I Want To Create Table In Mysql With Use Of Random() Function I Try But Cant Create.

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PHP

<?php
$con = mysql_connect("localhost","root","");
   		mysql_select_db("textile");
		if (!$con)
		{
			die('Could not connect: ' . mysql_error());
		}

$temp_table=rand(1000,9999);
$sql="CREATE TABLE $temp_table(FirstName CHAR(30),LastName CHAR(30),Age INT)";

// Execute query
if (mysql_query($con,$con))
  {
  echo "Table persons created successfully";
  }
else
  {
  echo "Error creating table: " . mysqli_error($con);
  }

?>

but not created please help..

Posted 29-Mar-14 5:01am

sumit WanZa

Updated 29-Mar-14 5:12am

CHill60

v2

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CHill60 29-Mar-14 11:11am

Any error message?

Peter Leow 29-Mar-14 12:04pm

Do you understand your code?

1 solution

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Mohibur Rashid · Answer 1 · 2014-03-29T13:15:00

Why would you do that? why would you create table with random name?

by the way, change your sql like below:

PHP

$sql="CREATE TABLE `".$temp_table."`(FirstName VARCHAR(30),LastName VARCHAR(30),Age INT)";//no unique id??

and correct your mysql_query function like this:

PHP

mysql_query($sql,$con);//you wrote: mysql_query($con,$con)