ASP.NET

Re: How to make a bound column field into a buttonColumn?

30-May-07 22:45

good day if my first question is hard to understand...

how to make a bound column into a buttom Column / or link column?

thanks

start a new beginning in every ending; thats what life for......

Chetan Ranpariya30-May-07 23:52

Chetan Ranpariya

30-May-07 23:52

Hi,

Do u want to display data from the datasour in the text property of button or link?

if yes then you can create <asp:buttonfield> column as following

<asp:ButtonField ButtonType="link" DataTextField="fieldname" CommandName="commandname"/>

This will display a linkbutton column with the text property from "fieldname" column from the datasource.

I hope this will help u.

Thanks and Regards,
Chetan Ranpariya

Re: How to make a bound column field into a buttonColumn?

moomoooomoo31-May-07 0:08

Re: How to make a bound column field into a buttonColumn?

31-May-07 0:08

Sir thank you it gives me an idea..

but this is not what i wanted although its close to it...

i have 3 columns with databounds, and i want the first column to have a capability of link or same as button field...

start a new beginning in every ending; thats what life for......

Chetan Ranpariya31-May-07 0:51

Chetan Ranpariya

31-May-07 0:51

Hi,

You can order your columns as u want by making "autogenerantecolumns" propertry of gridview to false and creating your column in order whatever u want.

see the following example.
<asp:GridView runat="server" ID="gv" AutoGenerateColumns="false">
<Columns>
<asp:ButtonField ButtonType="link" DataTextField="username"/>
<asp:BoundField DataField="username" />
<asp:BoundField DataField="password" />
</Columns>
</asp:GridView>

Here the first column will have a link button and next two column will just display data.

Thanks and Regards,
Chetan Ranpariya

bound column be used as button selection?

moomoooomoo30-May-07 22:33

30-May-07 22:33

good day to everyone im new to asp.net and using a 2005 version

i need help on how to set a buttonColumn to any column on my grid in asp.net2005...

i used this inserted this code :

<--! ButtonColumn CommandName="select" HeaderText="Employee"
''' DataTextField="EmployeeName" /> -->

i encounter this error:

Parser Error Message: System.Web.UI.WebControls.DataControlFieldCollection must have items of type 'System.Web.UI.WebControls.DataControlField'. 'asp:ButtonColumn' is of type 'System.Web.UI.WebControls.ButtonColumn'.

anyone, pls i need help

start a new beginning in every ending; thats what life for......

Sherin Iranimose30-May-07 23:31

30-May-07 23:31

Hi,

I dont know is this your are expecting.

<asp:GridView ID="GridView1" runat="server">
<Columns>
<asp:ButtonField ButtonType="Button" Text="Button" />
</Columns>
</asp:GridView>

if not, specify what you are trying to do.

To succeed, we must first believe that we can.
Sherin Iranimose

moomoooomoo30-May-07 23:47

30-May-07 23:47

to be simple i had three columns in my gridview and all three columns had bound values / data...

the thing that i wanted to do is how to make the first column that has bound data into a buttonColumn for selection?

start a new beginning in every ending; thats what life for......

Sherin Iranimose30-May-07 23:58

30-May-07 23:58

moomoooomoo wrote:
bound data into a buttonColumn for selection

Can You explain this?

To succeed, we must first believe that we can.
Sherin Iranimose

Sherin Iranimose30-May-07 23:38

30-May-07 23:38

Hi
<asp:GridView ID="GridView1" runat="server">
<Columns>
<asp:CommandField ButtonType="Button" ShowSelectButton="True" />
</Columns>
</asp:GridView>

To succeed, we must first believe that we can.
Sherin Iranimose

moomoooomoo30-May-07 23:56

30-May-07 23:56

this helps but this code adds a new control button..

i want to make use one of my three columns that is already displayed on the gridview... and change it to be an hyperlink to button select....

start a new beginning in every ending; thats what life for......

