How to get 3 decimal number in output

Question

1.00/5 (2 votes)

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if the input is 65.790, then the output will be 65.790, 65, and A.

What I have tried:

using System;
using static System.Console;

namespace ConsoleApp08
{
class Program
{
static void Main(string[] args)
{
double aNumber;
WriteLine("Please input a number.");
aNumber = Convert.ToDouble(ReadLine());
WriteLine($"Your number as a double:{aNumber}");
aNumber = Convert.ToInt32(aNumber);
WriteLine($"Your number as an int:{aNumber}");
aNumber = Convert.ToChar(aNumber);
WriteLine($"Your number as a char:{aNumber}");

}
}
}

Posted 28-Jan-22 5:25am

Jay Katariya

Updated 28-Jan-22 6:00am

Richard Deeming

v2

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Comments

Richard MacCutchan 28-Jan-22 11:34am

You have declared aNumber as a Double type, so you cannot store an integer or a character into it.

Jay Katariya 28-Jan-22 11:37am

Yes, how to get 3 decimal in double as output?

Richard MacCutchan 28-Jan-22 11:40am

You cannot store an integer in a double type.

2 solutions

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M Imran Ansari · Answer 1 · 2022-01-28T06:00:00

A double cannot convert into char. Try the following code:

double aNumber, bNumber;
char charNo;
Console.Write("Please Input a Number:");
aNumber = Convert.ToDouble(Console.ReadLine());
bNumber = Math.Truncate(aNumber);
charNo = Convert.ToChar((int)bNumber);
Console.WriteLine("Result " + aNumber + "," + bNumber + "," + charNo);

Richard MacCutchan · Answer 2 · 2022-01-28T05:40:00

Solution 1

This is a duplicate of your question at Use the appropriate method of the convert class[^]. Please do not repost.

Posted 28-Jan-22 5:40am

Richard MacCutchan