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Hi
I have a third party product which exposes an api (dll/type library).
What i want to do is create a dll using some of the functions/classes/interfaces provided by the api for e.g retireve some product related information and use the notification engine to send emails etc.
This newly created dll is then going to be consumed by an application.
I am new to vc++ and have no clue how to go about creating this dll. Can somebody tell me the steps to achieve this?
I need to meet a deadline and have no clue how to go about doing it.
Any help would deeply appreciated
Regards
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What I want to do is take an input from the user to set up a grid. This grid is a multi- dimensional array. I can do this with a simple array (1-D) and create the object as new. But when I try this with a multi- dimensional I get the error "constant expression expected."
If only I had more time!
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bitsNbites wrote:
But when I try this with a multi- dimensional I get the error "constant expression expected."
Without showing the code in error, it's impossible to offer any suggestion(s).
"Ideas are a dime a dozen. People who put them into action are priceless." - Unknown
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The code that has the error is not correct. I think I need to try a different method, but this is it.
In the header I have an int pointer. int* sizeArray;
Then in a function in the class.
int row=22, col=20;
sizeArray = new int[40]; // This is OK
sizeArray = new int[row]; // This is OK
sizeArray = new int[row][col];// This errors.
"non-constant expression as array bound"
and '=' : cannot convert from 'int (*)[1]' to 'int *'
row and col will be values taken as arguments but for testing I just assign a value.
If only I had more time!
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See here.
"Ideas are a dime a dozen. People who put them into action are priceless." - Unknown
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int _tmain(int argc, _TCHAR* argv[])
{
int** sizeArray;
int row=22, col=20;
sizeArray = new int*[row];
for(int i=0; i<row; i++)
sizeArray[i] = new int[col];
for(int i = 0; i<row; i++)
for (int j=0; j<col; j++) {
sizeArray[i][j] = i*j;
}
for(int i = 0; i<row; i++)
for (int j=0; j<col; j++) {
printf("sizeArray[%d][%d] = %d\n",i, j, sizeArray[i][j]);
}
return 0;
}
http://www.priyank.in/
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Great that helps a lot. I now am using:
int** q = new int*[rows];
for(int i = 0; i < rows; i++)
q[i] = new int [col];
This works.
MSDN states "Multidimensional arrays are not equivalent to arrays of pointers." It seems that here this code is creating just that. I suspect this is why I don't see the elements in the Autos window. I will play around with this for a while and will post new questions later.
Thanks for the help.
If only I had more time!
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You can always create multi dimensional arrays by arrays of pointers pointing to another array. The difference I think is basically in memory locations, creating arrays by this method dynamically may not have continous memory locations, like that by creating arrays like int a[5][5];
http://www.priyank.in/
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Hi ,
Is there any Static address in computers in a local network?
Like the MAC Address But I want to send Information to it.
Cheers,
Thanks.
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dSolariuM wrote:
Is there any Static address in computers in a local network?
IP addresses are either statically or dynamically assigned.
dSolariuM wrote:
Like the MAC Address But I want to send Information to it.
Are you wanting to send information to an IP address or a MAC address?
"Ideas are a dime a dozen. People who put them into action are priceless." - Unknown
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I want to send information to MAC address.
Thanks.
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Have a win32 console application, when I right click on it the version tab is missing.
How do I add this information?
ThankX in advanced
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Just add a Version resource to it. Click on the ResourceView tab in the Workspace pane. Use Ctrl+R to insert a new resource. Select Version from the list.
"Ideas are a dime a dozen. People who put them into action are priceless." - Unknown
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Add a resource file (*.RC) to your project.
Add a version information resource to the resource file.
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I add a rich edit control from controls tool box, when I run my project, it appear a message box "Failed to create empty document"
What is this error ?
Could you give me an example how to create a rich edit control ?
Thank you.
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Have you called AfxInitRichEdit()?
"Ideas are a dime a dozen. People who put them into action are priceless." - Unknown
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Why do we need to use this function ?
Thank you.
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You might not need to, unless this is an MFC application. It was merely a suggestion. Do you know for certain that it is not needed?
"Ideas are a dime a dozen. People who put them into action are priceless." - Unknown
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Because it will enable/initialize the richedit support.
Maximilien Lincourt
Your Head A Splode - Strong Bad
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Hi everybody,
I have created an PopUp Menu in a CDialog...it works OK.
Now I want to create a PopUp Menu inside an ActiveX every time I click Button RIGHT of the mouse...
I have copied the code inside the function WM_RBUTTONDOWN...The problem is that it shows the Menu but it is DISABLED (it is shown but I can not select an option).
How can I do it to solve it...to make it enable?
Thanks
Javier
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The menu items will be disabled until you write the code for the menu items. When the handlers are written, then the menu items will be enabled.
Artificial intelligence is no match for natural
stupidity.
Never argue with an idiot. They will drag you down to their level where they are an expert.
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But...I have already written the handlers...or at least...this is what I think
I enclose the code here :
HMENU hMenu = ::CreatePopupMenu();
if (NULL != hMenu)
{
// add a few test items
::AppendMenu(hMenu, MF_ENABLED | MF_STRING & !MF_GRAYED, 1, "Change Color");
::AppendMenu(hMenu, MF_ENABLED | MF_STRING & !MF_GRAYED, 2, "Hide");
::AppendMenu(hMenu, MF_ENABLED | MF_STRING & !MF_GRAYED, 3, "Item 3-");
ClientToScreen(&point);
int sel = ::TrackPopupMenuEx(hMenu,
TPM_CENTERALIGN | TPM_RETURNCMD,
point.x,
point.y,
m_hWnd,
NULL);
CString s;
s.Format("The selected item is %d", sel);
TRACE(s);
::DestroyMenu(hMenu);
}
Thanks
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javi_jmc wrote:
::AppendMenu(hMenu, MF_ENABLED | MF_STRING & !MF_GRAYED, 1, "Change Color");
Do you have a function that the application would call when you click the "Change color" menu item? If not, that's what you need to do. Without a function to call, the menu item will be disabled.
Artificial intelligence is no match for natural
stupidity.
Never argue with an idiot. They will drag you down to their level where they are an expert.
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But...why do I need a function to call ? I have "sel" which gives the value of the item selected. With "sel", I can manage the selection with, for instance, a CASE
But...if it is not possible and I have to do it as you are saying...how can I link a function to a selection?
Thanks you very much.
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javi_jmc wrote:
But...why do I need a function to call
I hate to tell you this, but that's the way it is. When you click on a menu item, that's an event that the application will receive. If the app isn't going to handle the events then the menu items won't even be enabled. There's nothing to map the events to so there isn't any sense in enabling the menu item. Your case statement won't handle the menu event.
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