How do I write this code,

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How do i make a program use recursive function to input salary every month and display the output of accumulated salary every month.

example:

Month 1: 10000 (input) accumulated salary: 10000 (output)
Month 2: 5000 (input) accumulated salary: 15000 (output)
Month 3: 7000 (input) accumulated salary: 22000 (output)
Month 4: 8000 (input) accumulated salary: 30000 (output)
...
Month 12:...

What I have tried:

I try use recursive function and loop (while(true)), didn't work (maybe iam wrong).

Posted 5-Dec-21 17:35pm

Firdaus Nandu

Updated 5-Dec-21 20:41pm

v2

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Patrice T 6-Dec-21 0:58am

Show your work.

Firdaus Nandu 6-Dec-21 1:08am

#include<iostream>
using namespace std;
int main(){
int a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,x,y;

while(true){
cout<<"====================================="<<endl;
cout<<"="" "<<endl;
="" cout<<"month="" 1:="" ";cin="">>a; cout<<"\t\t\tAccumulated: "<<a;
cout<<"\nmonth="" 2:="" ";cin="">>b; cout<<"\t\t\tAccumulated: "<<a+b;
cout<<"\nmonth="" 3:="" ";cin="">>c; cout<<"\t\t\tAccumulated: "<<c+a+b;
cout<<"\nmonth="" 4:="" ";cin="">>d; cout<<"\t\t\tAccumulated: "<<a+b+c+d;
f="a+b+c+d;
" cout<<"\nmonth="" 5:="" ";cin="">>e; cout<<"\t\t\tAccumulated: "<<e+f;
cout<<"\nmonth="" 6:="" ";cin="">>g; cout<<"\t\t\tAccumulated: "<<e+f+g;
cout<<"\nmonth="" 7:="" ";cin="">>h; cout<<"\t\t\tAccumulated: "<<e+f+g+h;
i="e+f+g+h;
" cout<<"\nmonth="" 8:="" ";cin="">>j; cout<<"\t\t\tAccumulated: "<<j+i;
cout<<"\nmonth="" 9:="" ";cin="">>k; cout<<"\t\t\tAccumulated: "<<j+i+k;
cout<<"\nmonth="" 10:="" ";cin="">>l; cout<<"\t\t\tAccumulated: "<<j+i+k+l;
m="j+i+k+l;
" cout<<"\nmonth="" 11:="" ";cin="">>n; cout<<"\t\t\tAccumulated: "<<n+m;
cout<<"\nmonth="" 12:="" ";cin="">>o; cout<<"\t\t\tAccumulated: "<

Patrice T 6-Dec-21 2:06am

Use Improve question to update your question.
So that everyone can pay attention to this information.

2 solutions

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CPallini · Accepted Answer · 2021-12-05T20:41:00

Write a function like, for instance

C++

int accumulate_salary(int month, int sum_of_salary)
{
  // insert here the stop condition, returning the accumulated sum of salaries
  // insert here the recursion step, calling the function itself for the next month, with the updated sum of salaries
}

and then, call it in you main function, e.g.

C++

int main()
{
  cout << "sum of salaries " << accumulate_salary(1, 0) << endl;
}

KarstenK · Accepted Answer · 2021-12-05T19:49:00

Solution 1

You can use the salary of 0 as inner abortion criteria. Use a struct or class to store the already computed data.

Posted 5-Dec-21 19:49pm

KarstenK