C / C++ / MFC

Re: Command Prompt commands from vc++ gui

3-Aug-06 4:20

Are you wanting to pass data to your console application from your GUI application? If so, see here and here.

"Money talks. When my money starts to talk, I get a bill to shut it up." - Frank

"Judge not by the eye but by the heart." - Native American Proverb

vineet14083-Aug-06 8:24

vineet1408

3-Aug-06 8:24

Dear david,

thanks for the reply , i am going through the tuorial u have mentioned. . I must thank you once again for prompt reply. I will look fwd for more guidance from you.

regards --vineet

Thanks to everybody who even thought of helping me. regards--vineet

Function with default arguments

Andy Rama3-Aug-06 3:03

Andy Rama

3-Aug-06 3:03

Hi,
If I can declare a function as
void Show(int i = 1729,double d);
But I can't call this function by passing only 2nd argument then what is the use of that function? OR How to use this function (to pass only 2nd argument)?

ex.
void Show(int i, double d = 3.14);
void Show(int i = 1729,double d);
void Show(int i, double d)
{
printf("\n\t %d %0.2lf",i,d);
}
main()
{
Show(); // Output 1729 3.14
Show(12); // Output 12 3.14
Show(45,5.6); // Output 45 5.60
Show(23.9); // Output 23 3.14 ....... But can I get output as 1729 23.9 ?
}

Thanks & Best Regards,
Aniket Salunkhe

Re: Function with default arguments [modified]

toxcct3-Aug-06 3:06

toxcct

3-Aug-06 3:06

default arguments only starts at the end of the parameters list...

TOXCCT >>> GEII power

[VisualCalc 3.0 updated ][Flags Beginner's Guide new! ]

Andy Rama3-Aug-06 3:07

Andy Rama

3-Aug-06 3:07

toxcct wrote:
default arguments only starts at the end of the parameters list...

I know that...but see the program given by me ... it doesn't show error

-- modified at 9:08 Thursday 3rd August, 2006

Nyarlatotep3-Aug-06 3:07

3-Aug-06 3:07

Only the last arguments in the arguments list can assume a default value.

"void Show(int i = 1729,double d);" is not correct

If you need to pass int or double you can use polymorphism ...

void Show( int i= 1729 );
void Show( double d=3.14);
void Show(int i, double d);

Zac Howland3-Aug-06 3:45

Zac Howland

3-Aug-06 3:45

Nyarlatotep wrote:
If you need to pass int or double you can use polymorphism ...

void Show( int i= 1729 );
void Show( double d=3.14);
void Show(int i, double d);

This is function overloading ... not polymorphism.

If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week

Zac

Nyarlatotep3-Aug-06 3:48

3-Aug-06 3:48

also called "function polymorphism" Smile | :)

Zac Howland3-Aug-06 3:53

Zac Howland

3-Aug-06 3:53

Polymorphism is generally used with reference to classes or objects, and it deals with method OVERRIDING, not overloading.

If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week

Zac

Gary R. Wheeler3-Aug-06 3:12

Gary R. Wheeler

3-Aug-06 3:12

Arguments with default values must come at the end of the argument list. C++ does not provide a syntax for specifying missing arguments.

Another thing you might be seeing, since you are using numeric arguments, is that the compiler will automatically convert numeric constants to the correct type.

The best way to do this would be:

void Show(double d,int i = 1729)
{
  printf("\n\t%d %lf",i,d);
}
main()
{
  Show(); // compile error; no value specified for 'd'
  Show(12); // output 1729 12.0
  Show(5.6,45); // output 45 5.6
  Show(23.9); // output 1729 23.9
}

Software Zen: delete this;

Fold With Us![^]

Zac Howland3-Aug-06 3:43

Zac Howland

3-Aug-06 3:43

You cannot pass just the second parameter. If you change the declaration so that the default parameters are the last arguments to your function, you can pass the first arguments and skip the default ones (if desired), but you cannot do it the way you are trying to.

Also, you cannot create the same function with the same arguments and different default parameters.

Aniket Salunkhe wrote:
void Show(int i, double d = 3.14);
void Show(int i = 1729,double d);
void Show(int i, double d)

Declaring all 3 of those will give you a compiler error.

void Show(double d, int i = 1729);

Show(3.14);
Show(3.14, 2000);

If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week

Zac

David Crow3-Aug-06 4:34

3-Aug-06 4:34

Neither C nor C++ support "named parameters." See here for more.

