|
One way:
//application[@name="OutlookView"]/*[name()='version' or name()='url']
|
|
|
|
|
i have a transformer to convert xml to html.
i have created following xsl.
but when i get the output html the starting table tag (<table>) is missing. the end table tag however appears in the html. What coul be the problem?
<code><?xml version='1.0'?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html"/>
<xsl:template match="data_table">
<table> <xsl:apply-templates/>
</table>
</xsl:template>
<xsl:template match="body">
<tr >
<TH valign='top' colspan='3'>
<xsl:apply-templates select="heading"/>
</TH>
<TH valign='top' colspan='3' align='right'>
<xsl:if test = "./link/linkurl and ./link/linktext != ''">
<xsl:element name="A">
<xsl:attribute name="href">
<xsl:value-of select="./link/linkurl"/>
</xsl:attribute>
<xsl:value-of select="./link/linktext"/>
</xsl:element>
</xsl:if>
</TH>
</tr>
</xsl:template> </code>
-- modified at 6:55 Monday 30th January, 2006
|
|
|
|
|
HI
Need Java Code For Validating The XML agaianest XSD which includes other xsd's
|
|
|
|
|
hi guys:
i am using XmlDocument to save a xml file, but it always output something like this xmlns=""
how do i get rid of this?
thanks
|
|
|
|
|
I have a rss feed app that I would like to add the Newspaper View Style like the RSS Bandit. Can anyone help me to add this feature to my app.
Thanks
Thanks cPod....
|
|
|
|
|
Take a look at my article:
http://www.codeproject.com/soap/reallymostsimplesyndctn.asp
It includes newspaper-style XSLT stylesheets.
Don't worry, be happy  )
|
|
|
|
|
I'm getting some problem to bind my DropDown control with an xml file...
I made an example using xmlTextReader displaying it in a table format. its working...
But i need to display data in my dropdown control using xmlTextReader....
please help
here is my example coding...
private void Page_Load(object sender, System.EventArgs e)
{
// Placer ici le code utilisateur pour initialiser la page
string strAtt,strType,strName,strValue,strTemp,strPath;
strPath=Server.MapPath("list.xml");
System.Xml.XmlTextReader xmlRdr;
xmlRdr=new
System.Xml.XmlTextReader(strPath);
strTemp="<table border=1 width=100%><tr><th width=150px>ISBN No.</th><th>Book Name</th></tr>";
Response.Write(strTemp);
while(xmlRdr.Read())
{strType=Convert.ToString(xmlRdr.NodeType);
strName=xmlRdr.Name;
if(strType=="Element")
{
if(strName=="subject")
{
strAtt=xmlRdr.GetAttribute("name");
strTemp="<tr><td colspan=2 align='left' bgcolor='pink'>"+strAtt+"</td></tr>";
Response.Write(strTemp);}
else if(strName=="book")
{
strAtt=xmlRdr.GetAttribute("isbn");
xmlRdr.Read();
strValue=xmlRdr.Value;
strTemp="<tr><td>"+strAtt+"</td><td>"+strValue+"</td></tr>";
Response.Write(strTemp);
}
}
}
Response.Write("</table>");
xmlRdr.Close();
}
and now how will i change this code to display in a dropdown control????
-- modified at 3:10 Friday 20th January, 2006
|
|
|
|
|
You can just set the DataSource property of the DropDownList control to be your xml reader. Then specifiy how you can display the data. Also, you can load your xml document into a DataSet (might be slow depending on size) and use that instead.
~Javier Lozano
|
|
|
|
|
thanks, but i managed to do it from the xml file.I've got restriction and must used an xml file to display.
I've got another problem.
suppose ive got a checkbox in my web, when i click on the first element in the dropdownlist it must be disable and when i click on the second it must be enabled.
