Why it throws type error ?

Question

1.00/5 (1 vote)

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It shows throws
id = [int(data[-1]['emp_id'][6:])]
TypeError: list indices must be integers or slices, not str.

how to solve this ?

What I have tried:

id = [int(data[-1]['emp_id'][6:])]
emp_id = id[-1] + 1
id.append(str(emp_id))

Posted 13-Jun-22 4:36am

Member 15667238

Updated 13-Jun-22 4:47am

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Richard MacCutchan · Answer 1 · 2022-06-13T04:42:00

Solution 1

As the message clearly states, you cannot use a string type to address elements of a list. The index value 'emp_id' is not allowed. Maybe you meant to use that variable name without the quotes:

Python

id = [int(data[-1][emp_id][6:])]

Posted 13-Jun-22 4:42am

Richard MacCutchan

Comments

CPallini 13-Jun-22 10:45am

5.

Patrice T · Answer 2 · 2022-06-13T04:47:00

Solution 2

Quote:
TypeError: list indices must be integers or slices, not str.

Python

id = [int(data[-1]['emp_id'][6:])]
//                 ^ here is the error

Python expect integer indices 0, 1, 2, 3 ...
~~I fear Python will chock on -1 and 6: too.~~
NumPy Array Indexing[^]

Posted 13-Jun-22 4:47am

Patrice T

Updated 13-Jun-22 5:07am

v2

Comments

Richard MacCutchan 13-Jun-22 10:55am

No, Python will be happy with -1, which is the last item in the list, and 6: which is the slice offset 6 to the end. See 3. An Informal Introduction to Python — Python 3.10.5 documentation[^].

Patrice T 13-Jun-22 11:06am

Thanks for information, I am not Python user :)

Richard MacCutchan 13-Jun-22 11:24am

Python has lots of features that are a bit strange until you get used to them.

Also, if you read it, you will see that NumPy uses the same indexing as Python.