"Money talks. When my money starts to talk, I get a bill to shut it up." - Frank

"Judge not by the eye but by the heart." - Native American Proverb

Gary R. Wheeler3-Aug-06 5:30

Gary R. Wheeler

3-Aug-06 5:30

DavidCrow wrote:
named parameters

One of the the (all too few) cool things about the Ada programming language. Named parameters made for more readable and self-documenting code.

Software Zen: delete this;

Fold With Us![^]

Hamid_RT4-Aug-06 6:50

Hamid_RT

4-Aug-06 6:50

See Default arguments in C++ functions[^]

WhiteSky

Time zones [modified]

Nyarlatotep3-Aug-06 3:00

3-Aug-06 3:00

I've a weird problem making me crazy !!!

I've to read a sequence of dates from a text file and convert these dates into time_t.
I DON't want to take into account timezones and daylight savings, so the input date must be converted into the exact output date.
So, i've avoided mktime() to convert from tm (filled up with string dates from source) to time_t.
The next solution i've used was to convert a SYSTEMTIME to a time_t with these functions (based on similar functions, UnixTimeToSystemTime(), described in MSDN):

void FileTimeToUnixTime(LPFILETIME pft, time_t *t)
{
LONGLONG ll;

ll = pft->dwHighDateTime;
ll <<= 32;
ll |= pft->dwLowDateTime;

ll = ll - 116444736000000000;
*t = ll / 10000000;
}

void SystemTimeToUnixTime(LPSYSTEMTIME pst, time_t *t)
{
FILETIME ft;

SystemTimeToFileTime(pst, &ft);
FileTimeToUnixTime(&ft, t);
}

because I was sure that SystemTimeToFileTime() only converts to SYSTEMTIME format to FILETIME format without any other considerations like timezone or daylight saving.
In my PC these work well. When I've run the code in another PC, the resulting date is 1 hour back.
(it's very strange too, because that PC has the same date settings of mine).

I can't achive the result to obatin a time_t that reflect the same source date, without variations caused by currently timezone and daylight saving settings.

-- modified at 9:12 Thursday 3rd August, 2006

David Crow4-Aug-06 3:11

4-Aug-06 3:11

Nyarlatotep wrote:
I've to read a sequence of dates from a text file...

What do these dates look like?

"Money talks. When my money starts to talk, I get a bill to shut it up." - Frank

"Judge not by the eye but by the heart." - Native American Proverb

Nyarlatotep4-Aug-06 3:19

4-Aug-06 3:19

Input file is a CSV file. Dates are in dd/mm/yyyy format and I've to convert those dates into time_t without time zone o daylight saving affection ...

David Crow4-Aug-06 4:07

Re: Time zones [modified]

4-Aug-06 4:07

If you are reading the dates in as dd/mm/yyyy, then you can separate the three components like:

char dateToday[] = "04/08/2006";
char *pDay = strtok(dateToday, "/"),
     *pMonth = strtok(NULL, "/"),
     *pYear = strtok(NULL, "/");

Now you can convert those to numeric values using atoi().

"Money talks. When my money starts to talk, I get a bill to shut it up." - Frank

"Judge not by the eye but by the heart." - Native American Proverb

Nyarlatotep4-Aug-06 4:19

4-Aug-06 4:19

My problem is not to parse the input string date.
I parse the input date and input time and put each value into a tm struct (day, month, year, hour, minutes, seconds) and I'have used mktime() function to convert from the tm struct to time_t value.

BUT

mktime() takes into account time zone and daylight saving so, for example, if input date into the tm struct is 01/06/2006 15:00:00 (first June), the time_t date obtained from mktime() is 01/06/2006 17:00:00 (I am in GMT +1 and day light saving is in effect adding an extra hour).

Instead I want to convert the parsed date into time_t without take into account time zones and day light saving, obtaining the the same date as the input, in every time zone the program runs.

To avoid this 'problem' I've tried to use a function (see inital post) that use SystemTimeToFileTime internally, because I thought that SystemTimeToFileTime only converts from SYSTEMTIME struct to FILETIME struct without taking into account time zones and day light saving. But I was wrong, I suppose.

-- modified at 10:23 Friday 4th August, 2006

David Crow4-Aug-06 4:30