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Yes i have downloaded that project but its not related my query but i get the idea to read the fiel in chunk
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Hi All,
I have a XML string with me in the format
<row xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<SEQNO>6</SEQNO>
<B_CO_CD>H</B_CO_CD>
<B_AREA_CD>K</B_AREA_CD>
</row>
the XML tags are taken in an actual string variable and then I need to find a particular tag and get its value to actually set that value in a dataset column that corresponds to this tag.
How can I do this ??
Pls guide me.. I need to give demo on this..Pls Pls
Omkar
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 Hi Omkar,
find below the code to get value in a particular tag.
System.Data.DataSet ds=new DataSet();
ds.ReadXml("D:\\MY_WORK\\ssis projects\\Executessis\\WindowsApplication1\\XMLFile1.xml");//here set your xml file path
int i=ds.Tables[0].Columns["SEQNO"].Ordinal;//getting the position of the column/tag
string s=ds.Tables[0].Rows[0].ItemArray.GetValue(i).ToString();//getting the actual vlaue inside the tag
Tell me if it will not work...
Regards,
Saurabh Maheshwari
Nucleus Software ,Noida
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Hi,
I have a directory containing loads of xml files that change regularly. To generate a list of all the files in the directory i use this code:
Sub Page_Load(sender as Object, e as EventArgs)<br />
If Not Page.IsPostBack then<br />
Dim dirInfo as New DirectoryInfo(Server.MapPath(""))<br />
repeater.DataSource = dirInfo.GetFiles("*.xml")<br />
repeater.DataBind()<br />
End If<br />
End Sub
I then display this information in a asp repeater. Currently it lists the filename and size and when the document was last edited.
I wish to extend this concept to allow me to display the 'title' element of each xml file alongside the filename in my asp repeater. I know how to extract the 'title' from a static list of xml files by explicity binding to each one, but i dont know how to do this 'on the fly' with the xml files in my generated list. I hope that made relative sense to somebody.
Thanks alot.
Colm.
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"<xsl:with-param name="Curnode" select="//RealTimeData/*[position()=count(//RealTimeData/MasterData)]" />"
Kindly explain the select clause ...particularly what does the * imply here
Please elaborate on the result of each step....
-- modified at 5:44 Thursday 14th September, 2006
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* means zero or more occurences
Christian Graus - Microsoft MVP - C++
Metal Musings - Rex and my new metal blog
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I have, for example, a variable $title accepting value (a string with value "title") from a text box .
Then I want to use this string to make reference to an element when I try to use a template that accepts a parameter as a node set.
<xsl:call-template name="show-items">
<xsl:with-param name="text" select="$title"/>
</xsl:call-template>
My xml is like this
<book>
<lang>english</lang>
<title>XML Basics</title>
<content>
......
</content>
</book>
but it does not work. The title accepted in the template "show-items" is not "XML Basics" but "title".
Please help!!!!
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What you want to do is pass parameter "text" in "show-items" template with value "XML Basics" in it???
Try
<xsl:with-param name="text" select="/book/title/text()"/>
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I want to use like
<xsl:with-param name="title" select="/book/$title">
but it doesn't work. It is said that a node set is needed, while the value of $title is 'title' (a string) not the title element, the "//book/title" one, the child node element of the book.
All I have now is a string with the value is the name of that element, and I want to use this name, translate it into a real element and then use that element.
Can I do that?
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how can i pass xml nodes from a web service to a client.. as i m doin it in the normal way the way we pass string but its giving a parser error and soap exception
rabia
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I help a small structure below
<jokes>
<joke>
<cat>poem</cat>
<title>ABC</title>
<content>
...
</content>
</joke>
<joke>
<title>123</title>
<content>
...
</content>
</joke>
</jokes>
As you can see, the values for <cat> is "poem" and "normal", for example. But I would like to make it like, when the <cat>poem</cat> appears, it means, the joke is in poem. But if the <joke> does not have <cat> or it has a empty pair <cat></cat>, the type of that joke is considered to be "normal".
How can I check to see if a tag is empty or not present?
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You can test for the presence of a tag with XPath by just writing the tag name: //joke/cat This selects all <joke> tags that have a child <cat> tag. This selects all <cat> tags that are children of a <joke> tag. To test the actual contents of the <cat> you'll need other XPath functions (I just know basic XPath so I don't know the functions by heart, check out the docs)
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Michael Dunn wrote: You can test for the presence of a tag with XPath by just writing the tag name: //joke/cat This selects all <joke> tags that have a child <cat> tag.