Sherin Iranimose31-May-07 0:04

connect string in webconfig

31-May-07 0:04

Oh.. I See

What you should do is
convert field in to a template field.
Add watever controls you need in to the template field.

To succeed, we must first believe that we can.
Sherin Iranimose

list gridview data

kvijayajyothy30-May-07 22:30

kvijayajyothy

30-May-07 22:30

How to list field heading / column headings when there is no records in the case of gridview listing of data.

Thank you

vijaya

vijaya

Re: list gridview data

azhara30-May-07 23:08

azhara

30-May-07 23:08

In the function that gets the data, check the count of the rows, and if its = 0 add a blank dummy row:

if (myTable.Rows.Count==0)
{
DataRow myNewRow = myTable.NewRow();
myTable.Rows.Add(myNewRow);
}

Re: list gridview data

kvijayajyothy31-May-07 0:52

kvijayajyothy

31-May-07 0:52

i am not getting it so i used this mehtod but
how to implement it in BLL ?
if (GridView1.Rows.Count == 0)
{
GridView1.DataSource = mylist.GetAdapter("SELECT 'COMPCD', 'COMPNM', 'CORPADD','CORPCITY' FROM Dual ");
GridView1.ShowHeader = false;

}
GridView1.DataBind();

vijaya

Suhail Shahab30-May-07 22:04

Suhail Shahab

30-May-07 22:04

i want to set the connect string in webconfig file at run time.my sanrio is than when my web page load that server name read from note paid and than write in webconfig file'
is it possible?

<add key="dbcon" value="Persist Security Info=False;User ID=sa;password=sa;Initial Catalog=RMS;Data Source=varServerName">

suahil shahab

wEb GuRu...30-May-07 22:07

wEb GuRu...

30-May-07 22:07

well budy can't understand why you want to do this...

All the way fromSialkot ...

Guffa30-May-07 22:45

Guffa

30-May-07 22:45

If you change the web.config file at runtime, the web application will be restarted.

What is it that you want to accomplish?

---
single minded; short sighted; long gone;

Venkatesh Mookkan30-May-07 22:55

Venkatesh Mookkan

30-May-07 22:55

You can write... But when you change the web.config, the application will compiled again by MSIL by the ASP.NET. So all the sessions will be destoryed...

Example:

Dim config As System.Configuration.Configuration<br />
Dim appSetting As New System.Configuration.AppSettingsSection<br />
<br />
config = System.Web.Configuration.WebConfigurationManager.OpenWebConfiguration("~")<br />
appSetting = config.GetSection("appSettings")<br />
<br />
'To add new key<br />
appSetting.Settings.Add("[KEY_NAME]", "[VALUE]")<br />
<br />
'To change exists key<br />
appSetting.Settings("[KEY_NAME]").Value = "[VALUE]"<br />
<br />
<br />
config.Save()

Regards,
Venkatesh Mookkan.
Software Engineer, India
My: Website | Yahoo Group | Blog Spot

Suhail Shahab31-May-07 0:58

Suhail Shahab

31-May-07 0:58

i want same code that u define. when i use this code it give error in

in following line plz guide me.i have imports System.configuraton

Dim config As System.Configuration.Configuration
Dim appSetting As New System.Configuration.AppSettingsSection

config = System.Web.Configuration.WebConfigurationManager.OpenWebConfiguration("~")
appSetting = config.GetSection("appSettings")

suhail shabab

Venkatesh Mookkan31-May-07 2:06

Venkatesh Mookkan

31-May-07 2:06

Can you tell me the Error please??

Regards,
Venkatesh Mookkan.
Software Engineer, India
My: Website | Yahoo Group | Blog Spot

Suhail Shahab31-May-07 23:22

Suhail Shahab

31-May-07 23:22

System.Configuration.AppSettingsSection is not define

Venkatesh Mookkan1-Jun-07 5:35

Venkatesh Mookkan

1-Jun-07 5:35

Please post your code...

The error is not relevent to find the fact.

Regards,
Venkatesh Mookkan.
Software Engineer, India
My: Website | Yahoo Group | Blog Spot