I'm not sure what you want to achieve, but have a look at below example:
SELECT F1, COUNT(F1) AS CountOfF1, SUM(F2) SumOfF2
FROM (
SELECT 1 AS F1, 2 AS F2
UNION ALL SELECT 1, 5
UNION ALL SELECT 1, 3
UNION ALL SELECT 1, 4
UNION ALL SELECT 2, 12
UNION ALL SELECT 2, 5
UNION ALL SELECT 2, 5
UNION ALL SELECT 2, 15
) AS T
GROUP BY F1
SELECT COUNT(F1) AS DistinctF1Fields, SUM(Q.CountOfF1) AS SumOfCountOfF1
FROM (
SELECT T.F1, COUNT(T.F1) AS CountOfF1, SUM(T.F2) SumOfF2
FROM (
SELECT 1 AS F1, 2 AS F2
UNION ALL SELECT 1, 5
UNION ALL SELECT 1, 3
UNION ALL SELECT 1, 4
UNION ALL SELECT 2, 12
UNION ALL SELECT 2, 5
UNION ALL SELECT 2, 5
UNION ALL SELECT 2, 15
) AS T
GROUP BY T.F1
) AS Q
Result of 1. query:
1 4 14
2 4 37
Result of 2. query:
2 8