C / C++ / MFC

Re: Why I was rejected so much with following resume ?

2-Feb-05 14:11

If you're looking for a job in the U.S. or in England (or any other English speaking country), you may want to have a friend do a bit of rewriting so that it's a bit more understandable. I'm sure that much of the original formatting was lost as well, though, so it's hard to tell what's bulleted and what isn't.

With 8 years of experience, you may want to expand more on the things you've done, and eliminate personal information such as age, marital status, and hobbies.

In any event, that's what I can think of off the top of my head. But look at the bright side: at least you're getting interviews. The tech bubble is well past popped, and it's a buyers market now. There are more programmers than jobs, and lots of companies are getting hundreds of resumes for a single position. Consider yourself lucky that you're at least getting in the door.

Bob Ciora

vgrigor12-Feb-05 14:27

vgrigor1

2-Feb-05 14:27

I find job in My native country, in town where I live.
Not Us and England, but sometimes this companies - outsource US, England.

Re: Why I was rejected so much with following resume ?

Anthony_Yio2-Feb-05 23:19

Re: Why I was rejected so much with following resume ?

2-Feb-05 23:19

I think what Bob Ciora trying to say is the expected salary figure is the reason that drive the decision and might not be your resume or experience.
Or suppose Russia has too many good programmers that drive the competition crazy?

Sonork 100.41263:Anthony_Yio

vgrigor13-Feb-05 0:06

vgrigor1

3-Feb-05 0:06

SALARY:
AS I said: I much job offer skills for 80-100%,
confirm it usually, for 80-100%,
much salary offer for it precisely.
get after interview words "we like you, wait days"
and no responce - means reject.

Up to now useful - to eliminate hobies. I can delete it easily.
But many employers has such a line in resue form.

Some products is big enough, thus creating one per year in average is not a good
result ?
I written many small utilities- must I include description of it -
does not my esume will be too much, and technology repetitive ?

But is it only disadvantages you found ?

Other is perfect ?

Big thanks for brainy help.

math puzzle

ghostpirate72-Feb-05 13:26

ghostpirate7

2-Feb-05 13:26

I'm trying to use this to figure out this problem:
1abc x 4 = de52 The letters a, b, c, d, e each represents a digit in the range 1-9. No digit can be used twice. 1, 5, 2, are already used.
Just wondering if any of you have good ideas of how to get the answer. Below is some of the code I started to write for it.

#include<iostream>

using namespace std;

bool checkSolution(int,int,int,int,int);//
void display(int,int,int,int,intmain()
{

int a,b,c,d,e;
int count=0, checkR=0;

for (int a=3; a<9; a++)

{
if (a > 9 || a==5 || a==4 ) continue;

for (int b=3; b<9; b++)

{
if (b > 9 || b==5 || b==4) continue;

for (int c=3; c<9; c++)

{
if (c > 9 || c==5 || c==4) continue;

for (int d=3; d<9; d++)

{
if (d >= 9 || d==5 || d==4) continue;

for (int e=3; e<9; e++)

{
if (e >= 9 || e==5 || e==4) continue;

if (a!=b && a!=c && a!=d && a!=e)
{
count++;
break;
}

checkR=checkSolution(a,b,c,d,e);

if (checkR==1);
display(a,b,c,d,e);

}
}
}
}

}

}// end of main

bool checkSolution(int a, int b, int c, int d, int e)
{
if ((a!=b && a!=c && a!=d && a!=e) && ((1+a+b+c)*4==(d+e+52)))

return 1; // temporary return so sample will compile

else
return 0;

}

void display(int a, int b, int c, int d, int e)
{

cout << "1" << a << b << c << "\n";

}

Re: math puzzle

Bob Ciora2-Feb-05 13:43

2-Feb-05 13:43

Hey now! You should be paying people to do your homework Wink | ;)

Seriously, though, your logic is flawed:

1abc x 4 = de52

Actually resolves to:

(1000 + 100*a + 10*b + c) * 4 = 1000*d + 100*e + 52

or (factoring out the 4):

1000 + 100*a + 10*b + c = 250*d + 25*e + 13;

or (rearranging terms):

100*a + 10*b + c - 250*d + 25*e + 987 = 0

You know that a, b, c, d, and e can only be single digits in the set {3,6,7,8,9}. So try to come up with a solution, using this simple 5-entry array, as your basis.

