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thanx,.,. ok, then do i have to use char myString[max] or is there another variable type that I could use?
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You can use the member function CString as GetAt().
For eg.,
CString strName;
strName.GetAt(0);
strName.GetAt(1);
....
....
....
You can use GetLength() function of CString and loop through all the characters.
Regards,
Neelesh K J Jain. 
Don't Forget to Rate the replies when they help you.
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Is strName.GetAt(1) a read-only or I can also assign characters to them?
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There's a corresponding SetAt function.
CString members
He is smart. He will make our Windows go.
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Its a read-only, for assigning characters at a particular location, use SetAt() member function.
Don't forget to rate the replies which helps you.
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benjnp wrote:
How will I going to be able to do it in Visual c++
What about CString::GetAt(..)
"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow
cheers,
Alok Gupta
VC Forum Q&A :- I/ IV
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I created a dialog-based MFC project, I inserted a menu on the resources and put some items. I was able to place commands on the items on the menu but the shortcut keys aren't working at all. I've inserted an Accelerator on the resources and placed the shortcut keys but again the shortcut keys (ctrl+_) aren't working. Did I miss something? Bcoz shortcut keys are working when I created SDI in MFC project.
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I tried the link but my program now closes because of an error. It started to run but a warning message saying that it has an error then it will be closed.
Is there any other way on how to place a shortcut on a dialog-based MFC project?
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Hello Friends,
I am having a problem with the ToolBar Control of my SDI application. 
I am having few buttons and in between one combo box. I am trying to delete one button before combobox at runtime based on satisfying a condition.
I am able to Hide the button, but all the other buttons on its right hand side are moving, but the combo box is not moving at all due to which the button next to the combobox is getting overlapped by combobox.
Please help to overcome the above problem. Its very important for me to work this one.
Thanks alot in Advance.
Neelesh K J Jain.
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I want to determine the existing drives in my PC viaa program. I was able to do that by using FindFirstFile, if it does not able to find any single file on the path (e.g "c:\\*"), then it means that the drive does not exist, and it worked out well but the problem is that I don't know if the drive detected is a CD drive, a USB, etc. Do you guys know how will I going to determine the Drive specifically if its a normal hard disk or a CD, DVD, USB, etc? Thanx
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Thanx Michael, just exactly what I need
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benjnp wrote:
Do you guys know how will I going to determine the Drive specifically if its a normal hard disk or a CD, DVD, USB, etc? Thanx
Here is wrapper for that :-
CNMPDrivesClass[^]
"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow
cheers,
Alok Gupta
VC Forum Q&A :- I/ IV
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Guys, I REALLY need help. My program works but it does not give me the outcome I am looking for. Let's say I have this input:
110.0 12.4 -10.0 16.1 78.9 123.0 -2.0 59.3 66.5 658.45 -1.1
My program should sort these numbers up to the negative and than print, than it should keep on reading, sorting and when it hits negative again, it should print again. Like this:
110.0 12.4
123.0 78.9 16.1
658.45 66.5 59.3
My problem is that my program sorts ALL the numbers and gives an output like this
12.4 16.1 59.3 66.5 78.9
and so on whithout breaking on the negative. Can somebody look at my code and tell me what do I do wrong? Your help is greatly appreciated!!!
