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I don't need to go, I'm there already. You were talking about Devon, right?
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Saw SW Christmas paper, Mac and Cheese, the only thing I haven't seen is a light Saber Sausage.
After seeing the previews, I have little interest. I think it will be over the top.
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http://www.twogag.com/comics/2015-12-11-TGAG_629_Pay_The_Piper.jpg[^]
Did you ever see history portrayed as an old man with a wise brow and pulseless heart, waging all things in the balance of reason?
Is not rather the genius of history like an eternal, imploring maiden, full of fire, with a burning heart and flaming soul, humanly warm and humanly beautiful?
--Zachris Topelius
Training a telescope on one’s own belly button will only reveal lint. You like that? You go right on staring at it. I prefer looking at galaxies.
-- Sarah Hoyt
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LOL[^]
Bad command or file name. Bad, bad command! Sit! Stay! Staaaay...
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http://cube-drone.com/comics/c/its-grrreat[^]
If you have an important point to make, don't try to be subtle or clever. Use a pile driver. Hit the point once. Then come back and hit it again. Then hit it a third time - a tremendous whack.
--Winston Churchill
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I pity the tiger that have to eat some of my co-workers...
Skipper: We'll fix it.
Alex: Fix it? How you gonna fix this?
Skipper: Grit, spit and a whole lotta duct tape.
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As long as it doesn't eat the tea lady...
If you have an important point to make, don't try to be subtle or clever. Use a pile driver. Hit the point once. Then come back and hit it again. Then hit it a third time - a tremendous whack.
--Winston Churchill
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Teams made of tigers who are paid to mew, and not roar.
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How do i count for specific integer values in a datagridview row, with a column range in c#. And display the count results in a certain column.
I have tried this, but am getting an error:
for (int i = 0; i <DataGridView.Rows.Count; i++)
{
try
{
var values = DataGridView.Rows.Cast<DataGridViewRow>().Select(x => x.Cells[i].Value);
var sector1 = values.Count(x => Convert.ToInt32(x) >= 34 && Convert.ToInt32(x) <= 50);
var sector2 = values.Count(x => Convert.ToInt32(x) >= 51 && Convert.ToInt32(x) <= 100);
DataGridView.Rows[i].Cells[4].Value = values.ToString();
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
modified 13-Dec-15 11:22am.
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Start by learnoing to read; especially the bit above in red about Programming Questions.
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Start with Google.
If that doesn't help try here: Ask a question[^] - but two things:
1) Explain exactly what you have tried, and where you are stuck. The more accurate you are the better the response.
2) Pay attention to what you are doing in future: not bothering to look at instructions which tell you what not to do is a good way to annoy people. Annoyed people do not help as much as happy people...
Bad command or file name. Bad, bad command! Sit! Stay! Staaaay...
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The error am getting is "System.Linq.Enumerable+WhereSelectEnumerableIterator`2[System.Windows.Forms.DataGridViewRow,System.Object]".
Am trying to select a rang of values and count how many they are in a row, starting from a column 4 upto of all rows upto column 20 of each and every row
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You are clearly a very slow learner.
This is not the right place for technical queries, as you have been told twice before.
I repeat:
0) Start with Google.
1) Start paying attention to your surroundings. Look at the top of this page and you will see in bright red letters that this isn't the place for technical queries. So if you want to make people happy, post this in the right place. Happy people give better help than annoyed ones do...
2) Post it here: http://www.codeproject.com/Questions/ask.aspx[^] but think first: Remember that we can't see your screen, access your HDD, or read your mind - we only get what you tell us to work from. So write your question based on that!
3) Explain exactly what you have tried, and where you are stuck. The more accurate you are the better the response.
And don't post questions here again, or I for one will start to consider it as abusive behaviour...
Bad command or file name. Bad, bad command! Sit! Stay! Staaaay...
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Me think that the 'real' problem is that Google Translate can't handle numbered lists...
Skipper: We'll fix it.
Alex: Fix it? How you gonna fix this?
Skipper: Grit, spit and a whole lotta duct tape.
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Me think the "real" problem is mummy always did everything for him...
Bad command or file name. Bad, bad command! Sit! Stay! Staaaay...
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How large your code is?[^]
Skipper: We'll fix it.
Alex: Fix it? How you gonna fix this?
Skipper: Grit, spit and a whole lotta duct tape.
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Before obfuscation!
<sig notetoself="think of a better signature">
<first>Jim</first> <last>Meadors</last>
</sig>
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True.
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Friend: Do you mean your whole life fits on two 3.5 inch floppy disks?
Coder: Well, yes, ... ... ... and also some cache in my bank account
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The flaw with that comic:
If he's only been coding for 12 years, it's kinda surprising he's used floppies long enough to still remember their storage capacity.
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A european floppy or an african floppy?
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After years and years of using JavaScript, only now do I find that checking for zero on the denominator when dividing is a complete waste of time since JavaScript handles it gracefully without crashing.
console.log(0 / 0);
console.log(1 / 0);
var divide = (...args) => args.reduce((a, b) => a / b);
console.log(divide(0, 0));
console.log(divide(1, 0));
var result = divide(42, 0);
saveMeSomehow.result = isNaN(result) || !isFinite(result) ? 0 : result; These young kids these days just don't know how spoiled they are.
Note: I don't think the syntax highlighting supports ES6 yet, so yay I broke the Internet.
Jeremy Falcon
modified 13-Dec-15 1:20am.
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