Array comparision in java

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Dear,

i have two arrays and need to compare index 1 of one array and index 1 of second array like 2-2,3-3 like that upto array length at any time mismatch means exit

C#

String tt="Adyar, Chennai, Tamil Nadu, India";
        String[] parts = tt.split(",");
        String tt1="Chennai, Tamil Nadu, India";
        String[] parts1 = tt1.split(",");

need compare this two array form last

if sencond array is compare sucessfully with first array then need give output

thanks in advance

Posted 7-Jan-14 0:59am

mekalareddy

Updated 7-Jan-14 1:03am

v2

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BK 4 code 7-Jan-14 7:03am

exactly what do you need as a result after comparison?

phil.o 7-Jan-14 7:12am

And what have you already tried?

2 solutions

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CPallini · Accepted Answer · 2014-01-07T01:30:00

Solution 1

Java

boolean comArr(String [] sa1, String [] sa2)
{
  if (sa1.length != sa2.length) return false;
  for (int n=0; n<sa1.length; ++n)
  {
    if ( ! sa1[n].equals(sa2[n]) ) return false;
  }
  return true;
}

[update]
In order to check if an array contains the other, you might use:
(Please note you have to use split(", "), in your original code)

Java

public static boolean comArr(String [] sa1, String [] sa2)
{
  String [] bigger;
  String [] smaller;

  if (sa1.length < sa2.length)
  {
    bigger = sa2;
    smaller = sa1;
  }
  else
  {
    bigger = sa1;
    smaller = sa2;
  }
  int d = bigger.length - smaller.length;

  for (int offset = 0; offset <= d; ++offset)
  {
    int n;
    for (n=0; n<smaller.length; ++n)
    {
      if ( !smaller[n].equals(bigger[offset+n])) break;
    }
    if ( n == smaller.length) return true;
  }

  return false;
}

[/update]

Posted 7-Jan-14 1:30am

CPallini

Updated 7-Jan-14 2:58am

v3

Comments

mekalareddy 7-Jan-14 7:57am

thanks pallini
but size of array are not same in some conditions

CPallini 7-Jan-14 8:02am

If the size is not the same how can they be equal?
Are you instead checking if one of the arrays contains the other?

mekalareddy 7-Jan-14 8:25am

ya pallini sir,but if 2 array elements all are match with first array means enough
for example
String tt="aa,aaa,aaaa,Chennai, Tamil Nadu, India";
String[] parts = tt.split(",");
String tt1="aaaa,Chennai, Tamil Nadu,India";
String[] parts1 = tt1.split(",");
like this two arrays if 2 array all element in first with corresponding index then return true

CPallini 7-Jan-14 8:34am

That confirms you are checking if an array contains (or is equal to) the other one.

mekalareddy 7-Jan-14 8:43am

need to check if there 10 elements in first and 5 element in second array check like 10-5,9-4,8-3,7-2,6-1 like that based on second array no need of size if match return true

mekalareddy 8-Jan-14 0:14am

GM sir,

i tried this code but this is not working. what i need is
String tt=" LB road, Indiranagar, Adyar, Chennai, Tamil Nadu, India"; this adress i got from network

my adress is Adyar, chennai, TamilNadu, India.

now need to compare my adress is in network in above example my adress is match with network address so need to return true

CPallini 8-Jan-14 3:32am

It looks you need case-insensitive string comparison. It is simple to modify the code in order to achieve that (you could, for instance, convert the strings in upper case and then compare).

mekalareddy 8-Jan-14 5:00am

ya got sir thanks for help

CPallini 8-Jan-14 5:07am

You are welcome.

mekalareddy 8-Jan-14 5:35am

can you give ur fb account name

CPallini 8-Jan-14 5:41am

Why? I don't think it is needed.

mekalareddy 8-Jan-14 8:16am

k sir no problem
just need to develop my skills from you and sharing any tech news

mekalareddy 19-Jan-14 23:49pm

Hi sir,
gud morning, small question..

i need to get data form sql server table of system to my application in android mobile so that previously i used web services is there any another way to get data pls explain the different view if possible with examples

thanks in advance

Giannakakis Kostas · Accepted Answer · 2014-01-07T01:52:00

Solution 2

You can also use Arrays.deepEquals:

Java

boolean isEqual = Arrays.deepEquals(parts, parts1);

Posted 7-Jan-14 1:52am

Giannakakis Kostas

Comments

mekalareddy 7-Jan-14 8:29am

thanks Giannakakis Kostas, but if different length means