#include <iostream>
#include <cstdlib>
#include <stdlib.h>
using namespace std;
void bubbleSort(double array[], int size);
double *getDouble(int & numbersRead)
{
int arraySize = 0;
double inputVal;
double *array = NULL; // Initializing to NULL pointer
numbersRead = 0;
cout << "Please, enter any number of integers: ";
cin >> inputVal;
while(inputVal != -1.1)
{
if(numbersRead == arraySize)
{
double *original = array;
array = new double [arraySize * 2 + 1];
for(int i = 0; i < arraySize; i++)
array[i] = original[i];
delete [] original; // Safe if original is NULL
arraySize = arraySize * 2 + 1;
}
array[numbersRead++] = inputVal;
cin >> inputVal;
}
return array;
}
int main ( )
{
double *array;
int size;
array = getDouble(size);
for (int j = 0; j < size; j++)
{
if (array[j] > 0)
bubbleSort(array, size);
cout << array[j] << " ";
cout << endl;
}
delete [] array;
return 0;
}//end of main
void bubbleSort(double array[], int size)
{
int last = size - 2;
int isChanged = 1;
while(last >= 0 && isChanged)
{
isChanged = 0;
for(int k = 0; k <= last; k++)
if(array[k] < array[k+1])
{
double temp;
temp = array[k];
array[k] = array[k+1];
array[k+1] = temp;
isChanged = 1;
}
last--;
}
}
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Hi,
maybe this one works:
void sort(double* Array, int Begin, int End)
{
for(int i = Begin; i < (End - 1); i++)
{
int m = i;
for(int j = (i + 1); j < End; j++)
{
if (Array[m] < Array[j])
{
m = j;
}
}
double d = Array[i];
Array[i] = Array[m];
Array[m] = d;
}
}
void show(double* Array, int Begin, int End)
{
for(int i = Begin; i < End; i++)
{
cout << Array[i] << " ";
}
cout << endl;
}
int main(int argc, char** argv)
{
const int size = 11;
double array[size];
array[0] = 110.0;
array[1] = 12.4;
array[2] = -10.0;
array[3] = 16.1;
array[4] = 78.9;
array[5] = 123.0;
array[6] = -2.0;
array[7] = 59.3;
array[8] = 66.5;
array[9] = 658.45;
array[10] = -1.1;
int start = 0;
for(int i = 0; i < size; i++)
{
if (array[i] < 0)
{
sort(array, start, i);
show(array, start, i);
start = (i + 1);
}
}
return 0;
}
Regards
Achim Klein
We can do no great things, only small things with great love. - Mother Theresa
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If the array ends with a positive number:
int main(int argc, char** argv)
{
const int size = 13;
double array[size];
array[0] = 110.0;
array[1] = 12.4;
array[2] = -10.0;
array[3] = 16.1;
array[4] = 78.9;
array[5] = 123.0;
array[6] = -2.0;
array[7] = 59.3;
array[8] = 66.5;
array[9] = 658.45;
array[10] = -1.1;
array[11] = 100.0;
array[12] = 200.0;
int start = 0;
for(int i = 0; i < size; i++)
{
if (array[i] < 0)
{
sort(array, start, i);
show(array, start, i);
start = (i + 1);
}
}
if (start < i)
{
sort(array, start, i);
show(array, start, i);
}
return 0;
}
We can do no great things, only small things with great love. - Mother Theresa
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Sveta80 wrote:
My program works but it does not give me the outcome I am looking for.
So how does it work if it does not give you the outcome you are looking for? 
Sveta80 wrote:
while(inputVal != -1.1)
This condition may never evaluate to true. It's best not to test floating-point numbers for equality to a constant value. A better solution would be something like:
while (inputVal > 0.0)
...
"One must learn from the bite of the fire to leave it alone." - Native American Proverb
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If you read through the program you will see that I can not use
while (input > 0.0)
because you will get an infinite loop. How would my program will end the user's input from the keyboard?!
A line of code
while (inputVal != -1.1)
is keeping track of when the user is finished to enter numbers.
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double number;
while(cin >> number)
{
cout << number << endl;
}
Any input that is no number will terminate this loop.
We can do no great things, only small things with great love. - Mother Theresa
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Infinite loops are very easy to work around. Trying to do something with floating-point numbers that they were not designed to do is a lot more critical.
"One must learn from the bite of the fire to leave it alone." - Native American Proverb
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Hi. How can i include an image on top of a dialog? Thanks.
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Hi,
you could add a CStatic control to your dialog.
For more details click here.
Regards
Achim Klein
We can do no great things, only small things with great love. - Mother Theresa
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There is a special picture control you can add just like a static control.
Don't try it, just do it! 
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