Im trying to make a loop but its not working, do u have any tip????
public void Page_Load(object sender, System.EventArgs e)
{
// Placer ici le code utilisateur pour initialiser la page
//string strAtt,strType,strName,strValue,strTemp,strPath,strId;
strPath=Server.MapPath("list.xml");
System.Xml.XmlTextReader xmlRdr;
xmlRdr=new
System.Xml.XmlTextReader(strPath);
strTemp="<SELECT style='LEFT: 480px; POSITION: absolute; TOP: 104px' WIDTH='130px' HEIGHT='8px' >";
Response.Write(strTemp);
while(xmlRdr.Read())
{
strType=Convert.ToString(xmlRdr.NodeType);
strName=xmlRdr.Name;
if(strType=="Element")
{
if(strName=="subject")
{
strAtt=xmlRdr.GetAttribute("name");
strTemp="<DIV>Label"+strAtt+"</DIV>";
Response.Write(strTemp);}
else if(strName=="Action")
{
strAtt=xmlRdr.GetAttribute("id");
xmlRdr.Read();
strValue=xmlRdr.Value;
strTemp="<OPTION selected>"+strValue+"</OPTION>";
Response.Write(strTemp);
}
}
}
Response.Write("</SELECT>");
/*
if(strName=="Action")
{
strAtt=xmlRdr.GetAttribute("id=1");
xmlRdr.Read();
strValue=xmlRdr.Value;
CheckBox1.Visible=true;
}
else if(strName=="Action")
{
strAtt=xmlRdr.GetAttribute("id=2");
xmlRdr.Read();
strValue=xmlRdr.Value;
strTemp=
CheckBox1=false;
}
*/
xmlRdr.Close();
}
here is my xml file>>>
<?xml version="1.0" encoding="utf-8" ?>
<booklist>
<subject id="sub1" name="Traitement du rejet">
<Action id="1">Aucun</Action>
<Action id="2">En Attente</Action>
<Action id="3">Retour Afdas</Action>
<Action id="4">Commentaire</Action>
</subject>
</booklist>
|
|
|
|
|
You the below javascipt to check/unchekc you check box.
check
uncheck
function enabledisable(dd)
{
if (dd.options[dd.selectedIndex].text=='check')
{
document.getElementById("Checkbox1").checked=true;
}
else
{
document.getElementById("Checkbox1").checked=false;
}
}
naveen
|
|
|
|
|
where can find the code of validating xml file using xsd file in C?
|
|
|
|
|
Hi,
I have an xml feed and I want to parse the data so I can get specific items and build a datatable with all the data in it so I can display it in a datagrid. Can someone help me?
Sample of XML
<stocklist recnumb="20" listname="all" sort="matchedShares" order="desc">
<stock rank="1" symbol="SIRI">
<market>NM
<booked marketsession="allday">
<bookedshares>134434586
<bookedorders>74013
<lastorder>
<ordertime>15:05:08.493-05:00
<open>
<openshares>125542614
<openorders>1159
<matched marketsession="allday">
<matchedshares>33219895
<lastmatch>
<matchprice>6.2200
<matchtime>15:05:03.775-05:00
I only want to show, symbol, match price, and match time, thanks for reading. Any help would be helpful.
Da Intern
|
|
|
|
|
Can you modify your post? I don't see XML Tags.
DevIntelligence.com - My blog for .Net Developers
|
|
|
|
|
I have been working with XML for a while however Microsoft's approach to XML in the dotNet framework has me a little confused. I am not understanding why the XmlNamespaceManager must be used in conjunction with SelectSingleNode or SelectNodes methods of the XmlDocument object when the namespaces have already been declared in the root element of the document. It seems to me that the XmlDocument object should already be "namespace aware", in this case, and resolve any XPath expression (that includes namespace prefixes) passed to aforementioned methods. Perhaps somebody can enlighten me. TIA
David Chappell (Not the MS Press author or comedian)
|
|
|
|
|
That's really a fair question and, unfortunately, I don't have a direct answer for you. However, I can tell you a couple of things about it....
Last year, I helped the Microsoft guys put together their Sarbanes-Oxley compliance solution. Internally, they had created the XnsDocument class, a namespace aware XmlDocument-like class that, when the document's content got loaded, parsed the namespaces and put them in the namespace manager.
