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Dear.....
i have a page in asp.net. there is a dropdownlist and there are many buttons for other other work like calander selection etc.
but there is a button for submition of selected item from the dropdownlist. problem is that, first i select one items from dropdownlist and when i press any button then page goes to postback and selected item of the dropdownlist goes to initial position. so what can i do for that???
Please help me...
Adv thanks....
yogesh
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This gets asked at least once a week. Your drop down is data bound, and you're binding to it in your page load. When you data bind, your selection is lost, as the old data is lost, even if it was the same. Put the code in a !IsPostback block so it only populates the first time the page loads.
Christian Graus - Microsoft MVP - C++
"I am working on a project that will convert a FORTRAN code to corresponding C++ code.I am not aware of FORTRAN syntax" ( spotted in the C++/CLI forum )
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you have to move a part of your code that initial your dropdownlist in page_load event of the page to a if block
if(!IsPostBack)
{
//your code...for initial of dropdownlist
}
nobody help you...
you have to help you yourself
and this is success way.
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hi
try by using autopostback= true in properties window for the dropdownlist box.
karthi
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Hi,
I'm working on a project that would work like this:
A textbox would be on screen and once someone enters the name of a programmer in the textbox and hits the submit button, the jobs that they have to complete will display in a table. The table will have their job number, the description, and then would show the days of the week (monday, tuesday, etc.) and then the column after those would show the estimated hours for the project, then the number of hours they already completed and the last column would be the estimated hours minus the actual hours for the "hours left". Of course, any hours they added in the fields for the different days of the week would be added to the actual hours. So, for instance, the estimated hours for project was 120 hours but the actual number of hours they took to complete the project was 100 hours (total hours). Then the hours left would be 20 so that they finished the project 20 hours ahead of schedule.
I'm trying to use a Gridview control for the data but they would have to edit line by line and I would like to have them just enter the numbers in the fields for the days of the week and hit the submit button the update everything in their list of jobs. This sounds similar to a shopping cart although I've never built one of those either.
There is a table that has the programmer, jobs, estimated hours, actual hours. I don't have anything for the days of the week so I suppose I'll have to make a new table for that. My question is, is the Gridview control useful or is there another way?
I hope I was detailed enough in this. 
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hi,
I've created a login page and I added a link button on that page.
Due to authentication, I can't redirect to another page when I click on that link button until after I login.
here's what I wrote in the web.config file:
<authentication mode="Forms">
<forms loginurl="login.aspx" protection="All" defaulturl="login.aspx">
<authorization>
<deny users="?">
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You have to set defaultUrl as the page that you redirect to.
Suppose that you redirect to index.aspx
<br />
<forms loginUrl="login.aspx" protection="All" defaultUrl="index.aspx"></forms><br />
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Hi All,
I m working with fileupload server control.
and using this uploaded file(text in the fileupload) for further processing.
but this uploaded file gets cleared while postback occurs.
how can persist filename in the uploadfile server control when postback occurs?
Please HELP.
Thanks,
In Advance.
Tejesh Kamble.
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Tejesh Kamble wrote: how can persist filename in the uploadfile server control when postback occurs?
It's not possible. It's the way FileUpload control has designed
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Thanks for your valuable feedback and reply.
Tejesh Kamble.
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Okay, so here's the progression of events...
1) I built an ASP.NET application last year in Visual Studio 2005 complete with a series of reports, all created in the built-in version of Crystal Reports.
2) Everything worked great for over a year. The reports functioned well and printed on demand.
3) I got a new development box with Vista on it, installed VS2005 and added SP1 (as well as the vista hotfix). That same day, I also applied Server 2003 Service Pack 2 to my production server - a sheer coincidence that complicates my troubleshooting of this problem significantly.
4) I made some changes and re-copied the majority of the site files to the production server using the "Copy Website" functionalty (I did this - like an idiot - to sync up my new VS2005 installation with the server so it would tell me when files needed to be updated).
5) Now, my reports don't print on any machines except mine and the server. As in, if I go to the website on IE from the server or my dev box, it works. Everywhere else you can open the report for viewing, but if you click the print button or try to export, one of two things happen.
a) On some machines, it thinks for a minute, then pops a message which reads:
Acrobat could not open ‘pdf9c9.tmp’ because it is either not a supported file type or because the file has been damaged (for example, it was sent as an email attachment and wasn’t correctly decoded).
In this scenario, the printable Adobe window never actually appears.
b) On other machines, the print window pops like it's going to work, but it just sits there - blank - and appears to keep trying to refresh. It will sit there all night if you let it (I have).
