[Solved] Problem while opening OpenFileDialog

Question

3.77/5 (3 votes)

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Hello,

In my application, when i am trying to open a OpenFileDialog, i am getting an error as:
"Current thread must be set to single thread apartment (STA) mode before OLE calls can be made. Ensure that your Main function has STAThreadAttribute marked on it. This exception is only raised if a debugger is attached to the process".

I did added [STAThread] attribute to my main function but still i am getting this error.

In my main form, i am opening another form as ShowDialog() and inside that form i am trying to call OpenFileDialog(), is this not allowed?

Please tell me what i am doing wrong.

Thanks,
Nagendra.

Posted 26-Nov-10 0:50am

nagendrathecoder

Updated 26-Nov-10 1:12am

v2

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Comments

tranthuongthien 3-May-13 22:29pm

Thread thdSyncRead = new Thread(new ThreadStart(syncRead));
thdSyncRead.SetApartmentState(ApartmentState.STA);
thdSyncRead.Start();

tranthuongthien 3-May-13 22:30pm

Bạn cần thêm dòng lệnh (command) thdSyncRead.SetApartmentState(ApartmentState.STA);
ở bên dưới Thread như thế là được . Tôi đã thử và thành công.

Vishwaeet 13-Jan-15 1:21am

Great solution. It worked for me in asp.new web application.

Member 11638754 2-May-15 6:42am

Ya bro... u r right...

Ajayk3 18-Apr-20 8:46am

Working file, it is need to be used in the thread which is running and giving error

2 solutions

Solution 3

public class Invoker
{
public CommonDialog InvokeDialog;
private Thread InvokeThread;
private DialogResult InvokeResult;

public Invoker(CommonDialog dialog)
{
InvokeDialog = dialog;
InvokeThread = new Thread(new ThreadStart(InvokeMethod));
InvokeThread.SetApartmentState(ApartmentState.STA);
InvokeResult = DialogResult.None;
}

public DialogResult Invoke()
{
InvokeThread.Start();
InvokeThread.Join();
return InvokeResult;
}

private void InvokeMethod()
{
InvokeResult = InvokeDialog.ShowDialog();

}
}

Usage

SaveFileDialog dlg = new SaveFileDialog();
if (DialogResult.OK == (new Invoker(dlg).Invoke())) { /*handle result*/ ;}

Posted 26-Jun-14 4:17am

siminal

Updated 26-Jun-14 4:18am

v2

Comments

[no name] 26-Jun-14 10:23am

The question asked and answered 4 years ago. Why are you digging up dead questions to answer?

Member 10137996 12-Dec-14 18:50pm

//SaveFileDialog dlg = new SaveFileDialog();
FolderBrowserDialog folderBrowserDlg = new FolderBrowserDialog();
if (DialogResult.OK == (new Invoker(folderBrowserDlg).Invoke()))
{

// A new folder button will display in FolderBrowserDialog.
folderBrowserDlg.ShowNewFolderButton = true;
//Show FolderBrowserDialog

>>>//get error DialogResult dlgResult = folderBrowserDlg.ShowDialog();
if (dlgResult.Equals(DialogResult.OK))
{
//Show selected folder path in textbox1.
textBox1.Text = folderBrowserDlg.SelectedPath;
//Browsing start from root folder.
Environment.SpecialFolder rootFolder = folderBrowserDlg.RootFolder;
}
}

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**JF2015** · Accepted Answer · 2010-11-26T00:52:00

Solution 1

Hi,

see this thread on MSDN that shows several possible solutions. See if one of them helps you.

http://social.msdn.microsoft.com/Forums/en-US/winforms/thread/2411f889-8e30-4a6d-9e28-8a46e66c0fdb/[^]

Posted 26-Nov-10 0:52am

JF2015

Comments

nagendrathecoder 26-Nov-10 7:11am

Thanks man, i used the solution of Threading from that link and it solved my problem.