On the other hand, having the Microsoft setup allows for you to hardcode your own prefixes so that you don't have to worry about the literal text in the document. Consider the following code. You have two XML packets whose namespace prefixes are different. However, the namespaces themselves are the same. So, you can define your own prefix and always make the call to SelectSingleNode/SelectNodes regardless of the namespace prefix.
string xml = @"<one xmlns:goo=""goo.com"" xmlns:foo=""foo.com""><foo:two /><goo:three /></one>";
XmlDocument doc = new XmlDocument();
doc.LoadXml( xml );
XmlNamespaceManager nm = new XmlNamespaceManager( doc.NameTable );
nm.AddNamespace( "floam", "goo.com" );
nm.AddNamespace( "bar", "foo.com" );
Console.WriteLine( doc.SelectSingleNode( "//bar:two", nm ).OuterXml );
xml = @"<one xmlns:mario=""goo.com"" xmlns:luigi=""foo.com""><mario:two /><luigi:three /></one>";
doc = new XmlDocument();
doc.LoadXml( xml );
nm = new XmlNamespaceManager( doc.NameTable );
nm.AddNamespace( "floam", "goo.com" );
nm.AddNamespace( "bar", "foo.com" );
Console.WriteLine( doc.SelectSingleNode( "//floam:two", nm ).OuterXml );
"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty
|
|
|
|
|
Thank you for your response, Curtis.
After posting my question, I realized, "Duh ..the XmlNamespaceManager allows us to not worry about how a particular xml document's namespaces are prefixed." ..That makes sense! I guess what doesn't make sense to me is why the XmlDocument doesn't internally use the XmlNamespaceManager according to any declared namespaces and prefixes by default. That way the XmlDocument could resolve its XPath expressions without the extra steps. Then if we wanted to use our own prefixes in our XPath expressions, we can do so with our own instance of the XmlNamespaceManager.
Again, thanks for your answer. I'm a little slow, but eventually I come around 
David Chappell (Not the MS Press author or comedian)
|
|
|
|
|
I am working at SQLXML Bulk load, and i got followinf error in the connection string
SQLXMLBULKLOADLib.ISQLXMLBulkLoad failed.
-- modified at 1:21 Wednesday 18th January, 2006
|
|
|
|
|
I would like to know how i can use XML/XSL to transform a XML file into C++/C#/... code (header) files. It should be possible for structures and enumerations.
I guess that has been done before so maybe someone can point me to some samples with a XSLT file.
Thanks
|
|
|
|
|
Well, what's the format of the source XML? If you write your own XML format then you should be able to write your own XSL transform to turn it into text.
I wrote an article[^] that used the XMI format which can be exported by a lot of UML diagramming tools. I then converted that into CodeDom, which I think is more useful than a stylesheet because I can convert to VB, C#, or JScript.
Another cool way to do it is to use CodeSmith[^]. It can read a database schema and create classes, stored procedures, etc. The templates used in CodeSmith work a lot like ASP pages and can also have code-behinds. So they're much easier to use than XSL.
|
|
|
|
|
I'm trying to add some XSL to my XML page. I have checked my CXSL code with XMLSpy and it's well formed. I insert the following line which works fine when I open up the XML file on it's own:
However, when I try openoing up my whole html document, it doesn't work. The table comes up, but there's no colour, border adjustments, nothing! Why is this? I've checked websites and even a book and they all say this code is correct. I want to get my XSL inside the HTML file but for some reason it isn't letting me. I have to hand this work in tomorrow morning so please help me quick!
|
|
|
|
|
The code didn't show up for some reason, i'll try again:
"?"
Please help me!
|
|
|
|
|
This is rediculous, how do I get the code to show up? It's the "xml stylesheet type=text/xsl href="CDCatalog.xsl". I'm hoping as i've written it normally this time without any brackets it'll show up?
|
|
|
|
|
Some expert must be there to help me surely? I'm really panicking over this. Even if you don't think you're right could someone please suggest something?
|
|
|
|
|
while posting click the ignore html tags check box at the bottom of the post
hope it works
|
|
|
|
|
When you post XML/(X)HTML documents, you need to change all the < to < and > to >. Or, you can just check the "Ignore HTML tags in this message (good for code snippets)" checkbox below the textarea. If you post it again, I can take a look at it and maybe help you.
"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty
|
|
|
|
General 
News 
Suggestion 
Question 
Bug 
Answer 
Joke 
Praise 
Rant 
Admin 
Submit an article or tip