I've tried rebuilding the setup package and reinstalling it at the server. No matter what I do, I still can only print reports from my box and the server. At this point, I'm completely dead in the water, since I can't print any reports - which is the primary purpose for which my people asked me to create this stupid application. Can ANYONE help with this problem?
Thanks!
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Hi,
There is the requirement like this:,
One Login page is there for User Name, Password. Here the LAN user can only Login. How we will validate for a LAN user using C#.
Thanks in Advance.
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Hi,
I need to hide the first row in the datagrid(Not header).
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Here is the code.....hope it will help you...
GridView1.Rows[0].Visible = false;
Regards,
Sandeep Kumar.V
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Thanks sandeep. It works fine.
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I want to show the selected records Details on the next page with in the Popup window.iam displaying all the details in the Datagrid,i add one Link button in the Item template when click on this link button it should show the popup window.am binding the data while page loading.
Javascript Code as follows
function openWindow(url) {
window.open(url,'Calendar',
'width=500,height=400,left=200,top=250');
}
LinkButton PostbackUrl code as follows
PostBackUrl="javascript:openWindow('UserDetails.aspx?id=<%# DataBinder.Eval(Container.DataItem,"ID") %>');">LinkButton
when am running this page am getting this error message
'The server tag is not well formed'.It is showing in the Postbackurl code line.what is wrong in this line.
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Kurian_Kurian wrote: PostBackUrl="javascript:openWindow('UserDetails.aspx?id=<%# DataBinder.Eval(Container.DataItem,"ID") %>');">LinkButton
Replace with below code.......
PostBackUrl="javascript:openWindow('UserDetails.aspx?id=<%# DataBinder.Eval(Container.DataItem,'ID') %>');
Regards,
Sandeep Kumar.V
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Hi Sandeep,
I Tried with your code,it is not showing any error,page is loading,but when i click on the Link Button am not getting the popup window,that time not showing any error message.
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hey post your code completely so that i can help you better
Regards,
Sandeep Kumar.V
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Hi Sandeep am sending my code.
why the code is not showing after posting.what format i should use for showing the complete code.Now it is showing some part only.
Javascript function
function openWindow(url) {
window.open(url,'Calendar',
'width=500,height=400,left=200,top=250');
}
Link Button Code
<asp:templatecolumn headertext="Name">
<itemtemplate>
<asp:linkbutton id="lbName" runat="server" text="<%# DataBinder.Eval(Container, "DataItem.NAME") %>"
="" postbackurl="javascript:openWindow('UserDetails.aspx?id=<%# DataBinder.Eval(Container,'DataItem.ID') %>');">LinkButton
if am just passing 'userdetails.aspx' it will work.i will get popup window.but i want to add each record id also along with that.
-- modified at 11:00 Wednesday 17th October, 2007
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Kurian_Kurian wrote: why the code is not showing after posting.what format i should use for showing the complete code.Now it is showing some part only.
Check the "Ignore HTML" checkbox.
---
"Anything that is in the world when you're born is normal and ordinary and is just a natural part of the way the world works. Anything that's invented between when you're fifteen and thirty-five is new and exciting and revolutionary and you can probably get a career in it. Anything invented after you're thirty-five is against the natural order of things."
-- Douglas Adams
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Hi, I am using AJAX to dynamically produce a DataList according to the input in a TextBox. I am using the 'OnTextChanged' event to achieve this and a problem that occurs is that I will lose focus in my TextBox as soon I begin to type anything.
An easy solution for this would be to remove the TextBox from the UpdatePanel but as I am using the UpdateProgress to produce a neat loading gif each time the OnTextChanged event occurs I have to keep the TextBox inside the UpdatePanel right?
I have seen a number of examples on the net which suggest using the LastFocus property but have had no luck getting that to work. Am I right in thinking that my problem cannot be solved with the LastFocus property as I also have an UpdateProgess in my code?
I am very new to ASP.NET and would highly appreciate any advice with this - my code is fairly large so I'll enclose a snippet of it, that will hopefully make my problem a bit clearer:
<asp:updatepanel id="upPnlLabels" runat="server">
<contenttemplate>
asp:TextBox ID="txtSearch" OnTextChanged="txtSearch_OnTextChanged" AutoPostBack="true" runat="server">
<asp:updateprogress id="upMyProgress" runat="server" associatedupdatepanelid="upPnlLabels">
<progresstemplate>
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Sorry I can't figure out how to post html on here, still hope to get some feedback on my problem
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i have on html page on clicking on the button of the page iam moving to the another page which is getting on the same page ie first page itself .now on clicking on the close button of the second page.i want the second page values in the first page .
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