ASP.NET

Re: adding checkbox to Gridview edititemtemplate column

19-Feb-07 21:07

I wanted to edit a grid view column using a checkbox control,so i have used a template column and placed a checkbox control in the edit item template,and set the bind property for item control.but in the following event i am unable to identify the checked status of the control.

<br />
protected void ReportView_RowUpdating(object sender, GridViewUpdateEventArgs e)<br />
    {<br />
        <br />
<br />
       <br />
<br />
  <br />
        GridViewRow row = ReportView.Rows[e.RowIndex];<br />
        row.RowState = DataControlRowState.Edit;<br />
        CheckBox chk1 = ((CheckBox)row.FindControl("CheckBox1"));<br />
        Response.Write(chk1.Text + chk1.Checked.ToString());<br />
        if (row != null)<br />
        {<br />
            bool isChecked = ((CheckBox)row.FindControl("CheckBox1")).Checked;<br />
           <br />
<br />
            if (isChecked)<br />
            {<br />
<br />
                Response.Write("The Text Entered is" +((CheckBox)row.FindControl("CheckBox1")).Text);<br />
<br />
            }<br />
            ReportView.EditIndex = -1;<br />
<br />
           BindData(); <br />
<br />
<br />
        }<br />
<br />
    }<br />

here the checked status is not identified ie even if the check box is checked,the status is always false,but it is identifying the checkbox control
.the text value is correct ,but the checked status is always false,
please help with a solution

-- modified at 4:08 Tuesday 20th February, 2007

PandemoniumPasha19-Feb-07 22:32

Re: adding checkbox to Gridview edititemtemplate column

19-Feb-07 22:32

use the following code where u do the checking:

if((CheckBox)(dg.Items(i).Cells(0).FindControl("ChkBox").Checked)
{
//you code goes here
}

where i would be the iterating variable indicating the row index of the datagrid (ie. dg) and the CheckBox control is assumed to be in the first column ie. Cessl(0) and the CkeckBox control name is assumed to be "ChkBox"

hope that helps.

Sebastian T Xavier20-Feb-07 20:23

Re: adding checkbox to Gridview edititemtemplate column

20-Feb-07 20:23

hi thanks for ur reply
but again even if the control is identified ,the checked status is always given as false
should i give anything else to bind the checkedchange event

thanks

PandemoniumPasha20-Feb-07 21:33

Re: adding checkbox to Gridview edititemtemplate column

20-Feb-07 21:33

this is because every time the page load event is triggered, the datagrid gets a new data.
to avoid this you should check the ispostback property.
see a very simple example below:

private void Page_Load(object sender, System.EventArgs e)
{
if (!Page.IsPostBack)
BindDG();
}
public void BindDG()
{
System.Data.SqlClient.SqlConnection conn = new System.Data.SqlClient.SqlConnection("user id=sa;password=sa;initial catalog=test;data source=192.168.111.30");
System.Data.SqlClient.SqlCommand cmd = conn.CreateCommand();
cmd.CommandText="select *from users";
DataSet ds = new DataSet();
System.Data.SqlClient.SqlDataAdapter da = new System.Data.SqlClient.SqlDataAdapter(cmd);
da.Fill(ds);
dg.DataSource=ds;
dg.DataBind();
}
private void BtnDel_Click(object sender, System.EventArgs e)
{
string objName;
System.Data.SqlClient.SqlConnection conn = new System.Data.SqlClient.SqlConnection("user id=sa;password=sa;initial catalog=test;data source=192.168.111.30");
System.Data.SqlClient.SqlCommand cmd = conn.CreateCommand();
conn.Open();
for (int i=0; i

Sebastian T Xavier20-Feb-07 23:18

Re: adding checkbox to Gridview edititemtemplate column

20-Feb-07 23:18

thank you, let me check this method...

sebastian

Sebastian T Xavier21-Feb-07 17:58

21-Feb-07 17:58

Thank you very much,it worked successfully.

Data grid!

nclauder19-Feb-07 20:27

19-Feb-07 20:27

Hi,
Is it possible to insert data into datagrid with out getting the data from a database like sql or access.
Thanks.

PandemoniumPasha19-Feb-07 20:42

19-Feb-07 20:42

you can create a simple array and bind that to the datagrid as well.

nclauder19-Feb-07 21:18

19-Feb-07 21:18

Thank you,
I'm not so sure to have understood How you tried to explain to me.
Thanks

nclauder19-Feb-07 21:40

19-Feb-07 21:40

I've decided to use sql but I'm having problem with seeing my datagrid? Yet I set Property visible to true what could be the Problem
Thanks.

PandemoniumPasha19-Feb-07 21:48

19-Feb-07 21:48

you might not have called the databind() function of the datagrid.

nclauder19-Feb-07 22:06

19-Feb-07 22:06

For sure I did call the databind() That's why I find it strange do you think I'missing something else?

luckyve19-Feb-07 22:30

luckyve

19-Feb-07 22:30

did you set the "data source" and "data member" for it ?
then u should use data bind .

PandemoniumPasha19-Feb-07 21:47

19-Feb-07 21:47

for the datagrid to display data, it need to have some data in. this data can be of any type, dataset,table, array of userdefined class, etc.
so, if u need to display data in the datagrid which is not from any database, create a class of your choice, declare its array, add values to the array, add that object ot the datasource of the datagrid then bind the data by calling databind().
hope this makes it more clear

NanaAM19-Feb-07 22:19

NanaAM

19-Feb-07 22:19

Grid can be bound to any Collection type.
You can create a dummy datattable as following:-
DataTable dt = new DataTable("Try");
dt.Columns.Add("column1");
dt.Rows.Add("one");
dt.Rows.Add("two");
dt.Rows.Add("three");

and now set the datasource to dt.

Also you need to have atleast 1 row in datasource to get the grid displayed

Nana

nclauder19-Feb-07 22:33