About multi-column listbox - C / C++ / MFC Discussion Boards

Re: [Internet] Connect directly between 2 computer

arr.cpp3-Apr-07 5:36

arr.cpp

3-Apr-07 5:36

I had the same problem:

wiew my question and answer: tcp connection[^]

A linker error!

Malini Nair31-Mar-07 20:50

Malini Nair

31-Mar-07 20:50

Hi everybody!
i have done a file transfer program and the sender part works well.
but i get a linker error in receiver part!

My error is:
Linking...
nafxcwd.lib(thrdcore.obj) : error LNK2001: unresolved external symbol __endthreadex
nafxcwd.lib(thrdcore.obj) : error LNK2001: unresolved external symbol __beginthreadex
Debug/aaa.exe : fatal error LNK1120: 2 unresolved externals
Error executing link.exe.

The thing is I have not used these functions in my program!
Any suggestions please!
Thanks in advance!

regards,
Shalini

Re: A linker error!

hoanglinh946631-Mar-07 21:02

hoanglinh9466

31-Mar-07 21:02

You must add the .lib file to your project: Project/Settings/link, write your name of .lib file to Object/library modules:

Re: A linker error!

CPallini1-Apr-07 1:03

CPallini

1-Apr-07 1:03

the library you're using requires your application to link with multithreaded C run-time libraries. Use the /MT compiler option
(for instance, on Visual Studio 6, choose menu Project->Settings, then on the C/C++ tab, add /MT in the Project Options list).

hope that helps.

Smile | :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

Re: A linker error!

C Mahesh1-Apr-07 20:38

C Mahesh

1-Apr-07 20:38

Add MFC support to your program

Re: A linker error!

Sachin R Sangoi2-Apr-07 1:20

Sachin R Sangoi

2-Apr-07 1:20

Add MT in ur project settings as rightly suggested which means support for Multithreading in ur project. Happy coding Smile | :)

Get the facts or facts will get you and when you get them, get them right or they will get you wrong.

Happy Coding Smile | :)

SDI as Main View with Zero to Many MDI-like Child Views

C. Peterson31-Mar-07 18:52

C. Peterson

31-Mar-07 18:52

Hello All-

I'm working on a SQL database application. The database contains a main table of information, and then each table has another set of data associated with it from another table. What I'd like to do is keep a maximized view of the main table of data open at all times (just like with SDI), and then be able to open up in MDI-like child views of each subset of data associated with an item in the main view.

Another way to describe what I want would be to say I want MDI with the root main frame window also containing a view in it.

Please give me any suggestions you can.

Thank You!

Caleb Peterson

About multi-column listbox

Chen-XuNuo31-Mar-07 16:20

Chen-XuNuo

31-Mar-07 16:20

I am doing a multi-column listbox,I set its styles:OwnerDraw-Fixed,Multi-column and "No integal height".Then I add virtual function MeasureItem and add code :
void CColorListBox::MeasureItem(LPMEASUREITEMSTRUCT lpMeasureItemStruct)
{
// TODO: Add your code to determine the size of specified item
CRect rect;
GetWindowRect(&rect);

ScreenToClient(&rect);

lpMeasureItemStruct->itemHeight=rect.Height()/2;
lpMeasureItemStruct->itemWidth=rect.Width()/4;
}

I add a member function to initialize the data and call this function in PreSubclassWindow:
void CColorListBox::InitData()
{
SetItemData(0,RGB(255,0,0));
SetItemData(1,RGB(0,255,0));
SetItemData(2,RGB(0,0,255));
SetItemData(3,RGB(125,0,0));
SetItemData(4,RGB(0,125,0));
SetItemData(5,RGB(0,0,125));
SetItemData(6,RGB(125,125,0));
SetItemData(7,RGB(125,125,125));
}

The last I do DrawItem:
void CColorListBox::DrawItem(LPDRAWITEMSTRUCT lpDrawItemStruct)
{
// TODO: Add your code to draw the specified item
CDC* pDC=CDC::FromHandle(lpDrawItemStruct->hDC);
UINT action=lpDrawItemStruct->itemAction;
UINT state=lpDrawItemStruct->itemState;
CRect rcItem=lpDrawItemStruct->rcItem;

//pDC->SetBkMode(TRANSPARENT);
if( !(state&ODS_SELECTED) )
pDC->FillSolidRect(&rcItem,(COLORREF)lpDrawItemStruct->itemData);
}

Is there something wrong in my operation?I set a breakpoint in MeasureItem and debug the program,but it don't run through the breakpoint?

