, he will get a lot of bug report saying that the application hangs.
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Multiple combo-boxes are being populated using a single Access database.........but everytime I select any of the combo-box, the values in all other combo boxes also changes accordingly........since I want to generate a report using multiple selections of combo-box I want all combo-boxes to have different values of my choice.......how can i do that.........pls help me out.......!!!
- Thanks
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You asked the same question[^] two days ago and did not respond to my answer
modified 12-Sep-18 21:01pm.
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Thanks for the reply.........but I'm not getting any clue as how can I use multiple datasources when I'm using only one Access database............"empDB" is the access table and "EmpdID" is the field and likewise other fields in the same way....
pls see the used code below and guide ........
***********************************************************************************
comboID.DataSource = myDS.Tables["empDB"];
comboID.DisplayMember = "EmpID";
comboName.DataSource = myDS.Tables["empDB"];
comboName.DisplayMember = "EmpName";
comboProfession.DataSource = myDS.Tables["empDB"];
comboProfession.DisplayMember = "EmpProfession";
comboCountry.DataSource = myDS.Tables["empDB"];
comboCountry.DisplayMember = "EmpCountry";
***********************************************************************************
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Verghese wrote: comboID.DataSource = myDS.Tables["empDB"];
comboID.DisplayMember = "EmpID";
comboName.DataSource = myDS.Tables["empDB"];
comboName.DisplayMember = "EmpName";
comboProfession.DataSource = myDS.Tables["empDB"];
comboProfession.DisplayMember = "EmpProfession";
comboCountry.DataSource = myDS.Tables["empDB"];
comboCountry.DisplayMember = "EmpCountry";
You are using the same data source (see bold).
To have each combobox be selected seperately, have 4 different DataSet to be assigned to the 4 combo boxes.
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Anyway, Thanx for the reply...........but I got it the other way round........see code below......
*******************************************************************************************
OleDbConnection con = new OleDbConnection(connectionString);
OleDbCommand cmd = new OleDbCommand("select emp_name,emp_desig from emp", con);
con.Open();
OleDbDataReader dr = cmd.ExecuteReader();
while (dr.Read())
{
comboBox1.Items.Add(dr[0]);
comboBox2.Items.Add(dr[1]);
//add as many comboboxes you want to
}
dr.Close();
*******************************************************************************************
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Hello everyone,
I am doing input parameter checking for a string type, and string value except empty is valid. My function is provided to outer client to call. Sometimes I find to check null is not enough, I also need to check String.Empty.
My question is, what are the differences between null and String.Empty? I have made some web search for the answers but not very useful information.
thanks in advance,
George
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Null indicates that the string has not been initialised. Empty means that there is a zero-length string in there.
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Thanks Pete,
1.
For String.Empty, as you said, it represents a string initialized, but length is zero. Initialized means constructed (constructor called)?
2.
All variables initialized to String.Empty are pointing to the same memory address or not?
e.g.
String a = String.Empty;
String b = String.Empty;
a and b pointing to the same memory area?
regards,
George
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George_George wrote: For String.Empty, as you said, it represents a string initialized, but length is zero. Initialized means constructed (constructor called)?
Yes.
string empty1 = "";
string empty2 = string.Empty;
string empty3 = new string('');etc.
George_George wrote: All variables initialized to String.Empty are pointing to the same memory address or not?
Yes. String is a reference type. Therefore when you assign a string to another variable you are just assigning the reference.
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Hi Colin,
This line can not compile -- "string empty3 = new string('')". What do you want to show?
regards,
George
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George_George wrote: For String.Empty, as you said, it represents a string initialized, but length is zero. Initialized means constructed (constructor called)?
No, as it is static, there will only be 1 instance, and you simply refer to that single instance every time. That specific instance will only be created once, when the string type initializer runs.
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Thanks leppie,
You mean all references to String.Empty are pointing to the same instance -- an internal instance returned by String class which represents zero length string?
regards,
George
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2)
If All the variables initialized to <pre>String.Empty</pre> Then They will point to <b>different</b> memory address and all those memory addresses will contain same value "Zero Lenght String".
It is not possible that you create two different reference type variables and they have same memory reference, unless you assign one variable to another.
also remeber that
string is immutable. so every time you change the value it will be allocated and initialize with the new value again.
so if you want to do frequent string processing then use StringBuilder class.
String vs StringBuilder[^]
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Rutvik Dave wrote: If All the variables initialized to
String.Empty Then They will point to different memory address
Incorrect. Here is what reflector has to say on the subject:
public static readonly string Empty;
That means there is only one representation ever in memory. It is not copied, it is referenced. That means they will ALL point to the same memory address.
Rutvik Dave wrote: It is not possible that you create two different reference type variables and they have same memory reference, unless you assign one variable to another.
That is correct, but it does not apply to the current situation as you are not creating different objects. You are referencing an existing object.
Rutvik Dave wrote: remeber that string is immutable. so every time you change the value it will be allocated and initialize with the new value again
Also correct, but does not apply in this question.
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Colin Angus Mackay wrote: Rutvik Dave wrote:
It is not possible that you create two different reference type variables and they have same memory reference, unless you assign one variable to another.
That is correct, but it does not apply to the current situation as you are not creating different objects. You are referencing an existing object.
In case of strings it is possible to create two instances of a string object that contains the same constant string. Then the two reference types will point to the same place in memory (string interning). For example:
string str1 = "hello world";
string str2 = "hello world";
if (str1 == str2) Console.WriteLine("same reference");
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Erm, == is overriden for string, so it tests for value equality, not reference equality. But in this case, constant strings will be 'auto' interned by the compiler.
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leppie wrote: Erm, == is overriden for string
Thanks for pointing that out, you're right[^]
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It is great to always read more. 
regards,
George
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Thanks Zoltan,
1.
I have tested and get the same result from you. I think for string, since == opeartor is overridden, it compares for content of strings, correct?
2.
And for general Object type comparsion, and for the types derived from Object and is not overridden equality comparison operator, I think the memory address other than the content of instances are compared.
regards,
George
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Yes George correct, it is stated clearly in Msdn at the link I posted:
Two string values are considered equal when one of the following is true:
* Both values are null.
* Both values are non-null references to string instances that have identical lengths and identical characters in each character position.
Sometimes it's just better to look up the info.
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