Why else the code will not run؟

Question

1.00/5 (2 votes)

See more:

JavaScript

$.get(
            "ajax.php",
            {dta:val1},
  function(data1)
          {
           if(data1.msg1!=null)
            {
           alert(val1);
         
         
          $('#div10').text(data1.msg1);
         
          }
            } 
          else
          {
          alert('sosool')
             }
          }  , 'json'
            );

Why else the code will not run?
What is the problem?
tnx

[Edit]Code block added[/Edit]

Posted 17-Feb-13 3:44am

ali sheibani

Updated 17-Feb-13 3:53am

Thomas Daniels

v3

Add a Solution

Comments

Shahare 17-Feb-13 9:54am

Maybe because the code here is not complete :)
Tried to copy your code above and it does not look good - if this is all the code use indentation to make it look right and you`ll see your problem

Sergey Alexandrovich Kryukov 17-Feb-13 12:19pm

Maybe because you reflect '?' in the mirror? :-)

You see, such questions cannot be valid in principle. "Not run" is not anything certain. You need to tell us what did you try to achieve, what did you expect from the code you show, what do you observe instead and why do you think it's wrong...
—SA

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Shobhana.n · Accepted Answer · 2013-02-18T08:19:00

$.get(
            "ajax.php",
            {dta:val1},
  function(data1)
          {
           if(data1.msg1!=null)
            {
           alert(val1);
         
         
          $('#div10').text(data1.msg1);
         
          
            } 
          else
          {
          alert('sosool')
             }
          }  , 'json'
            );

One extra curly brace :D .....Function ends before executing else part... :D