From there, you're on your own :p

Bob Ciora

Performance Testing

LighthouseJ2-Feb-05 12:56

LighthouseJ

2-Feb-05 12:56

I'm looking to try and thread this program I've been working on so it won't hog the system when files are open and analyzed. I think I understand threads but I am looking for a (free) program that might look at my program and tell me where the most resources are used, memory, CPU and disk so I can focus the thread usage on those. I was told about something like that for Unix (forgot the name) so I'm sure there's something, I just can't seem to find it. Thanks in advance, Nathan.

Re: Performance Testing

Bob Ciora2-Feb-05 13:28

2-Feb-05 13:28

I found This Article[^] right here on CodeProject. It seems to be a Profiler (which is the type of tool you're looking for). From the screenshot that comes with the article, there looks to be a "Threads" column, but I can only see the "T" and half of the "h" Smile | :)

It might be worth a look. And like everything here...it's free! Smile | :)

Bob Ciora

Re: Performance Testing

LighthouseJ2-Feb-05 13:30

LighthouseJ

2-Feb-05 13:30

ah, good call, I was probably using the wrong search terms, many thanks.

Re: Performance Testing

Bob Ciora2-Feb-05 13:44

Private inheritance question

2-Feb-05 13:44

No worries Smile | :)

Glad to help. I guess I should've mentioned that a Profiler is what you were looking for.

Bob Ciora

Link in RichEditCtrl

merkit2-Feb-05 12:48

merkit

2-Feb-05 12:48

I have found how to use the Link mask to make text act like an internal hyperlink. The linked text is underlined and colored to resemble a hyperlink. I am trying to remove both the underline and coloring to hide the link until it is hovered over. Is there a way to do this?

Thanks.

marinme2-Feb-05 12:03

marinme

2-Feb-05 12:03

I'm trying to make a class using private inheritance from two template classes.
I've made my own String class(I'm learning from a book and it has you do this), my own Array class. the Array class is a template class, and I am using it to take a type of another template class that takes two arguments.

class Class_name: private Array< other_class<int, int> >, private String
{
public:
Class_name(int l = 10);
~Class_name();
void Set(int in = 0); //takes index for array
private:
const int len; //length of array
};

the only definition that I think is relevant is the Set() method

void Class_name::Set(int in)
{
//take input from user to pass to array

}

in this member function, I'm not sure how to call the template class type of the array's function.

using containment, I can just set a variable of array type in it and call the function using the [] operator as a reference for the class...

Thanks for your help, please let me know if I'm too vague

Re: Private inheritance question

Bob Ciora2-Feb-05 12:48

Converting DBCS to Unicode

2-Feb-05 12:48

Actually, this isn't a question of inheritance, merely of scope. If you want to explicitly call Array's Set method, you simply define the call with the proper specifier:

void Class_name::Set(int in)
{
  // Store it to the Array...
  Array<other_class>::Set(in);
}

If you don't include the Array<other_class>:: specifier, the compiler wouldn't know any better, and would end up calling Class_name::Set. This would, of course, crash your stack soon enough.

You'll find yourself doing this sort of thing a lot in C++, primarily in virtual functions that override the same function in the base class. If it's required to call the base class, then you have to explicitly define the base class specifier to force a call to the function in the base class.

Hope it helps!

Bob Ciora

RYU^^2-Feb-05 11:37

2-Feb-05 11:37

Hi GURU,

I am getting double byte value from AS400 in EBCDIC with the values 0x43 and 0xA4. These values must be converted to be 0x83 and 0x7D.

The reason is that both values (0x43 and 0xA4) will made a single character which is represented by PC code as 0x83 and 0x7D.

Please look at the scheme below:

--------------------------------------------------------------------
|               EBCDIC               |            ASCII            |
--------------------------------------------------------------------
|               0x43                 |             0xA3            |
|               0xA4                 |             0xCF            |
|            0x43 and 0xA4           |        0x83 and 0x7D        |
--------------------------------------------------------------------

As you can see from the scheme above, if I do single byte conversion, 0x43 will becomes 0xA3 and 0xA4 will becomes 0xCF. However, if double byte conversion, the value 0x43 0xA4 will become 0x83 and 0x7D.

The problem I have is when I am using MultiByteToWideChar(), it is intepreted 0x83 as single value and 0x7D as another value. Therefore the result of the conversion is 0xA3 and 0xCF. My question is, how can I made MultiByteToWideChar() knows that both 0x43 and 0xA4 are double byte values that made 1 single character?

