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Savior999 wrote: but if i use ImageList_DrawEx for the first "row" it works fine, but with the remaining y should use another function
What do you mean by "row"?
LR_DEFAULTSIZE is for icons and cursors, right?
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Hi, thanks for the reply 
I use the imagelist with a bitmap containing three (say it) columns (that is the indexes of imagelist), then i've col 1, col 2 & col 3.
The bitmap contains the states of 3 "buttons", but all the "states" are all in the same col. Then i need to paint only a piece of the col.
Explanation:
My bmp is 90h * 54w px and the imagelist cut it in 3 cols of 90h * 18w px.
I need to paint only 18 * 18 px at a time.
I tried to use ImageList_DrawIndirect specifing the index and the x,y point where the Draw would begins to read, but it don't works.
PD: Yes, you are right... i typed unnecessarily, my mistake  But it's not in my code
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An image list has only one row. You're not going to be able to draw starting anywhere in the
image list except 0,0 for the given image index.
You'll need to layout your bitmap so its one long row (270x18) and index accordingly.
Mark
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Hello
I have been using CMap class of MFC (containg CString objects) declaring it as CMap<cstring,lpcstr,cstring,lpcstr> m_mapInfo. I stored values in it of type CStrings as the key and value. I used to loop thru the m_mapInfo using POSITION pos = m_mapInfo.GetStartPosition() to get the pointer to first member and looping using
while(pos != NULL)
m_mapInfo.GetNextAssoc(pos,string1,strin2)
It worked fine, until I had to make my code UNICODE complaint. To make it UNICODE complaint, I had to change the template definition to CMap<lpcstr,lpcstr,lpcstr,lpcstr> m_mapInfo. I stored the keys and values by converting CStrings to WideCharToMultiByte(). The values are being set in the map but now when I do a POSITION pos = m_mapInfo.GetStartPosition() it returns pos = 0xffff, though the size of the map is coming correctly as the number of elements set.
Can someone help me out ?
Thanx
Vipin
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Have you tried using the LPCTSTR type instead of the LPCSTR type? The 'T' types are already UNICODE and MBCS aware.
You may be right
I may be crazy
-- Billy Joel --
Within you lies the power for good, use it!!!
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vipin_nvk wrote: I stored the keys and values by converting CStrings to WideCharToMultiByte().
Why? CString objects can be used in Unicode and non-Unicode builds.
"Approved Workmen Are Not Ashamed" - 2 Timothy 2:15
"Judge not by the eye but by the heart." - Native American Proverb
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Hi all:
The following is my program.
<br />
#define WIN32_LEAN_AND_MEAN<br />
#include <math.h><br />
#include <windows.h><br />
#include <stdio.h><br />
#include <stdlib.h><br />
#include "lapack\matrix_clapack.h"<br />
<br />
<br />
#define NDIM 2 <br />
#define M_PI 3.14<br />
<br />
int main (){<br />
<br />
integer i, j, info2;<br />
integer N, NRHS, LDA, LDB;<br />
doublecomplex *A;<br />
doublecomplex *B;<br />
static integer IPIV[NDIM], INFO;<br />
<br />
A = (doublecomplex*) malloc(NDIM*NDIM*sizeof(doublecomplex));<br />
B = (doublecomplex*) malloc(NDIM*sizeof(doublecomplex));<br />
<br />
N=NDIM; NRHS=1; LDA=NDIM; LDB=NDIM;<br />
<br />
for (i=0;i<N;i++){<br />
for (j=0;j<N;j++) {<br />
A[i+N*j].r = cos(M_PI*(i+1)*3.0/4.0); <br />
A[i+N*j].i = sin(M_PI*(j+1)/5.0); <br />
printf(" %f + %fi \n",A[i+N*j].r, A[i+N*j].i);<br />
}<br />
}<br />
<br />
B[0].r = 1.0; <br />
B[0].i = 1.0; <br />
B[1].r = 2.0;<br />
B[1].i = 3.0;<br />
<br />
<br />
info2 = zgesv_(&N, &NRHS, A, &LDA, IPIV, B, &LDB, &INFO);<br />
<br />
printf("info %d \n",INFO);<br />
<br />
for (i=0;i<N;i++)<br />
printf(" %f + %fi \n",B[i].r, B[i].i);<br />
}<br />
And here is the compiler message:
<br />
1>------ Build started: Project: test, Configuration: Debug Win32 ------<br />
1>Compiling...<br />
1>test.cpp<br />
1>Linking...<br />
1>test.obj : error LNK2019: unresolved external symbol _zgesv_ referenced in function _main<br />
1>D:\Project\test\Debug\test.exe : fatal error LNK1120: 1 unresolved externals<br />
1>Build log was saved at "file://d:\Project\test\test\Debug\BuildLog.htm"<br />
1>test - 2 error(s), 0 warning(s)<br />
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========<br />
<br />
I just want to try to test the LAPACK library. But what's the problem with this program please?
