Image Switching in a Picture Box

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Hello
OK my question might be a bit vague. Say i have two images i-e "image 1" and "image 2" and i want both of them to be displayed one after the other one in the same picturebox say picturebox1. Now one way that might not be a smart way of doing it is

C#

while(true)
{
picturebox1.image=image 1;
picturebox1.refresh();
pictureboz1.image=image 2;
picturebox1.refresh();

}

Is there any other way of doing it.?
Thanks anyways

Posted 20-Sep-13 23:47pm

loraloper_22

Updated 21-Sep-13 0:11am

v2

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2 solutions

Solution 1

Try some of these links[^].

Posted 21-Sep-13 0:18am

Richard MacCutchan

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OriginalGriff · Accepted Answer · 2013-09-21T00:19:00

Solution 2

Well, no, that's not a smart way - for a couple of reasons:
Firstly, it'll probably not show any image at all because it sits in a loop changing them and never gets a chance to do the Paint event for anything...
Secondly, because if it did show anything, it would be replaced so quickly that the user probably wouldn't notice it at all...

It's difficult to say exactly what to do, because you don;t specify the environment you are running in, but the use of PictureBox implies WinForms, so I'll go with that:
1) Add a Timer to your form, and set it's Interval property to 1000 - that's a one second interval. Start the timer.
3) Add a private bool field to your form class, call it showFirst and set it to true
2) Handle the Timer.Tick event, and do this:

C#

pictureBox1.Image = showFirst ? image1 : image2;
showFirst = !showFirst;

That should change your image every second.

Posted 21-Sep-13 0:19am

OriginalGriff

Comments

loraloper_22 21-Sep-13 6:32am

That is fine but the problem is i want to display it in a loop which i am not able to do by your solution. Say i want something like user to pres a button and then it should start switching images in a loop I-e continuously doing this task. I hope i am not bothering but i am just a beginner in this programming world

OriginalGriff 21-Sep-13 6:40am

Um. Did you try it? :laugh:
That's what the showFirst variable is there for - it toggles from true to false each time, and causes the image to change. Because the Tick event runs continually once the timer is started, each second the value of showFirst changes, and so does the image.

If you want it to start when the user presses a button, start the timer running in the button click handler.

loraloper_22 21-Sep-13 6:48am

my bad :P

loraloper_22 21-Sep-13 6:56am

Still now working ok let me explain it a bit further i created ShowFirst and set it to true then i created a windows.form timer and now this is inside my button clic handler
{
t1=1000;
t1.start();
picturebox1.image=showFirst ? image 1: image 2;
showFirst=!showFirst;
}
and when i debug it the code it runs only for one iteration and then leaves the event handler?Do i need to call the tickevent somewhere?
Beginner so excuse my silly mistakes

OriginalGriff 21-Sep-13 7:34am

No, read the instructions: the last two lines should be in the Timer.Tick event handler so they happen each time the timer fires.
(and when you show code, it's a good idea to copy and paste it - the sample you show won't compile) ;)

loraloper_22 21-Sep-13 11:34am

Thanks a lot for you help really it worked like a charm!!! :)
Thank you so much
Regards

OriginalGriff 21-Sep-13 11:50am

You're welcome!

loraloper_22 24-Sep-13 15:20pm

After few days of playing around the solution i am again kind of a stuck
Ok it works perfect for the first time. and i ma maintaining a variable(counter) in the event handler that makes the switching b/w images to 5 times but when it is over and when i again press the button i dont see anything on the picturebox but when i save the images in hardrive that works fine the problem is it just does not show it on picture box for the second time when i press the button. Below is the code i wrote inside event handler
if(counter<=5)
{
pictureBox4.Image = showFirst ? resultImage : over_resultImage;
showFirst = !showFirst;
counter++;
}

OriginalGriff 24-Sep-13 15:29pm

Have you considered adding an "else" clause?
if(counter<=5)
{
pictureBox4.Image = showFirst ? resultImage : over_resultImage;
showFirst = !showFirst;
counter++;
}
else
{
counter = 0;
}

Though I don't really see what you need the counter for - unless you are trying to display more than two images, in which case you need to replace the bool with a counter, and probably set up an array of images to show.

loraloper_22 24-Sep-13 15:36pm

actually there is an else clause i just didnt copy it :( which sets the counter to zero and time but it is still not working. counter is there for the number of times i want to see the switching of images. For example i want to see the switching between two images for 5 times so the counter when reaches to the 5 it should stop display after that.

OriginalGriff 25-Sep-13 5:46am

I've read this about six times now, and I still can't work out what you are trying to do, or what the problem is! :laugh:
It sound like you want to have the user press a button, and the two pictures will swap five times, then stop swapping until he presses it again? Is that right? Or am I hopelessly confused because I can't see why you would want to do that?
(I will admit, the later is pretty normal... :sigh: )

loraloper_22 25-Sep-13 5:57am

Well i understand and i generally confuse people with my below common sense questions so i will take it as a compliment :) you are partly right the two pics will swap 5 times after that it will stop since now after five times i call "timer1.stop()".... now when the user agian presses the play button (so that he should again see image swapping for 5 times) it does not happen. If it confused you more then i am nice enough to say its all right you can stop helping me :).
Regards

OriginalGriff 25-Sep-13 6:17am

You can do it by stopping the timer - but then you need to call Timer.Start again if you want it to proceed.

My preference is not to stop the timer unless I have to.
What I would do is work off the count: dump the else condition completely, and set the count to zero in the button press event. That way, the picture will immediately start swapping again, and the user can press it as many times as he likes, but all he will get is five swaps from his last press.
When the Timer Tick event occurs, if the five swaps have been done, nothing happens and it just exits.

Does that make sense?

loraloper_22 25-Sep-13 7:13am

It does let me try