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Did that make any sense? If not, here's an example (lot of stuff leaved out, don't expect it to compile)
<br />
<br />
class Base<br />
{<br />
public:<br />
int m_iInt;<br />
<br />
public:<br />
int virtual GetInt() {return m_iInt);<br />
CString virtual GetClassInfo() {return CString("Base")};<br />
int NonVirtualGetInt(){return m_iInt);<br />
}<br />
<br />
class Derive1 : Base<br />
{<br />
public: <br />
int m_iAnotherInt;<br />
<br />
public:<br />
int virtual GetInt() {return m_iAnotherInt);<br />
CString virtual GetClassInfo() {return CString("Derive1")};<br />
int NonVirtualGetInt(){return m_iAnotherInt);<br />
}<br />
<br />
class Derive2 : Base<br />
{<br />
<br />
public:<br />
int virtual GetInt() {return 2 * m_iInt);<br />
CString virtual GetClassInfo() {return CString("Derive1")};<br />
int NonVirtualGetInt(){return 2 * m_iInt);<br />
}<br />
<br />
int main()<br />
{<br />
Base *pointer[3];<br />
<br />
pointer[0] = new Base;<br />
pointer[1] = new Derive1;<br />
pointer[2] = new Derive2;<br />
<br />
pointer[0]->m_iInt = 1
pointer[1]->m_iInt = 10
(CDerive1*)pointer[1]->m_iAnotherInt = 15
(CDerive2*)pointer[2]->m_iInt = 100<br />
(CDerive2*)pointer[2]->m_iAnotherInt = 150
<br />
for (i=0; i<3; i++) <br />
cout << pointer[i]->GetInt()
<br />
for (i=0; i<3; i++)<br />
cout << pointer[i]->m_iInt
<br />
for (i=0; i<3; i++)<br />
cout << pointer[i]->m_iAnotherInt
<br />
for (i=0; i<3; i++)<br />
cout << pointer[i]->NonVirtualGetInt()
<br />
for (i=0; i<3; i++) {<br />
CString cs=pointer[i]->GetClassInfo()<br />
if (cs == "Base") pointer[i]->NonVirtualGetInt()
if (cs == "Derive1") (Derive1*)pointer[i]->NonVirtualGetInt()
if (cs == "Derive2") (Derive2*)pointer[i]->NonVirtualGetInt()
}<br />
I'm sure you get the general idea. One thing that helps me in these cases is to always keep in mind that the compiler can only act on what it knows - so if it thinks an object is of type Base it will call Base-methods, unless the methods are virtual
Cheers
Steen.
"To claim that computer games influence children is ridiculous. If Pacman had influenced children born in the 80'ies we would see a lot of youngsters running around in dark rooms eating pills while listening to monotonous music"
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ng kok chuan wrote:
pointer[0] = *(new Base);<br />
pointer[1] = *(new Derive1);<br />
pointer[2] = *(new Derive2); and so on...
This what is known a late binding
ng kok chuan wrote:
the type of classes are created correctly when the constructors are called. however, when i tried to access the pointers again later in my program, the program only treats each pointer as Base and no longer as any derived classes. thus polymorphism cannot work at all... this is crucial to me as i have several classes that's supposed to belong to the vector of pointers. if i use a simple array polymorphism works. but i need the vector.
How about putting the virtual before the name of the function (in the base class)
ng kok chuan wrote:
vector < Base* > pointer)<br />
pointer[0] = *(new Base);
doesn't make sense
Surely, it shold be
pointer[0] = new Base;
Anyway, I got a sample app to give you an idea. If you e-mail I'll gladly send it to you.
Happy programming
Alton
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I am writing C++ wrapper for libCURL to send https requests to the webserver.
Currently i am finding some help on client cert authentication using the same. Please let me know if anybody has done in this.
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I need to compress an avi file using a video codec in my application
how can I do this
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I'm a relatively new programmer and I was wondering if there was an easy way to read a text file of numbers seperated by spaces into a matrix. Here's what I got:
int i, j;<br />
short ImageArray[IMAGE_SIZE_X][IMAGE_SIZE_Y];<br />
<br />
char *FileName = C:\Image.asc;<br />
<br />
ifstream ImageFile;<br />
ImageFile.open(FileName);<br />
<br />
for(i=0; i<IMAGE_SIZE_Y; ++i)<br />
{<br />
for(j=0; j<IMAGE_SIZE_X; j++)<br />
ImageFile >> ImageArray[i][j];<br />
}<br />
ImageFile.close();
I know I'm reading it wrong but I don't know the correct way to do it. Any help would be greatly appreciated.
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I've seen a few programs out there that are very small in size and actually do something (ex.: .kkreiger)... When I look at their import functions list I see only LoadLibrary and GetProcAddress. The question is: How do you remove all those additional dependencies from your programs (C++)?
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Hi,
I'm resizing the workarea of Windows in the initialization of my program so that my application will show always, like taskbar.
My problem is that sometimes, not always, the workarea reverts back to the original size.
It usually takes 1-20 seconds after I start my app to happen.
Any ideas on what is causing this behaviour and more importantly how to fix it?
I'm using Visual C++ 6 and my app is dialog based using mfc.
thanks
ahto111 at hotmail
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I use microsoft VC++.
I have a group of header and source files that I want to compile into a library to be linked in my program.
How can i do that in Microsoft Visual Studio 6 ??
Thanks in advance
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Hmmm,
I get this error and I dont now what it means!
Can anyone explane this to me, what is I doing wrong?...
