ASP.NET

20-Nov-07 19:41

I have given begindcode

while(dr10.Read())
{
Response.Write("<img src=~\"uploads\" width=\"39\" border=\"1\" height=\"40\">");
}

HTML CODE

<asp:TemplateField>
<ItemTemplate>

<asp:Label ID="lbl4" runat="server" Text='<%#DataBinder.Eval(Container.DataItem,"picture") %>'></asp:Label>
</ItemTemplate>
</asp:TemplateField>

Its not retrieving

krishna

Michael Sync20-Nov-07 19:43

Michael Sync

20-Nov-07 19:43

Have you read this one??
http://www.codeproject.com/script/comments/forums.asp?msg=2328302&forumid=12076#xx2328302xx

Don't post new post for the same question! this is not cool.

Thanks and Regards,
Michael Sync ( Blog: http://michaelsync.net)

"Please vote to let me (and others) know if this answer helped you or not. A 5 vote tells people that your question has been answered successfully and that I've pitched it at just the right level. Thanks."

John-ph20-Nov-07 19:59

John-ph

20-Nov-07 19:59

Have a look at this One[^], Two[^].

What exactly is the problem?

- Regards -
JON

Life is not measured by the amount of breaths we take, but by the moments that take our breath away.

Krishna Varadharajan20-Nov-07 21:47

20-Nov-07 21:47

Please understand, i hope u people will help me thats y iam keep sending dont mistake me r to get angry...

The producer wht u had send all storing link to the db, but i have stored a image file name as (9.jpg) no image was there, image was in separate folder having this image file 9.jpg.

In out put its receiving like 9.jpg( no image ), so how to link with that folder to retrieve the image.

Advance Thanx,

krishna

Sun Rays20-Nov-07 21:53

Sun Rays

20-Nov-07 21:53

Hi,
as you have just store image name in your database and your inmage is in another folder of your application.

So, first you have to get image name from database and then you have to concat the string of folder path of that image with file name, then you will get image.

see this below code.
your page is in forms directory and yr image is in images directory.
So now on page.

String path = Server.MapPath("../Images/" + filenameFromDatabase);

So you will get ......../Images/image1.jpg path. Now open the file.

Thanks,
Sun Rays

Rate this post if you like answer.

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Krishna Varadharajan20-Nov-07 22:25

20-Nov-07 22:25

Which one is this ' filenameFromDatabase' means ?

krishna

N a v a n e e t h20-Nov-07 22:30

N a v a n e e t h

20-Nov-07 22:30

Clickety[^]

All C# applications should call Application.Quit(); in the beginning to avoid any .NET problems.- Unclyclopedia

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John-ph20-Nov-07 22:09

John-ph

20-Nov-07 22:09

ok, all that I understand up till this moment is that you store the File Name in the Database and the Corressponding Images are stored in the folder in the server, right? can you show only the code that you use to set src property of Img?

- Regards -
JON

Life is not measured by the amount of breaths we take, but by the moments that take our breath away.

Krishna Varadharajan20-Nov-07 22:30

20-Nov-07 22:30

Response.Write("");

krishna

John-ph20-Nov-07 22:45

John-ph

20-Nov-07 22:45

krishnavaradharajan wrote:
Response.Write("");

sorry, I really don't understand what you are trying to do with the above code.

Here is the tip to solve you problem. If I have to display a Image which lies in a virtual folder in my application then I would write the code as below.

HTML

<-img id="ImgFile" runat="server">

Code-Behind

string FileName = "Pic101.gif"; <br />
ImgFile.Src = "./Images/" + FileName;

Same code will work for you with the ImageName picked from the Database and provided the corressponding Image folder should be available in the given virtual path and Corressponding Image should also availble in the folder.
Try it out.

- Regards -
JON

Life is not measured by the amount of breaths we take, but by the moments that take our breath away.

