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AnswerRe: The multi-part identifier "..." could not be bound. Pin
Rob Graham12-Feb-07 8:59
Rob Graham12-Feb-07 8:59 
GeneralRe: The multi-part identifier "..." could not be bound. Pin
Quecumber25612-Feb-07 9:02
Quecumber25612-Feb-07 9:02 
Generalgridview filtering using dropdownlist and textbox Pin
bernie_01128-Feb-07 22:20
bernie_01128-Feb-07 22:20 
QuestionSql Server query needed Pin
Saira Tanwir12-Feb-07 4:43
Saira Tanwir12-Feb-07 4:43 
AnswerRe: Sql Server query needed Pin
Parwej Ahamad12-Feb-07 6:07
professionalParwej Ahamad12-Feb-07 6:07 
Question[Message Deleted] Pin
DeepaliVaibhav12-Feb-07 0:58
DeepaliVaibhav12-Feb-07 0:58 
AnswerRe: Multiple-step operation generated errors. Check each status value. Pin
Blue_Boy12-Feb-07 1:04
Blue_Boy12-Feb-07 1:04 
AnswerRe: Multiple-step operation generated errors. Check each status value. Pin
Pete O'Hanlon12-Feb-07 3:06
mvePete O'Hanlon12-Feb-07 3:06 
You haven't given enough information for people to help. What is the database that you are using? Are you inserting using Stored Procedures or direct SQL? Which database access method are you using, e.g. Sql... for Sql Server or OleDb... for OLE DB? What code are you actually using?

BTW - rather than use a 0 for new record, try explicitly setting values using column names. In other words, try doing this instead:

INSERT INTO Table1(Field2, Field3) VALUES (@Value1, @Value2)


If Field1 (not included in the insert statement) is an autoincrement column, then it will be automatically incremented.





the last thing I want to see is some pasty-faced geek with skin so pale that it's almost translucent trying to bump parts with a partner - John Simmons / outlaw programmer

Deja View - the feeling that you've seen this post before.

QuestionLast Accessed Date Pin
Logup12-Feb-07 0:45
Logup12-Feb-07 0:45 
AnswerRe: Last Accessed Date Pin
andyharman12-Feb-07 3:16
professionalandyharman12-Feb-07 3:16 
QuestionDisplaying a record per day Pin
Logup11-Feb-07 22:57
Logup11-Feb-07 22:57 
AnswerRe: Displaying a record per day Pin
andyharman12-Feb-07 1:09
professionalandyharman12-Feb-07 1:09 
Questionselect distinct On multiple fields Pin
hamidreza_buddy11-Feb-07 22:26
hamidreza_buddy11-Feb-07 22:26 
AnswerRe: select distinct On multiple fields Pin
Sushant Duggal11-Feb-07 22:39
Sushant Duggal11-Feb-07 22:39 
AnswerRe: select distinct On multiple fields Pin
M A A Mehedi Hasan11-Feb-07 23:13
M A A Mehedi Hasan11-Feb-07 23:13 
GeneralRe: select distinct On multiple fields Pin
Sushant Duggal12-Feb-07 0:06
Sushant Duggal12-Feb-07 0:06 
AnswerRe: select distinct On multiple fields Pin
Blue_Boy11-Feb-07 23:57
Blue_Boy11-Feb-07 23:57 
QuestionSQL Server does not exists or access denied Pin
Sushant Duggal11-Feb-07 22:26
Sushant Duggal11-Feb-07 22:26 
AnswerRe: SQL Server does not exists or access denied Pin
Sylvester george11-Feb-07 22:42
Sylvester george11-Feb-07 22:42 
GeneralRe: SQL Server does not exists or access denied Pin
Sushant Duggal11-Feb-07 22:56
Sushant Duggal11-Feb-07 22:56 
GeneralRe: SQL Server does not exists or access denied Pin
Sylvester george11-Feb-07 23:01
Sylvester george11-Feb-07 23:01 
GeneralRe: SQL Server does not exists or access denied Pin
Sushant Duggal11-Feb-07 23:05
Sushant Duggal11-Feb-07 23:05 
GeneralRe: SQL Server does not exists or access denied Pin
Sylvester george11-Feb-07 23:09
Sylvester george11-Feb-07 23:09 
GeneralRe: SQL Server does not exists or access denied Pin
Sushant Duggal11-Feb-07 23:50
Sushant Duggal11-Feb-07 23:50 
AnswerRe: SQL Server does not exists or access denied Pin
Aaron S.12-Feb-07 11:20
Aaron S.12-Feb-07 11:20 

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