I have used inline const and want to call in a different function but the variable it include gives an error

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any.cpp

C++

#include <iostream>
namespace hey
{
	inline const int Obiick()
	{
		double pi{ 3.1416 };
		return 0;
	}
}

main.cpp

C++

#include <iostream>
inline const int Obiick();

int main()
{
	int B{ Obiick()};
	std::cout << B; 
	return 0;  
}

in the output, it is saying that pi is initialized but not referenced ( when I don't use namespace in the any.cpp file.
then when I use namespace and try to use hey::Obiick() , it gives me a different error.

What I have tried:

i have tried using namespace and without namespace for inline . but everytime I'm getting error. Im new here so .

Posted 24-Apr-22 9:56am

Obiick

Updated 24-Apr-22 12:45pm

merano99

v2

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Daniel Pfeffer · Answer 1 · 2022-04-24T12:45:00

There are multiple issues here.

* 'Pi' initialized but not referenced message
This is a warning, rather than an error. The compiler sees that you have declared a variable, but do not use it anywhere. Either delete the declaration or use the variable.

* Namespaces
You have declared 'inline const int Obiick();' before your main() function. This is in the global namespace, i.e. ::Obiik(). You then declare 'inline const int Obiik()' in the 'hey' namespace, i.e. hey::Obiik(). These are not the same function!

If you wish to declare a function inside a namespace, you should write:

namespace foo
{
int bar();
}

* inlining
You should declare 'inline' functions either in the same source file where they are used or in a header file common to all users of the inline function.

I hope that this helps!