Thanks
Asura
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The implementation of the zgesv_ function that is inside the LAPACK library could not be found during the linking process.
You have to add the LAPACK library, the .lib file, to the list of libraries you're building with.
Bring up the options for the project and add the path for the LAPACK lib-file to the "input libraries".
"It's supposed to be hard, otherwise anybody could do it!" - selfquote
"No one remembers a coward!" - Jan Elfström 1998
"...but everyone remembers an idiot!" - my lawyer 2005 when heard of Jan's saying above
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Roger Stoltz wrote: Bring up the options for the project and add the path for the LAPACK lib-file to the "input libraries".
An easier way is to use a #pragma comment(lib "LAPACK.lib") (assuming LAPACK.lib is the lib file name) directive to link import libraries.
You may be right
I may be crazy
-- Billy Joel --
Within you lies the power for good, use it!!!
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Ha, that one I didn't know about! ![Rose | [Rose]](https://www.codeproject.com/script/Forums/Images/rose.gif)
Thanks for the info, PJ. Nice to know. My 5 for that!
This day was not in vain after all, now that I've learnt something new...
"It's supposed to be hard, otherwise anybody could do it!" - selfquote
"No one remembers a coward!" - Jan Elfström 1998
"...but everyone remembers an idiot!" - my lawyer 2005 when heard of Jan's saying above
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Thanks folks
for your valuable advice of Tcp over Udp.
As far as my requirements are concerned, it demands UDP.
Bcoz the scenario is such that we have to broadcast packets at the same
to n number of Machines across the network.That's the reason i need help
on Sending files over UDP protocol.
I have worked previously on TCP,but not on UDP.
As far as previous post is concerned,somebody said that it is similar
as creating Socket and Sending it using IP and Port.
I hope in UDP you are sending on a Broadcast IP and port,so how to do it.
Thankx in Advance.
Girish
Software Developer
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Girish601 wrote: I hope in UDP you are sending on a Broadcast IP and port,so how to do it.
Create the socket with a call to CSocket::Create and set the nSocketType parameter to SOCK_DGRAM for UDP.
If the socket was successfully created you can use CSocket::SendTo for sending datagrams to whatever address and port you desire since both shall be provided as formal parameters.
If you're not using MFC you can use the raw socket API, but I think you get the picture.
Hope this helps
--
Roger
"It's supposed to be hard, otherwise anybody could do it!" - selfquote
"No one remembers a coward!" - Jan Elfström 1998
"...but everyone remembers an idiot!" - my lawyer 2005 when heard of Jan's saying above
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It is very similar, except that datagrams (UDP messages) have a maximum size, and there is no guaranteed delivery or sequencing/ordering of data.
With TCP, if you send 128KB of data with a single call, internally it will be broken up (if necessary) into smaller packets (either on your system or possibly further down the network) that will be reassembled on the receiving system.
With UDP, IIRC, if you try to send 32KB with a single call, only a certain amount of it will be sent (something like 1500 bytes, I think). You will need to break up the data yourself into packets and send them one at a time. Additionally, if you send 5 packets in a row (1,2,3,4,5), they may arrive on the other side out-of-sequence (1,2,4,5,3), or some may not make it at all (1,3,4,2 but no 5th datagram).
Sending multiple-packets of data via UDP often requires that you implement your own packetizing logic so that you handle lost or out-of-sequence packets.
Broadcast, point-to-point, point-to-multipoint or multicast has nothing to do with your using TCP or UDP, IIRC. You can data using either style to a broadcast address (i.e. xxx.xxx.xxx.255), or to a multicast address (multicast router, for example).
Peace!
-=- James Please rate this message - let me know if I helped or not!<HR>If you think it costs a lot to do it right, just wait until you find out how much it costs to do it wrong!
Avoid driving a vehicle taller than you and remember that Professional Driver on Closed Course does not mean your Dumb Ass on a Public Road!
See DeleteFXPFiles
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James R. Twine wrote: Broadcast, point-to-point, point-to-multipoint or multicast has nothing to do with your using TCP or UDP, IIRC. You can data using either style to a broadcast address (i.e. xxx.xxx.xxx.255), or to a multicast address (multicast router, for example).
I'm currently doing some research on broadcast and multicast, as we plan to use it in one of our projects. All documents I found so far claim that broadcasing and multicasting require the use of UDP. This does make sense to me, as TCP requires an established connection and for broadcasing and multicasting you don't even know to how many recepicients you are talking.
