Re: how do achieve auto-login like msn messager - C# Discussion Boards

Re: Install Database into MSQL Server by C# code ?

21-May-07 23:18

What do you mean by install?
Do you want to create a database?

Giorgi Dalakishvili21-May-07 23:24

Giorgi Dalakishvili

21-May-07 23:24

I think he means attaching a database

how do achieve auto-login like msn messager

jason_mf21-May-07 21:51

jason_mf

21-May-07 21:51

was it write a cookies?
if it was write a cookies,
How do write and read?
please give me directions, thanks.

Re: how do achieve auto-login like msn messager

Expert Coming21-May-07 22:14

Expert Coming

21-May-07 22:14

Windows application or ASP.NET?

Windows application could be done several ways, you can write an encrypted file with all the login information, system registry(better not to), or store it in the application settings. I would suggest the first solution.

ASP.NET/ASP, then you would use cookies.

To do the reading/writing of a file, use FileStream, and StreamReader/StreamWriter.

The only way to speed up a Macintosh computer is at 9.8 m/sec/sec.

how to know there is no required attribute for the childnode in xml file

praveenkumar palla21-May-07 21:51

praveenkumar palla

21-May-07 21:51

I am using an xml and in that childnodes have one attribute which is optional, so that attribute may be present or not.

in front-end from c#.net 2005 i am reading that attribute, when it is not present it giving exception.

so how to find that there is no attribute for that childnode in runtime.

Thanks in advance

PraveenKumar Palla

Re: how to know there is no required attribute for the childnode in xml file

Martin#21-May-07 22:14

Re: how to know there is no required attribute for the childnode in xml file

21-May-07 22:14

Hello,

I think Reflection is what you are looking for.
The way from the object to the Attributes would be like this.

//For searching of property Attributes
using System.Reflection;
 
Type t = yourObject.GetType();
foreach (PropertyInfo pi in  t.GetProperties())
{
   if(pi.PropertyType.Attributes & TypeAttributes.Serializable) //For excample a comparison to the Serializable Attribute.
   {

   }
}
 
//For Searching of CustomAttributes of your object.
using System.Reflection;
 
Type t = yourObject.GetType();
object[] AllAttributes = t.GetCustomAttributes(true); //For excample

Hope it helps!

All the best,

Martin

andre_swnpl22-May-07 1:00

andre_swnpl

22-May-07 1:00

just test for null. eg.

XmlDocument oXML = new XmlDocument();
oXML.LoadXml("<root><name id='1' value='ggg' value2='ttt'/><name id='2' value='erer'/></root>");
            
XmlNodeList nl = oXML.SelectNodes("//name");

foreach (XmlNode n in nl)
{
if (n.Attributes["value2"] != null)
{
     //Do Something
}
}

Re: how to know there is no required attribute for the childnode in xml file

praveenkumar palla23-May-07 1:42

praveenkumar palla

23-May-07 1:42

when the below statement is executed then only getting exception(i.e. focusing to catch())

if (n.Attributes["value2"] != null)

Set label's background color to transparent.

blackjack215021-May-07 21:50

21-May-07 21:50

Hi.
How do you do what I've already written in the title? Smile | :)

Can it be done?
Thanks.

Martin#21-May-07 21:53

21-May-07 21:53

yourlabel.BackColor = System.Drawing.Color.Transparent;

blackjack215021-May-07 22:48

21-May-07 22:48

Thanks, but for some reason it doesn't seems to work. I've placed my label on top of a ToolStrip, which has the basic gradient drawn on it. I've set the label's color to transparent, but it still shows the default grey(Control) color.

Martin#21-May-07 22:54

21-May-07 22:54

Problem with Transparency is that it shows the BackGroundColor of the Parent Control.
Which means if you change the BackColor of your Parent Control, you will see this color also at the Labals BackColor.

blackjack2150 wrote:
I've placed my label on top of a ToolStrip, which has the basic gradient drawn on it

I don't know if I understand what you have done and what you whant to see.
Is the ToolStrip the Parent of your Label? (If this is possible!)
Is there a BackgroundImage involved or are you Drawing on your ToolStrip?

All the best,

Martin

blackjack215021-May-07 23:15

21-May-07 23:15

Here's a screenshot.
http://www.imagehosting.com/show.php/657380_label.JPG.html[^]

Note how the label with the text "104" obscures the gradient of the ToolStrip behind it. I want to avoid that.

Thanks for your interest.

Martin#21-May-07 23:32

21-May-07 23:32

Hello,

As I never worked with .Net>1.1 I'm not sure how the ToolStrip workes.
What I guess is, that the Label is in the same Container as the TollStrip, and it's just higher in the z-Order. (Brought to front)
I think this makes it impossible that the Label gettes the same gradient Background as the ToolStrip, It will allways show the Color of the ParentControl.
I think you have to write(paint) directly on the ToolStrip.

All the best,

Martin

blackjack215021-May-07 23:40

21-May-07 23:40

I was afraid of that. Smile | :)

Anyway, it's not such a big deal and it's not worth too much effort. It will just fine in the present form, but it was just a curiosity of mine.
Thanks for your time. I appreciate it.

Martin#21-May-07 23:43

21-May-07 23:43

Glad I could help (In fact, by not really solfing the problem Big Grin | :-D

)
You are wellcome!

Help!!!

MarkB77721-May-07 21:30

MarkB777

21-May-07 21:30

Help Help!

I've created an array of small picturebox's on a form, and want them to highlight when I click on them, but I don't know how to let the event handler method know which picturebox (which member of the array) ive clicked on...

See code below:

private PictureBox[,] lifeForms;

public coverForm(int dimX, int dimY)
{
InitializeComponent();
lifeForms = new PictureBox[dimX, dimY];

for (int y = 0; y < dimY; y++)
{
for (int x = 0; x < dimX; x++)
{
this.lifeForms[x, y] = new System.Windows.Forms.PictureBox();
this.paper[x, y] = lifeForms[x, y].CreateGraphics();
this.Controls.Add(lifeForms[x, y]);
lifeForms[x, y].BorderStyle = System.Windows.Forms.BorderStyle.Fixed3D;
lifeForms[x, y].Location = new System.Drawing.Point((x*20)+4, y*20+4);
lifeForms[x, y].SizeMode = System.Windows.Forms.PictureBoxSizeMode.Zoom;
lifeForms[x, y].Size = new System.Drawing.Size(20, 20);
lifeForms[x, y].Show();
lifeForms[x,y].MouseClick += new MouseEventHandler(this.selectDim_Click);
}
}
}

private void selectDim_Click(object sender, EventArgs e)
{
How can I read which picture box the user has clicked on down here?!!
}

Mark.

Martin#21-May-07 21:48

21-May-07 21:48

Hello,

The sender object is the instance of the pictureBox you whant.
You just have to cast it.

PictureBox actBox = sender as PictureBox
if(actBox!=null)
{
  //Do what you whant
}

Hope it helps,

Martin

MarkB77722-May-07 0:19

MarkB777

22-May-07 0:19

Thanks heaps guys I've got it working now... Legendary!!!

Mark.

Giorgi Dalakishvili21-May-07 22:01

Giorgi Dalakishvili

21-May-07 22:01

You can assign tag to each picturebox and then find out which one was clicked by examining sender

Martin#21-May-07 22:06