I appreciate your comments~

Re: About multi-column listbox

Chen-XuNuo1-Apr-07 1:22

Chen-XuNuo

1-Apr-07 1:22

The problem has been solved~

Thanks~

Re: About multi-column listbox

Hamid_RT1-Apr-07 18:22

Hamid_RT

1-Apr-07 18:22

You can share your answer;)

WhiteSky

CScroll behavior

johny_d31-Mar-07 10:02

johny_d

31-Mar-07 10:02

Hi, I've created a new horz scroll in a CDialog with this:

wnd_hscroll.Create(WS_CHILD | WS_VISIBLE,rct_hscroll ,this,9999);

and set its range with:

wnd_hscroll.SetScrollRange(1,1000,TRUE);

However, the control is not willing to respond to SetScrollPos or sliding the gripper when the app is running.

Any suggestions? Thx.

Live long and prosper

johny74656@gmail.com

Re: Warning while building a DLL

prasad_som31-Mar-07 18:36

prasad_som

31-Mar-07 18:36

Maintaining .def file is obsolete with currect C++ compilers. Instead you can use __declspec(dllexport).

Prasad
Notifier using ATL | Operator new[],delete[][^]

Re: Warning while building a DLL

chelsea_blues1-Apr-07 5:54

chelsea_blues

1-Apr-07 5:54

Thank you ....

Editbox in FormView

CosminU31-Mar-07 7:16

CosminU

31-Mar-07 7:16

Hi All,

I have some CEdit's in an CFormView and I can do copy&paste by using the contextual menu but I just cannot do that by using the keyboard combinations Ctrl+C, Ctrl+V and so on. Of course there is no such problem for a CEdit in a CDialog.

I suppose there are some keywords' related messages eaten by CFormView. Any tips on how to solve that? Thanks.

Regards,
Cosmin Unguru

Re: Editbox in FormView

bob1697231-Mar-07 18:14

bob16972

31-Mar-07 18:14

does your app have accelerators defined for those keyboard combinations?

Re: Editbox in FormView

CosminU1-Apr-07 23:35

CosminU

1-Apr-07 23:35

Yes it does, for copy, cut and paste. I tried to remove them but with no different results.

Regards,
Cosmin Unguru

asking how to program list only hidden files under linux in c

Arif Liminto31-Mar-07 7:15

Arif Liminto

31-Mar-07 7:15

hi iam doing a project to list <like dir=""> but only header files any good refrence for me?

Linux?

CPallini31-Mar-07 8:20

CPallini

31-Mar-07 8:20

arifliminto86 wrote:
hi iam doing a project to list but only header files any good refrence for me?

Sorry?

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

Re: asking how to program list only hidden files under linux in c

ThatsAlok1-Apr-07 21:18

ThatsAlok

1-Apr-07 21:18

arifliminto86 wrote:
hi iam doing a project to list but only header files any good refrence for me?

sorry dude.. this windows programing forum.. here linux is rare breed.. you have to search google for linux grp!

"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow

cheers,
Alok Gupta
Global Interface Table: An Easy Way to Marshal an Interface Pointer[new]
VC Forum Q&A :- I/ IV
Support CRY- Child Relief and You

HTF? :mad:

_808631-Mar-07 6:53

_8086

31-Mar-07 6:53

How the f*** OMG | :OMG:

this is sickening.

void fun(int);
void main()
{
 int a ;
 a=3;
 fun(a);
}

void fun(int n)
{
	if(n==0)//orif(n==-1)
		exit(0);<--If I put this the ouput is nothing, but if I remove it, the idiot compiler is bypassing the condition (0>0),(-1>0).
	if(n>0)//3,2,1,0,-1
	{
		printf("\nTHERE!");
		fun(--n);
		printf("\n%d",n); //HOW THE **** the control comes here?!!!?? :((
		fun(--n);////HOW THE **** the control comes here?!!!?? :((

	}
	else
	{
		printf("\nHERE!");
	}

}

How 0,-1 can be > than 0? sh*t. I'm not on drugs! but WTF | :WTF:

mark,led,jeron,toxcct,david someone help! help!
without exit(0),it prints

----------------------------
286? WOWW! Blush | :O

Re: HTF? :mad:

PJ Arends31-Mar-07 7:20

PJ Arends

31-Mar-07 7:20

First off, what is the output you are expecting? With the recursive calls you are making the output you are getting makes perfect sense.