No, that would select the "cat" elements not the "joke" elements.
"Alot of the people on this forum are incredibly stupid, thinking that the internet is real"
Score: 1.0 in the Soap Box
led mike
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 I was thinking the right thing, but explained it backwards.
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The response above is correct. You can also use the boolean XPath function to determine if a tag is there or not:
/jokes/joke[boolean(cat)] would select all the joke nodes that contain a cat child element
/jokes/joke[not(boolean(cat))] would select all the joke nodes that don't have a cat child element
Logifusion[ ^]
If not entertaining, write your Congressman.
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u can also compare value for that by using a query using XPathNavigator
-- modified at 5:13 Wednesday 13th September, 2006
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Hi I need to merge several versions of xml documents which contain different data. I can't just append one document to another, instead it need to substitute elements which are the same (meaning having same tag in a hierarchy). One file will have higher precedence than the other and would substitute the data of the other one if same tag. I think an example would explain better than words.
<?xml version="1.0"?>
<!-- Old version, low precedence -->
<movies>
<movie name="Snakes on a Plane">
<director>David Ellis</director>
<year>2006</year>
<rating>M</rating>
</movie>
<movie name="The Descent">
<rating>R</rating>
<year>2005</year>
<director>Neil Marshall</director>
</movie>
</movies>
<?xml version="1.0"?>
<!-- Newer version, higher precedence -->
<movies>
<movie name="Snakes on a Plane">
<director>David R. Ellis</director>
<country>USA</country>
<rating>R</rating>
</movie>
<movie name="Finding Nemo">
<rating>G</rating>
<year>2003</year>
<director>Andrew Stanton</director>
</movie>
</movies>
<?xml version="1.0"?>
<!-- Merged version -->
<movies>
<movie name="Snakes on a Plane">
<director>David R. Ellis</director>
<year>2006</year>
<rating>R</rating>
<country>USA</country>
</movie>
<movie name="The Descent">
<rating>R</rating>
<year>2005</year>
<director>Neil Marshall</director>
</movie>
<movie name="Finding Nemo">
<rating>G</rating>
<year>2003</year>
<director>Andrew Stanton</director>
</movie>
</movies>
Notice in the merged version that for example director for Snakes on a Plane been updated and country added to same movie. Is there any way to do this using standard tools, like C#/.NET or SQLServer 2005 or some other library/product? Or do I need to implement this myself? Thanks for any pointers, Patric
/Patric
My C# blog: C# Coach
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Patric_J wrote: I need to merge several versions of xml documents which contain different data.
Patric_J wrote: using standard tools, like C#/.NET
One way to manupulate XML in this fashion would be to use the System.XML.XmlDocument and the XML DOM that it represents. There is information everywhere about using XML DOM. It comes in real handy so you may as well bite the bullet and get familiar with it.
"Alot of the people on this forum are incredibly stupid, thinking that the internet is real"
Score: 1.0 in the Soap Box
led mike
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can anybody help? I don't know how to do that!
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Hi,
I have the following code:
public class Item
{
private string name;
private int id;
[XmlElementAttribute]
public string Name
{
get{return name;}
set{name=value;}
}
[XmlElementAttribute]
public int ID
{
get{return id;}
set{id=value;}
}
}
I need to serialize an ArrayList of these Item(s).
public class Dummy
{
[XmlElementAttribute(typeof(Item))]
private ArrayList list;
public Dummy()
{
list=new ArrayList();
list.Add(new Item("one",1));
list.Add(new Item("two",2));
}
//this is called by a class that instantiates Dummy
public void save()
{
XmlSerializer ser=new XmlSerializer(typeof(Item));
StreamWriter writer=new StreamWriter("file.xml");
ser.Serialize(writer,list);
writer.Close();
}
}
but this won't work. Can anyone offer any suggestions?
thanx
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Either make the list field public or make a read/write property for it. Xml serialization will not work on private fields. The reason for this is that the XmlSerializer builds some dynamic types to perform serialization instead of doing it by reflection. This puts the serialization outside of your namespace and it only has access to what is public. Which is also why you need a public default constructor. You also need to use the XmlArrayAttribute:
[XmlArray]
[XmlArrayItem(typeof(Item))]
public ArrayList list;
Logifusion[ ^]
If not entertaining, write your Congressman.
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Hi everyone,
I want to using xmldom but i dont have microsoft.xmldom in my computer can you give me a site that i can download it.
Thanks
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Thanks mike but which?theres many title?
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