Visual Basic

14-Dec-06 22:28

hi ..
can anyone give me msgrNL32.dll or msgr3NL.dll..its the one used to check spelling in word for dutch language..

thanx in advance..

ChandraRam14-Dec-06 23:08

14-Dec-06 23:08

BINO VARGHESE wrote:
hi ..
can anyone give me msgrNL32.dll or msgr3NL.dll..its the one used to check spelling in word for dutch language..

thanx in advance..

Clickety[^]

BINOVAR14-Dec-06 23:23

14-Dec-06 23:23

thank you very much Smile | :)

BINOVAR15-Dec-06 0:01

15-Dec-06 0:01

the DLL in that website is corrupted my dear friend...so can u plz send me someother link..

awaiting reply..

ChandraRam15-Dec-06 0:13

15-Dec-06 0:13

BINO VARGHESE wrote:
the DLL in that website is corrupted my dear friend...so can u plz send me someother link..

awaiting reply..

Well, I just googled for the file name and found some sites...

BINOVAR15-Dec-06 0:15

15-Dec-06 0:15

can u send me if u get any free sites for the DDL...me too searched but itz all paid sites Cry | :((

The ANZAC15-Dec-06 1:28

The ANZAC

15-Dec-06 1:28

Tried microsoft at all, considering they developed it and you can probably download it from them. Try this ne:

http://support.microsoft.com/kb/910284/[^]

Posted by The ANZAC

BINOVAR15-Dec-06 1:31

Sorting an array of objects!

15-Dec-06 1:31

thanx dude vl try using it....

portreathbeach14-Dec-06 21:20

portreathbeach

14-Dec-06 21:20

I have an array of objects. Each object refers to an mp3 file as follows:

mp3file.Title
mp3file.Artst
mp3file.Album
mp3file.TrackNumber

My question is, how can I sort the array by a specific item of the object, eg. Sorted by Artist, sorted by Album etc.

Thnaks

Guffa14-Dec-06 22:09

Guffa

14-Dec-06 22:09

Make a custom comparer for your class, and use that in a call to Array.Sort.

---
It's amazing to see how much work some people will go through just to avoid a little bit of work.

portreathbeach15-Dec-06 7:56

portreathbeach

15-Dec-06 7:56

Thanks for the quick reply.

You say, 'Make a custom comparer for the class'. I'm fairly new to VB.net and don't quite understand what you mean. Please could you explain a little more.

Thanks again

dhbaer15-Dec-06 8:11

dhbaer

15-Dec-06 8:11

Something like this. Say you want to sort by Artist name.
Make a function:

Function CompareArtist(ByVal Artist1 As String, ByVal Artist2 As String) As Boolean
IF (Artist1>Artist2) Then
Return True
Else
Return False
End IF
End Function

Then when you do your sort, have something like this:

If CompareArtist(mp3file(1).Artist,mp3file(2).Artist) Then
//Do you sorting here depending on the result of the compareartist function.
End If

You could make a seperate comparison function for each member of the object, or just 1 or 2 depending on the type's of the object's members (if they are all strings for example). I hope that makes some sense.

David

portreathbeach15-Dec-06 13:41

portreathbeach

15-Dec-06 13:41

Thanks very much, this is the sort of thing I was after.

I guess you cant use array.sort on an array of objects. I though there was probably some syntax you could add into array.sort to specify which 'column' you wanted to sort by.

Anyway, the code you have given me David looks fine. Thanks

need help with decimal rounding

Guffa15-Dec-06 16:23

Guffa

15-Dec-06 16:23

Create a class that implements the interface IComparer. The class needs to have a method named Compare that does the comparison of the properties you want to sort.

I usually don't program VB, but something like this:

Class MyObjectComparer Inherits IComparer

   Public Function Compare(A as Object, B as Object)
      Return String.Compare(DirectCast(A, MyClass).SomeProperty, DirectCast(B, MyClass).SomeProperty)
   End Function

End Class

This you can use to sort your array of MyClass objects:

Dim comparer as new MyObjectComparer()<br />
Array.Sort(TheArray, comparer)

---
It's amazing to see how much work some people will go through just to avoid a little bit of work.

vbbeg14-Dec-06 20:58

14-Dec-06 20:58

hi..

i need help with rounding decimals to nearest 10th.

e.g
$1.20,$1.21 & $1.22 rounded 1.20
$1.23,$1.24 rounded to $1.25
$1.26 , $1.27 rounded to $1.25
$1.28 , $1.29 rounded to $1.30

hope this above example is an idea of what i need.
thanks

Robbo

ChandraRam14-Dec-06 21:06

14-Dec-06 21:06

Multiply by 10, round it (integer rounding), and then divide by 10?

vbbeg14-Dec-06 21:39

14-Dec-06 21:39

hi chandra

can you give me a quick sample source.

Robbo

ChandraRam14-Dec-06 21:42

14-Dec-06 21:42

x = round(x * 10) / 10

vbbeg14-Dec-06 21:49

14-Dec-06 21:49

Chand

an a sample like this. the end result always rounds down

e.g. dim num as decimal = 1.23
dim roundednum as integer

roundednum = math.round(num *10)/10

'result = 1.2 instead of 1.25

Robbo

ChandraRam14-Dec-06 21:51

14-Dec-06 21:51

But that is what you wanted, right? Round to nearest 10th?

Btw, my name is Chandra

vbbeg14-Dec-06 21:57

14-Dec-06 21:57

i think my first message was right except i said 10th which gave a confusion.

basically i need decimal rounded down or up to nearest decimal
e.g 1.20 ,1.21,1.22 should be $1.20
1.23,1.24,1.25 should be $1.25
1.26,1.27 should be $1.25 (round down here)
1.27,1.28,1.29 should be $1.30

btw. i know your name is Chandra was just giving you a short nick thats all.
sorry if that offended you.

Robbo

ChandraRam14-Dec-06 21:55

14-Dec-06 21:55

My bad - I did not study the examples, just went by your statement D'Oh! | :doh:

What you want is round to nearest 5 cents...

Ok, try this then:
x = round(x * 20) / 20

vbbeg14-Dec-06 22:00

14-Dec-06 22:00

Thank you Chandra.. as soon as i posted my last msg .. YOU HAD MY FIX READY..
your a champ. thankyou so much champ..

just what i needed. Smile | :)

Robby

ChandraRam14-Dec-06 22:28