This is the code that I did:

<br />
const int IBMCodePage = 20290;	//IBM EBCDIC Japanese code page<br />
const int PCCodePage = 932;	//PC Japanese code page<br />
<br />
BYTE byteEBCDIC[2] = {0x43, 0xA4};<br />
BYTE byteASCII[2];<br />
wchar_t wchBytes[1024];<br />
DWORD dwSize;<br />
<br />
dwSize= MultiByteToWideChar(IBMCodePage , MB_PRECOMPOSED, (const char*)byteEBCDIC, 2, wchBytes, 1024);<br />
dwSize= WideCharToMultiByte(PCCodePage , WC_COMPOSITECHECK | WC_SEPCHARS, wchBytes, dwSize, (char*)byteASCII, 2, NULL, NULL);<br />

Thanks for any helps in advance...

Cheers... Smile | :)

Anthony_Yio2-Feb-05 23:26

2-Feb-05 23:26

I suppose you need to play around with

int isleadbyte(
int c
);

or

IsDBCSLeadByte

Sonork 100.41263:Anthony_Yio

RYU^^3-Feb-05 11:26

3-Feb-05 11:26

Hi Anthony,

IsDBCSLeadByte(...) is not apply in EBCDIC. EBCDIC uses Shift-Out (0x0E) / Shift-in (0x0F) to identify the start and the end of double byte.
eg. for double byte 0x43 0xA4 it will be

------------------------------------------
|   0x0E   |  0x43  |  0xA4  |   0x0F    |
------------------------------------------
| Shift In | Byte 1 | Byte 2 | Shift Out |
------------------------------------------

Now, how can I tell MultiByteToWideChar()/WideCharToMultiByte() that both 0x43 and 0xA4 is one single double byte value? Currently MultiByteToWideChar()/WideCharToMultiByte() will treat all of the bytes as single byte value.

Any help is greatly appreciated. I really need help. Please help...

Cheers...

FYI
---
For the code page, I am using:
EBCDIC Japanese code page = 20290
ANSI (Windows) Japanese code page = 932

Anthony_Yio3-Feb-05 15:40

3-Feb-05 15:40

I am sure there should exist a Windows API that deal with such situation but I do not know which one is it and how.

If I were you, I will dissect the double byte to byte and further to 4 bits each respectively to do what you want manually. Instead of relying on API. (at least this was what I did for a case I encounter. I don't bother to search on how to use the APIs avail and detail, simply waste more time in my opinion)

A good guide to this that I think would be helpful to you is

http://www.codeproject.com/cpp/endianness.asp[^]

Sonork 100.41263:Anthony_Yio

RYU^^3-Feb-05 17:34

3-Feb-05 17:34

Hi Anthony,

Thank you for the reply. I think I wasn't clear presenting my question. Currently, when converting single byte EBCDIC, it works fine. In fact, it converts correctly on the single byte EBCDIC. The problem I really facing is when converting 2 bytes at ONE time.

MultiByteToWideChar()/WideCharToMultiByte() converts byte by byte instead of 2 bytes at a time. I am looking at ways to convert 2 bytes at ONE time. Please look at the schema again (sorry if I repeated myself):

--------------------------------------------------------------------
|               EBCDIC               |            ASCII            |
--------------------------------------------------------------------
|               0x43                 |             0xA3            |
|               0xA4                 |             0xCF            |
|            0x43 and 0xA4           |        0x83 and 0x7D        |
--------------------------------------------------------------------

As you can see if 0x43 and 0xA4 is being converted byte by byte, the result is 0xA3 and 0xCF, however, if 0x43 and 0xA4 is being converted together, the result is 0x83 and 0x7D (this is the correct result. I am expecting 0x8 0x7D).

By the way, I did try to use Big-Endian and Little-Endian, but result is still bad.

Thanks for any help in advance. I am really appreciate your help Smile | :)

Cheers...

Anthony_Yio3-Feb-05 19:29

3-Feb-05 19:29

You can use the IsDBCSLeadByteEx(20290, yourByte);

Iterate each one of your bytes.

For normal
0x43 and 0xA4 (means, it is separated), you can just use your

dwSize= MultiByteToWideChar(IBMCodePage , MB_PRECOMPOSED , (const char*)byteEBCDIC, 2, wchBytes, 1024);

For 0x43 and 0xA4 that is meant to be together, by using IsDBCSLeadByteEx to check, you should be able to know if it is or not.

Then, use your own conversion. (means write a special function to deal with such case).

hope this help.

Sonork 100.41263:Anthony_Yio

RYU^^3-Feb-05 19:50