Krishna Varadharajan20-Nov-07 22:55

20-Nov-07 22:55

Thanx.

krishna

Krishna Varadharajan21-Nov-07 0:41

21-Nov-07 0:41

Its working fine iam retrieving images, but ....

For example : customer may upload 2 - 3 product details with image so we have 10 options to image upload.

So the condition is given like if i click button in new page by checking for karnataka state than all the product pictures should be displayed. because the condition iam checking for karnataka(like that i have to create 26 stats)

here iam receiving all the images as same.(it should be come different images according to that respective products.

krishna

asp.net 2.0 hosting problem

N a v a n e e t h20-Nov-07 22:13

N a v a n e e t h

20-Nov-07 22:13

krishnavaradharajan wrote:
Please understand, i hope u people will help me thats y iam keep sending dont mistake me r to get angry...

Have you tried the suggestion given by me ? What happened when you tried it. I don't think posting continuously won't help you. Try the suggestion and let me know. You code looks completely stupid to me.

All C# applications should call Application.Quit(); in the beginning to avoid any .NET problems.- Unclyclopedia

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saravanan0520-Nov-07 19:34

saravanan05

20-Nov-07 19:34

hi friends

I hosted the asp.net2.0.but it showed the error..but asp.net1.1 working properly..any difference betwen asp.net1.1 and asp.2.0 hosting.

regards
saravanan

Known Is Drop.Unknown Is Ocean

Re: asp.net 2.0 hosting problem

Michael Sync20-Nov-07 19:41

Michael Sync

20-Nov-07 19:41

There are some differences.. If your host supports both ASP.NET 1.1 and 2.0 then there should be one option to select which version you wanna use..

About Dropdownlist..

Rajeshwar Code- Developer20-Nov-07 19:10

20-Nov-07 19:10

hi i have one doubt , i have one dropdownlist and i populating 10 state_names from database, and i m using this code

string strStateId = ddlStateID.SelectedItem.ToString();

now i m selecting fifth item in dropdownlist and send it to databas e 4 update.but i m using this code if i selected fifth item but it is taking as first item only.. plz..tell me how can i do this..

thanks 2 all..

N a v a n e e t h20-Nov-07 19:13

N a v a n e e t h

20-Nov-07 19:13

Rajeshwar Developer wrote:
if i selected fifth item but it is taking as first item only

Check your page_load event code and make sure you are binding the dropdown by checking IsPostBack.

All C# applications should call Application.Quit(); in the beginning to avoid any .NET problems.- Unclyclopedia

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Rajeshwar Code- Developer20-Nov-07 19:17

20-Nov-07 19:17

hey hi brother ..thanks..

thanks 2 all..

Rajeshwar Code- Developer20-Nov-07 19:20

20-Nov-07 19:20

but brother if i put IsPostback , but after Click submit button it ll not go 2 pageload know... i was used !ISpostBack in pageload 2 populate state_nmaes in dropdownlist..

thanks 2 all..

Imran Khan Pathan20-Nov-07 19:14

Imran Khan Pathan

20-Nov-07 19:14

Rajeshwar Developer wrote:
string strStateId = ddlStateID.SelectedItem.ToString();

string strStateId = ddlStateID.SelectedItem.Text;
or
string strStateId = ddlStateID.SelectedItem.value;

Rajeshwar Developer wrote:
if i selected fifth item but it is taking as first item only.. plz..tell me how can i do this..

May be possible your dropdownlist will be bind again when you are trying to get selected value.
Check It

bEst rEgard
pAthan

please don't forget to vote on the post that helped you.

Gandalf_TheWhite20-Nov-07 19:33

Gandalf_TheWhite

20-Nov-07 19:33

Hi
Write That One in

if(!IsPostBack)
{
/* Put Your Code Here */
}

Here wat happanes if u don't write your code in this block,
Your Page Get Refreshed and It Takes it's Bydefault Value Which Is First.

Just Do IT™ [Information Technology]™ :->

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Rajeshwar Code- Developer20-Nov-07 20:21