Re: How to get the windows login un and pw in c# - C# Discussion Boards

Colin Angus Mackay31-Jan-07 2:08

Colin Angus Mackay

31-Jan-07 2:08

You cannot get the windows password.

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VijayaRam31-Jan-07 2:12

VijayaRam

31-Jan-07 2:12

Or tell me how to get windows username

Thanks and regards,

VijayaRam

xstoneheartx31-Jan-07 2:23

xstoneheartx

31-Jan-07 2:23

you can use System.Environment.UserName

Get image from RichTextBox.

MrEyes31-Jan-07 2:56

MrEyes

31-Jan-07 2:56

It isnt possible to get the user password, however you can validate it using the follow api call

const int LOGON32_LOGON_INTERACTIVE = 2;
const int LOGON32_PROVIDER_DEFAULT = 0;

[DllImport("advapi32.dll", SetLastError=true)]
private static extern bool LogonUser(String lpszUsername, String lpszDomain, String lpszPassword, int dwLogonType, int dwLogonProvider, ref IntPtr phToken);

private void DoLogonCheck(string userName, string domainName, string password)
{
 IntPtr phToken = IntPtr.Zero;
 bool logonRes = LogonUser(
  userName,
  domainName,
  password, 
  LOGON32_LOGON_INTERACTIVE,
  LOGON32_PROVIDER_DEFAULT,
  ref phToken);

 if (logonRes)
 {
  Console.WriteLine("Good logon with username : {0}", userName)
 }
 else
 {
  Console.WriteLine("Bad logon with username : {0}", userName)
 }
}

I use a similar piece of code to validate that the user true user is sat in front of the machine and not that they have left it unlocked.

god4k31-Jan-07 1:33

god4k

31-Jan-07 1:33

Hi everyone.

One month ago I try to search how to get image from RichTextBox,
But there is no answer.

Please help me how to get image from RichTextBox

Thank You.

Sorry for bad English

Re: Get image from RichTextBox.

xstoneheartx31-Jan-07 2:31

xstoneheartx

31-Jan-07 2:31

here is an article in msdn that is your answer.
in this article, the painting is done on printer surface; you can paint on surface of a bitmap.
Getting WYSIWYG Print Results from a .NET RichTextBox[^]

Multiple select in listbox

Andrew Em31-Jan-07 1:32

31-Jan-07 1:32

Hi
I'm building a little "search" function for my listbox! This is what i want to happend: I got a textbox, then i write the number (the listbox contains a list of numbers) i want to find. The number i write in the textbox should then get selected in the listbox when i click a button. That far, it works great with this code:

lstlistBox1.SelectedItem = txttextBox1.Text;

Now to the problem. If the number i write in the textbox exists more than one time in the list, i want all the items with that name to get selected. Been trying with loops and stuff to make it happend but just wont work. Anyone got a suggestion?

Thx in advance

Light is faster than sound... Thats why some people look smart till they start to talk.

Stefan Troschuetz31-Jan-07 1:59

Stefan Troschuetz

31-Jan-07 1:59

Iterate over the listbox items and use the SetSelect method to select or deselect the items according to the number in the textbox.

"Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning." - Rick Cook

www.troschuetz.de

Andrew Em31-Jan-07 2:06

31-Jan-07 2:06

think you could explain how i do that or add a code sample? Would appreciate it.

Thanks

Light is faster than sound... Thats why some people look smart till they start to talk.

VijayaRam31-Jan-07 2:09

VijayaRam

31-Jan-07 2:09

Hai do the following:

//Add a button and add the following code to that
{
listBox1.SelectionMode = SelectionMode.MultiExtended;
string strSearch = textBox1.Text;
for (int i = 0,j=0; i < listBox1.Items.Count; i++)
{
if (listBox1.Items[i].ToString() == strSearch)
listBox1.SetSelected(i, true);
else
listBox1.SetSelected(i, false);
}
}
Add a textbox and a listbox and try to execute.

regards,

VijayaRam

Andrew Em31-Jan-07 2:21

31-Jan-07 2:21

Good one, worked on first try Big Grin | :-D

Thanks!

Next part of the application is to make another listbox select the same indexes as the first one does, heres also the problem that it only selects one. (note: the same indexes, not the same numbers Smile | :)

)

Any suggestions?

Light is faster than sound... Thats why some people look smart till they start to talk.

Stefan Troschuetz31-Jan-07 2:42

Stefan Troschuetz

31-Jan-07 2:42

Did you even try to understand why and how the code snippet you were given solved your original problem? I doubt that cause otherwise, you would know how to easily solve this one.

Martin#31-Jan-07 2:56

Martin#

31-Jan-07 2:56

Yes, a "make my homework, so I don't have to think!" message board is missing!

Andrew Em31-Jan-07 3:12

31-Jan-07 3:12

Martin# wrote:
Yes, a "make my homework, so I don't have to think!" message board is missing!

Not asking anyone to "make my homework", i simply couldn't get it working... Tried understanding it, tried to get it work and i couldn't, thats why i asked.

Light is faster than sound... Thats why some people look smart till they start to talk.

Martin#31-Jan-07 3:23

Martin#

31-Jan-07 3:23

Don't take it too personal Wink | ;)

Tenkyu wrote:

Light is faster than sound... Thats why some people look smart till they start to talk.

Like that one!

Stefan Troschuetz31-Jan-07 3:43

Stefan Troschuetz

31-Jan-07 3:43

Tenkyu wrote:
Tried understanding it, tried to get it work and i couldn't, thats why i asked.

So what exactly don't you understand? The code snippet you were given is quite simple. It iterates over all list items by index, compares each item to the value of the textbox and then makes a call to the SetSelected method passing the the item index and a boolean indicating whether the item should be selected or not.

Andrew Em31-Jan-07 3:52

31-Jan-07 3:52

For the first i might add that i'm new to programming, it is one of my first projects i'm playin around with, so didn't know what "iterate" the list meant, and i didn't know how to use "SetSelected" method etc, i'm mostly trying my way there but error messages aint very funny.

Anyways thanks for the help, got it all working now i think.

Light is faster than sound... Thats why some people look smart till they start to talk.