C / C++ / MFC

#include "stdio.h"

void strcpyEx(char* dest, const char* source, int iLen)
{
    int i;
    for(i=0;i<iLen;++i)
    {
        dest[i] = source[i];
    }

}
int main()
{
    char a[] = {'\0','\0','H','i','\0'};
    char b[5];

    strcpy(b,a);
    printf("Attempting strcpy... b[3] is %d\n",b[3]);

    strcpyEx(b,a,4);
    printf("Attempting strcpyEx... b[3] is %d\n",b[3]);

    return 0;
}

Programm3r wrote:

I know memcpy will work but it will also wipe the data that is already in the buffer.

DavidCrow wrote:

One of the basic rules of physics states that no two objects can occupy the same space.

DavidCrow wrote:

One of the basic rules of physics states that no two objects can occupy the same space

Greetings.
--------
M.D.V.

If something has a solution... Why do we have to worry about?. If it has no solution... For what reason do we have to worry about?
Help me to understand what I'm saying, and I'll explain it better to you
“The First Rule of Program Optimization: Don't do it. The Second Rule of Program Optimization (for experts only!): Don't do it yet.” - Michael A. Jackson

Mohanraj D wrote:

what should be done??

Member 4542257 wrote:

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