Regards,
Tim
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Tim Paaschen wrote: All documents I found so far claim that broadcasing and multicasting require the use of UDP. This does make sense to me, as TCP requires an established connection and for broadcasing and multicasting you don't even know to how many recepicients you are talking.
Interesting... I think that makes sense for things like using PING to try to ping a broadcast address, but not for multicast that is supported by the network hardware. Since one or more routers could handle connetions to multiple clients, and since the connections are one-way, connection or connection-less would not matter - clients would subscribe to the 'cast by subscribing to the multicast server. But then again, I have not been close to multicast for some time now, so my memory of it may be faulty.
Peace!
-=- James Please rate this message - let me know if I helped or not!<HR>If you think it costs a lot to do it right, just wait until you find out how much it costs to do it wrong!
Avoid driving a vehicle taller than you and remember that Professional Driver on Closed Course does not mean your Dumb Ass on a Public Road!
See DeleteFXPFiles
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Girish601 wrote: I have worked previously on TCP,but not on UDP.
As far as previous post is concerned,somebody said that it is similar
as creating Socket and Sending it using IP and Port.
No big difference. It still requires port & IP.
Girish601 wrote: I hope in UDP you are sending on a Broadcast IP and port,so how to do it.
It's not "in UDP we broadcast". Broadcast is done if we want to. For sending files I dont think UDP would be the best option. But in LAN environment, it's success rate is 99%. The main difference is, it's connectionless protocol that means it doesn't maintain any connection between the server & client. Just "push" the data and "get" the data. No connection path is set up in between. let me give you a link ..please wait.
Code-Frog:So if this is Pumpkinhead. Time for him to run and hide. It's an interesting thought really.
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Hi, I have a question:
Let's say I write a program in C++ and then set a certain file extension to "open with" the program I wrote. When I double-click on the file, and it opens up my program, what happens to the file data? Basically I just need to get the data from that file so I can use it in my program, the same way in which the contents of a text file will appear in notepad if you double-click on a txt file (and have notepad set as your default text editor, of course).
Thanks~
kr
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The program that is launched gets the path to the file that was double clicked on as argument.
If you're using MFC that means you get the file path in CWinApp::m_lpCmdLine.
--
Roger
"It's supposed to be hard, otherwise anybody could do it!" - selfquote
"No one remembers a coward!" - Jan Elfström 1998
"...but everyone remembers an idiot!" - my lawyer 2005 when heard of Jan's saying above
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I'm not using MFC in this program, so what variable is that argument stored as? I'm assuming it's the same as getting a command line argument in UNIX for instance but I don't know where that string is or how to retrieve it when using a Windows GUI.
Thanks!
KR
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If you're writing a windowed application the you have the path inside WinMain:
int APIENTRY WinMain(HINSTANCE hInstance,
HINSTANCE hPrevInstance,
LPSTR lpCmdLine,
int nCmdShow)
lpCmdLine will contain the path of your file.
On the other hand, if you have a console application, then the path of the file will be in item 1 of argv[] argument of main.
int main(int argc, char* argv[])
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
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Oh duh, I didn't even notice the lpCmdLine there in the WinMain. Thanks, I'm all set!
KR
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KellyR wrote: I'm not using MFC in this program, so how do I process that argument?
Well, what are you using then?
You say that using "Windows GUI", but what do you mean by that?
If you're using another framework then the documentation for that framework must have some information about how to get hold of the program arguments. So if you're using any kind of framework you're basically the best suited for answering your question.
If you've implemented the main function you can get the program arguments as desccribed here[^].
"It's supposed to be hard, otherwise anybody could do it!" - selfquote
"No one remembers a coward!" - Jan Elfström 1998
"...but everyone remembers an idiot!" - my lawyer 2005 when heard of Jan's saying above
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Roger Stoltz wrote: If you're using another framework
In fact you don't need a framework to build up a Windows GUI application.
(for instance using Visual Studio 6, you can choose Win32 application to start a full featured GUI application without using MFC, it's the hard way, but it's there...).
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
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CPallini wrote: In fact you don't need a framework to build up a Windows GUI application.
Of course you don't.
You can always start with WinMain.
I even provided information about how to do it the old way if he was creating a console application: the link.
"It's supposed to be hard, otherwise anybody could do it!" - selfquote
"No one remembers a coward!" - Jan Elfström 1998
"...but everyone remembers an idiot!" - my lawyer 2005 when heard of Jan's saying above
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Roger Stoltz wrote: I even provided information about how to do it the old way if he was creating a console application: the link.
He actually needed info about WinMain, not main.
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
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