TRACE1("Error: no data exchange control with ID 0x%04X.\n", nIDC);
ASSERT(FALSE);
AfxThrowNotSupportedException
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Your DDX section refers to a resource id that isn't present in your dialog or view.
/ravi
My new year's resolution: 2048 x 1536
Home | Articles | Freeware | Music
ravib@ravib.com
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Ok and how can I fix this?
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Um... add the control to your dialog/view.
/ravi
My new year's resolution: 2048 x 1536
Home | Articles | Freeware | Music
ravib@ravib.com
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Well,
it on; CDialog::OnInitDialog(); And if I take it away I get this error; ASSERT(::IsWindow(m_hWnd));
So how can I fix that?
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Buy a book. Seriously, the error messages are telling you what's wrong, did you consider researching what that means youself ? What do you think the line above means ?
Christian
I have several lifelong friends that are New Yorkers but I have always gravitated toward the weirdo's. - Richard Stringer
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Yeee,
Well that dont help me.
I dont want to delite that line so how can I keep it and still run the program?
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Look, I didn't tell you to delete a line, I suggest you take some steps to learn how to program.
It's more helpful than you think. If you don't learn to do your own research, you will never be able to code anything for yourself. These are simple issues with the way you've set up your MFC project, although to be honest, at this stage your descriptions are too vague for me to know exactly what you need to do. It sounds like you DO need to delete the line in question, it sounds like you're trying to call updatedata, or some other operation that is not valid where you're doing it, because the window has not been created yet.
Christian
I have several lifelong friends that are New Yorkers but I have always gravitated toward the weirdo's. - Richard Stringer
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The OnInitDialog() method has nothing to do with the problem. Ravi has explained, in detail, what the problem is and how to rectify it. Every control ID referenced in the DoDataExchange() method must also be present in the dialog template. For example:
void CWorkFlowTab::DoDataExchange(CDataExchange* pDX)
{
CPropertyPage::DoDataExchange(pDX);
DDX_Control(pDX, IDC_WFS_XB_ACTIVE, m_xbActive);
DDX_Control(pDX, IDC_WFS_CB_RECIPIENT, m_cbRecipient);
DDX_Control(pDX, IDC_WFS_CB_MESSAGE, m_cbMessage);
DDX_Control(pDX, IDC_WFS_XB_COMPL, m_xbCompleted);
DDX_Control(pDX, IDC_WFS_CB_RECIPIENT2, m_cbRecipient2);
DDX_Control(pDX, IDC_WFS_CB_MESSAGE2, m_cbMessage2);
}If any of the six IDC_xxx controls are missing from the dialog template (in the .rc file), I will get a run-time error such as the one you got.
"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow
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Assuming you have a dialog, you will have a function like this
void CMyDialog::DoDataExchange(CDataExchange* pDX)
{
CDialog::DoDataExchange(pDX);
DDX_Control(pDX, IDC_CONTROL, m_Control);
DDX_Control(pDX, IDC_MISSINGCONTROL, m_MissingControl);
}
Within it are DDX_Control lines, one of the lines relates to a control you have not added or have recently removed from your resource dialog.
Just remove the line containing the missing control to get
void CMyDialog::DoDataExchange(CDataExchange* pDX)
{
CDialog::DoDataExchange(pDX);
DDX_Control(pDX, IDC_CONTROL, m_Control);
}
Ant.
I'm hard, yet soft.
I'm coloured, yet clear.
I'm fruity and sweet.
I'm jelly, what am I? Muse on it further, I shall return! - David Walliams (Little Britain)
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Thank!
But here it is;
This is what I have;
CDialog::DoDataExchange(pDX);
//{{AFX_DATA_MAP(CNetEyeStatusDlg)
DDX_Control(pDX, IDC_BMP_HIDE, m_HideDisable);
DDX_Control(pDX, IDC_MESSAGE_LIST, m_ctlMsgList);
DDX_Control(pDX, IDC_TXT_MESSAGE, m_ctlMessage);
DDX_Text(pDX, IDC_MESSAGE_LIST, m_Add);
DDX_Control(pDX, IDC_EDIT_MESSAGE, m_editIcon);
DDX_Text(pDX, IDC_LOG_EVENT, m_LogEvent);
DDX_Text(pDX, IDC_STATIC_ANTAL_USER, m_Log_User);
//}}AFX_DATA_MAP
DDX_Control(pDX, IDC_LOG_STATUS, m_lbxListBox);
And all of this is in the resoure.cpp file
So what can it be?
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First of all, DDX_Control(pDX, IDC_LOG_STATUS, m_lbxListBox); should probably be above that comment.
Please consider thinking for yourself, and trying things for yourself. If you just comment out lines, you can't break anything. Try taking the lines out one at a time until the problem is solved. Or just ask yourself - which of these names refers to a control that I created but then ended up deleting ?
Christian
I have several lifelong friends that are New Yorkers but I have always gravitated toward the weirdo's. - Richard Stringer
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Well I have find It but when I delite that line I get this again!
ASSERT(::IsWindow(m_hWnd));
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Mostly likely cause - you've created another problem, of the type I described before ( you're trying to do something with the window before it's created ), and now that the earlier error is fixed, the code is getting to the right point for this to blow up.
Next step - put breakpoints in all your OnInit/OnCreate/constructor type code, and step through to see where it's breaking. Actually, if you just go into debug mode when then assert fails, you should be able to see where it's blowing up in the call stack.
Christian
I have several lifelong friends that are New Yorkers but I have always gravitated toward the weirdo's. - Richard Stringer
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Well I have find the problem and it's fix,
That for help
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