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Thank you Brahmma, Now i want change the same color to caption bar and border also....
Is it possible?
-- modified at 6:22 Tuesday 28th November, 2006
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they are all classes inheriting from CWnd.
so your own class for each, inheriting from the class you want to modify, overload the right function, and that's it...
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The SetProcessDefaultLayout function changes the default layout when windows are created with no parent or owner only for the currently running process. -by MSDN-
In my case, i already used SetProcessDefaultLayout to change the default layout of my windows, the problems is that child windows ( for example a dialog wich shows the Police ) don't respect the layout of it's parent.
Is there an idea ?
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I want to invert bitmap thro 180 degree and want to display it into dialog box.
please suggest me something.
Thank you.
There Is Nothing Right & Wrong
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abhijit bhopale wrote: I want to invert bitmap thro 180 degree
Invert or rotate?
abhijit bhopale wrote: There Is Nothing Right & Wrong
Actually, there is.
Nobody can give you wiser advice than yourself. - Cicero
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Thank u..
Rotate.
There Is Nothing Right & Wrong
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I'm coding in C++, but just using basic C++ libraries (ie. not MFC or WTL etc.).
I would like to know if there is a more elegant/better way to do what I have coded below, just to learn something.
Basically, given a "code" I want to verify that each "digit" is Octal (ie. 0-7), and that the "code" is exactly 4 characters.
I'm using this as an opportunity for a "code review" by you peers to see if I can learn something.
bool Xpdr::IsValidCode(const wchar_t* code)
{
// Has 4 numeric digits
if (wcslen(code) != 4)
{
return false; // Code MUST be 4 digits
}
for (int i=0; i<4; i++)
{
// Check each digit is octal
if (code[i] < 0x30 || code[i] > 0x37)
{
return false; // Code digits must be 0 - 7
}
}
return true;
}
Thanks for your thoughts on how to make this better / more efficient.
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I think a possible alternative solution is:
bool Xpdr::IsValidCode(const wchar_t * code) const
{
for( int i = 0; i < 4; ++i, ++code)
{
if( *code < '0' || *code > '7')
{
return false;
}
}
return *code == 0;
}
I hope this works. In addition you can "unroll" this short loop and replace it with a series of "if"-s and autoincremented code pointer.
-- modified at 5:47 Tuesday 28th November, 2006
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Ah, very interesting. Nice touch verifying that there is a terminating NULL.
By unroll are you meaning something like this:
bool Xpdr::IsValidCode(const wchar_t * code) const
{
if( *code < '0' || *code > '7') { return false; }
code++;
if( *code < '0' || *code > '7') { return false; }
code++;
if( *code < '0' || *code > '7') { return false; }
code++;
if( *code < '0' || *code > '7') { return false; }
return *code == 0;
}
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Stick^ wrote: [...]By unroll are you meaning something like this[...]
Yes (actually you need one more ++: return *++code == 0). Or even like this:
inline bool Xpdr::IsValidCode(const wchar_t * code) const
{
return
code[0] >= '0' && code[0] <= '7' &&
code[1] >= '0' && code[1] <= '7' &&
code[2] >= '0' && code[2] <= '7' &&
code[3] >= '0' && code[3] <= '7' &&
code[4] == 0;
}
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Stick^ wrote: for (int i=0; i<4; i++)
{
// Check each digit is octal
if (code[i] < 0x30 || code[i] > 0x37)
{
return false; // Code digits must be 0 - 7
}
}
Have you considered wcstol(code, ..., 8)?
"Approved Workmen Are Not Ashamed" - 2 Timothy 2:15
"Judge not by the eye but by the heart." - Native American Proverb
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No, but I am thinking that function won't help me, because what I am trying to do is verify that input (a WCHAR*) typed by a user is in the range 0000 - 7777, with only octal (ie 0-7) digits. They could enter anything on their keyboard, so I need to validate it, not just convert it.
Thanks guys.
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Stick^ wrote: No, but I am thinking that function won't help me, because what I am trying to do is verify that input (a WCHAR*) typed by a user is in the range 0000 - 7777...
Which is exactly what it does. If you sent it "7778", it would return an error status.
"Approved Workmen Are Not Ashamed" - 2 Timothy 2:15
"Judge not by the eye but by the heart." - Native American Proverb
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Hi,
I do not know how to use the UpdateResource() function to create an ICON
resource within an .exe file. I have managed to create raw data resources
with this function, but not ICONs. Does anyone know how to make this work
given a file path to an .ico file. I need to change the icon in an .exe
file when it is displayed in explorer.
Many thanks
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Atom wrote: I do not know how to use the UpdateResource() function to create an ICON
resource within an .exe file.
Was there any problem? Have you tried creating an RT_GROUP_ICON instead.
For more information read the article Icons in Win32 in MSDN.
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Hi all,
I am writting a program which would like to detect if the PC is waken-up when it is in "stand-by" mode. Is there any method to do so? any reference source/material is welcome, thanks~
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StarMeteor wrote: any reference source/material is welcome, thanks~
Look up WM_POWER, WM_POWERBROADCAST, WM_POWERCHANGE_NEEDACK in MSDN.
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Is it possible to set hook for Joystick?
Please help!
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Hello people
Can anybody explain why my CSocket Receive call fails when i use it with threading
With Rgds
Girish
Software Developer
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Hi,
check error code
-----------
Mila
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Oh interesting, someone else with CSocket and Thread probs....
Had lately also probs with CSocket and CAsyncSocket....sending works fine but no Messages were send/received so I was unable to receive .....
I went back to C based socket communication and there it works
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If you had working code why would you use SOCKET wrapper classes?
CSocket, IMO, is only useful in a simple app.
CAsyncSocket is better (lower level) but unless you're using window messages for socket
notifications (why would you do that in a multithread app?) then you don't get much but a thin
wrapper.
Both work fine as designed and documented but they're not for everyone 
Cheers!
Mark
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Girish601 wrote: Can anybody explain why my CSocket Receive call fails when i use it with threading
Can you explain HOW the receive call fails?
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can someone gibe me source code or algorithem for solving electronic circuits in
computer
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echeshari wrote: can someone gibe me source code or algorithem
Click here[^]
Nobody can give you wiser advice than yourself. - Cicero
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