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Hi everybody, i need help. I am working with toolBars and i dont know how i can set the text of the buttons in the toolBar. If any body can help me i will be gratefull.
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neliocc wrote:
i dont know how i can set the text of the buttons in the toolBar
SetWindowText(HANDLE_OF_BUTTON, BUTTON_TEXT);
"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow
cheers,
Alok Gupta
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I cant get the handle of a button in a toolBar, thats the problem.
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m_wndToolBar.SetButtonText(0,"this text");
m_wndToolBar.GetToolBarCtrl().SetButtonSize(CSize(22,36));
Just set the button size CSize(22,36) to values which suit you.
this is this.
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Yes but i am working with win32 API and i can not do that.
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Send a TB_SETBUTTONINFO message to the toolbar.
"You're obviously a superstar." - Christian Graus about me - 12 Feb '03
"Obviously ??? You're definitely a superstar!!!" mYkel - 21 Jun '04
Within you lies the power for good - Use it!
Honoured as one of The Most Helpful Members of 2004
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neliocc wrote:
i am working with win32 API
Then Look for TB_SETBUTTONINFO and TB_SETBUTTONWIDTH messages
"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow
cheers,
Alok Gupta
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hi,
We are doing a project on Live video conferencing in LAN.File is recoreded on a single PC but the actual thing must do is to send the data on a network.I m using directshow for this in which "IMediaControl Interface" is used for run and stop the file to record.But i need the actual data(streams).The question is:
1.How to get Audio & Video Stream data using Directshow?
2.How to send,replay this data on network?
plz reply me soon.
best regards
shumyla
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I do this over and over and I can't figure out how to make this function into a template.
void CleanUpVector()
{
std::vector<Music_Item*>::iterator iter;
for (iter = vMusic.begin(); iter != vMusic.end(); ++iter)
{
delete *iter;
}
vMusic.clear();
}
struct TAG
{
string TrackNumber;
string Title;
string Artist;
string Genre;
string Year;
string Comment;
string Album;
string PersistsAs;
};
struct Music_Item
{
HSTREAM Stream;
TAG Tag;
};
Any ideas anyone? I can't figure this out.
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You really don't want to be doing this - it's asking for trouble. You'd be much better using something like boost::shared_ptr in the vector rather than raw pointers - then, if required you can pass custom deleters into the function.
Below is an example of a template function which does what you requested. Depending on usage the call to clear() may be redundant, or may not do what you expected.
template<class T>
void cleaner(std::vector<T>& v)
{
typedef typename std::vector<T>::iterator iter;
iter cur(v.begin());
iter end(v.end());
for(; cur != end; ++cur)
{
delete (*cur);
}
v.clear();
}
EDIT: fixed typo
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Thanks that worked great.
This is the part I couldn't figure out.
<br />
typedef typename std::vector<T>::iterator iter; <br />
iter cur(v.begin()); <br />
iter end(v.end());<br />
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Perhpas I've mad a mistake here, but I'm writing an application, and the short question is the: My division seems to be incorrectly calculating:
....
double divisiontest = 5/9;
cout << setprecision (4) << divisiontest << endl
...
the result I'm getting is: 0.00000000000
as a minimum I should get .5556 ??????
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try this :
double divisiontest = 5.0 / 9.0;
It was attempting to divide two integers and 0 would be the correct answer for that.
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Thank for the simple solution, but just so I understanding this what's the difference between two syntaxs?
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5 / 9 = .5556 in real life. The compiler interprets the 5 and the 9 as integers because nothing is telling it otherwise. So in your example, 5 / 9 = 0.5556 = 0 as an integer. I believe that the default data type is integer.
5.0 / 9.0 explicitly tells the compiler that the two numbers are a double data type so you would get the correct answer.
If you had written the first as:
double five = 5;
double nine = 9;
double answer = five / nine;
you would also get the correct answer since you had declared the variables as doubles to begin with.
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According to the compiler, 5 and 9 are integers and divsion of an int by an int results in an int. If one (or both) of the numbers are of type double, then the result is a double. So
double divisiontest = 5.0 /9 ;
...
will give you the correct answer.
Regards
Senthil
_____________________________
My Blog | My Articles | WinMacro
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This would also solve the problem
double divisiontest = (double)5/9;
m0n0
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Hello fellows. I'm doing a class library in C++.NET, and I declared two classes, A and b, as follows:
<br />
public __gc class B; <br />
<br />
public __gc class A : public baseA <br />
{ <br />
private: <br />
B *entrada; <br />
B *salida; <br />
}; <br />
<br />
public __gc class B : public baseB <br />
{ <br />
private: <br />
A **entrantes; <br />
A **salientes; <br />
};<br />
However, while compiling I get the following error:
error C3160: 'entrantes' : cannot declare interior __gc pointer or reference as a member of 'espacio_nombres::B'
error C3160: 'salientes' : cannot declare interior __gc pointer or reference as a member of 'espacio_nombres::B'
Why this error happens? What can I do about it?
Thanks for your thoughts.
Regards,
KK.
One day you'll find
that I have gone,
for tomorrow may rain, so
I'll follow the sun...
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I look it over on my MSDN copy, but I didn't fully understand. As far as I understood, this error means that a class cannot have a pointer to another managed class, which really sounds to me rather absurd. That's why I posted this message, because I think somehow I didn't understand that quite well... Any thoughts?
Regards,
KK.
One day you'll find
that I have gone,
for tomorrow may rain, so
I'll follow the sun...
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Hi all,
I want to let the user to select any time zone they like from the list of time zones.
I made some research to get the list of time zones..
some say, get it from register..
Would you please tell me how to get all avaliable time zone?
Thank you.
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These Api will help:-
EnumTimeFormats<br />
EnumDateFormats<br />
EnumCalendarInfo<br />
EnumUILanguages
and for more Info visit this link:-
National Language Support[^]
"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow
cheers,
Alok Gupta
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I get the following error message when trying to cout a variable of type __int64 in VC++:
" error C2593: 'operator <<' is ambiguous "
Why is this? How can I print variables of type __int64?
Thanks a bunch guys
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Actually, let me tell you what I am trying to do. I am taking a number C to the D power mod N.
C is a 7 digit number, and D is a 7 digit number. As an example, C squared is a 13 digit number. Thats why I need a data type that can hold very large numbers, and I figured __int64 is what I need.
What algorithm woul you use here?
Thanks a lot.
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cout doesn't overload the << operator with __int64 (I think because __int64 is a MS VC++ feature, not part of the C++ standard).
You can use _i64toa() to print them. Or if you want it to work with cout the following seems to work fine:
std::ostream& operator<< (std::ostream& ostrm, __int64 i)
{
char szBuff[65];
_i64toa(i, szBuff, 10);
return ostrm << szBuff;
}
int main(int argc, char* argv[])
{
__int64 i = 9223372036854775807;
std::cout << "i = " << i << std::endl;
return 0;
}
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