C#

TreeView.Nodes.RemoveAt(0);<br />
TreeView.Nodes.AddAt(0,workNode);

DataSet utDataset = myDataAccessClass.DoSelectStoredProcedure("procStoredProcedureName");

MyDefinedSchemaDataSet myDS = new MyDefinedSchemaDataSet();

myDS.Load(utDataset.Tables[0].CreateDataReader(), LoadOption.OverwriteChanges, myDS.myTableName);

public void MyMethod(params object[] parameters)
{
   //do stuff
}

int value1 = 100;
int value2 = 0;

try
{
    int output = value1 / value2;
}
catch (DivideByZeroException dbz)
{
    Console.WriteLine("I'm here");
}

    static void Main(string[] args)
    {
        try
        {
            float a = 100;
            float b = 0;
            float c = a / b;
        }
        catch (Exception ex)
        {
            Console.WriteLine("{0}", ex.ToString());
        }


        return;
    }
}

George_George wrote:

Any comments, Pete?

static void Main(string[] args)
{
    try
    {
        float a = 100;
        float b = 0;
        float c = a / b;

        int d = (int)c;    // Here, d is int.MinValue;
    }
    catch (Exception ex)
    {
        Console.WriteLine("{0}", ex.ToString());
    }

    return;
}

from msdn:

Dividing a floating-point value by zero will result in either positive infinity, negative infinity, or Not-a-Number (NaN) according to the rules of IEEE 754 arithmetic. Floating-point operations never throw an exception.

from msdn:

If the magnitude of the result of a floating-point operation is too large for the destination format, the result of the operation is PositiveInfinity or NegativeInfinity, as appropriate for the sign of the result.