mysql_num_rows() expects parameter 1 to be resource

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Helo Coders

I'm trying to insert a record into a database table but i'm getting this error

mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\wamp\www\United_Nations\register.php on line 107

I do not know what is wrong. Please help

include('localhost.php');
if (isset($_POST["SubmitButton"])){
$fullname=$_POST['FirstName'];
$Gender=$_POST['YourGender'];
$AgeGroup=$_POST['AgeGroup'];
$Organisation=$_POST['Org'];
$Purpose=$_POST['Purpose'];
$NRC=$_POST['NRC'];
$Province=$_POST['Province'];
$dbDate=$_POST['dbDate'];
$Address=$_POST['Address'];
$query=mysql_query("SELECT * FROM students WHERE NRC='$NRC'");
$numrows=mysql_num_rows($query); // this is line 107 in my editor
if($numrows==0){
$sql = ("INSERT INTO `students` set FullName='$fullname', Gender='$Gender', AgeGroup='$AgeGroup', Organisation='$Organisation', Purpose='$Purpose', NRC='$NRC', Province='$Province', dbDate='$dbDate', Address='$Address'");
$result=mysql_query($sql);
if($result)
echo " Data has been Saved ";
}else {
echo "Could not Save Data";
}
}
?>

Posted 10-Dec-14 5:33am

Member 11301170

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Peter Leow · Answer 1 · 2014-12-10T06:08:00

mysql_query returned false, that caused the error at mysql_num_rows(), you could have concatenated using . in php like this:

WHERE NRC='".$NRC."'");

However, there are two reasons here that you should not do it, rewrite your code instead:
1. mysql extension has been deprecated as of PHP 5.5, it is recommended to use mysqli or PDO, read more: Choosing MySQL APIs[^]
2. Use prepared statement instead of injecting parameters directly in the sql query owing to sql injection risk, read more: Prepared Statements in PHP and MySQLi[^]

amin khoshzahmat · Answer 2 · 2014-12-10T06:26:00

Solution 2

Check $query , or $sql before passing it to mysql_fetch_array or mysql_num_rows . You'll find that it's false because the query failed

Posted 10-Dec-14 6:26am

amin khoshzahmat