You may be right
I may be crazy
-- Billy Joel --

Within you lies the power for good, use it!!!

Re: HTF? :mad: [modified]

_808631-Mar-07 7:58

_8086

31-Mar-07 7:58

Thanks Arends,
but why does it bypass this condtion when n =0, or -1

<br />
if(n>0) //(0>0) (-1>0) [after successive calls to --n & fun(n)]<br />
{<br />
  but still it comes here! why?  <br />
}<br />

I still can't get that point. Recursion makes multiple copies of the function? may be I'm missing this? it gets into the stack everytime we call it, so the context of "n" changes? I can somehow come around the point but still need some help to understand it. Please help dude.

-- modified at 14:06 Saturday 31st March, 2007

----------------------------
286? WOWW! Blush | :O

Re: HTF? :mad:

PJ Arends31-Mar-07 12:07

PJ Arends

31-Mar-07 12:07

_8086 wrote:
but why does it bypass this condtion when n =0, or -1

It does not, the recursive function calls stop when n is zero or less.

I think your confusion is coming from what n is. You have to remember that a new n is created every time fun() is called, you are not using a single n.

I cleaned up your sample a bit, so lets step through it:

void fun(int n)                              // start with n = 3
{
   if (n > 0)                                // n is greater than zero
   {
      fun(--n);                              // n is now two, recursive call to fun(2)

        +void fun(int n)                     // start with n = 2
        |{
        |   if (n > 0)                       // n is greater than zero
        |   {
        |      fun(--n)                      // n is now one, another recursive call to fun(1)
        |
        |         +void fun(int n)           // start with n = 1
        |         |{
        |         |   if (n > 0)             // n is greater than zero
        |         |   {
        |         |      fun(--n)            // n is now zero, another recursive call to fun(0)
        |         |
        |         |         +void fun(int n) // start with n = 0;
        |         |         |{
        |         |         |   if (n > 0)   // n is not greater than zero
        |         |         |   {
        |         |         |      fun(--n)  // not called
        |         |         |      printf("%d\n", n);
        |         |         |   }
        |         |         +}               // exit fun()
        |         |
        |         |      printf("%d\n", n);  // n is zero - output "0"
        |         |   }
        |         +}                         // exit fun()
        |
        |      printf("%d\n", n);            // n is one - output "1"
        |   }
        +}                                   // exit fun()

      printf("%d\n", n);                     // n is two - output "2"
   }
}                                            // exit fun()

and repeat ad infinitum.

You may be right
I may be crazy
-- Billy Joel --

Within you lies the power for good, use it!!!

Re: HTF? :mad:

_808631-Mar-07 16:49

_8086

31-Mar-07 16:49

Excellent.

yourNewArtile* pjaRecursionArticle = (aritcle*) yourMessage; Big Grin | :-D

----------------------------
286? WOWW! Blush | :O

Re: HTF? :mad:

CPallini31-Mar-07 12:08

CPallini

31-Mar-07 12:08

Of course the compiler is working fine. Please follow me in code inspection, to make analysis shorter, let's start with fun(2):

fun(2){
  if(2>0){
    fun(1);

At the moment (no output yet produced) we have to stop considering fun(2) and, due to recursion, procede with the inspection of fun(1):

fun(1){
  if(1>0){
    fun(0);

Again (no output yet), we have to suspend considering fun(1) and go deeper in recursion with fun(0):

fun(0){
  if(0>0){

Here, the compiler, that is a honest guy, correctly evaluates (0>0) as false and the function returns. Have we done? No, of course, there are (in the order) fun(1) and fun(2) waiting on the stack. So let's go back to fun(1) and reprise whereever we suspended:

  printf("\n%d",0);
  fun(-1);
}

As you can see, this is the first time we have a number on the console, and the number is 0 (you can also see that fun(-1) is called, but it will do nothing). Of course we could go on with code inspection, but I think it's enough: we have the zero, and we also have the demonstration that the compiler is not insane.

hope that:
(1) the analysis is correct.
(2) it helps.

Smile | :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

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