Php mysql error inserting

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Hello! I keep getting a error for the following insert statement:

PHP

$uploadAttempts = "INSERT INTO `results` (`fullName`, `temp`, `data1`, `data2`, `data3`, `data4`, `data5`, `data6`, `message`, `result`, `dateTime`, `indexData`) VALUES ('$answer1', '$answer2', '$answer3', '$answer4', '$answer5', '$answer6', '$answer7', '$answer8', '$answer9', '$overallResult', CURRENT_TIMESTAMP, '1'";

Not sure what is wrong with it, I referenced back to another insert statement and everthing looks good. Could it be the CURRENT_TIMESTAMP?

What I have tried:

I tried using php checker with the result of :

Error: There is 1 more opening parenthesis '(' found

I also tried putting single quotes around CURRENT_TIMESTAMP with no luck.

Posted 16-May-20 15:25pm

Cody O'Meara

Updated 16-May-20 15:53pm

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Garth J Lancaster · Accepted Answer · 2020-05-16T15:54:00

There are only two problems with your SQL

1) you should never concatenate strings to form SQL - you leave yourself open to SQL injection - xkcd: Exploits of a Mom[^] - so please learn how to use a parameterised SQL statement - yes, its possible, even in PHP ;-)

2) this

$uploadAttempts = "INSERT INTO `results` (`fullName`, `temp`, `data1`, `data2`, `data3`, `data4`, `data5`, `data6`, `message`, `result`, `dateTime`, `indexData`) VALUES ('$answer1', '$answer2', '$answer3', '$answer4', '$answer5', '$answer6', '$answer7', '$answer8', '$answer9', '$overallResult', CURRENT_TIMESTAMP, '1'";

might need to be

...CURRENT_TIMESTAMP, '1')";

(note the ')' before the closing double-quote '"' )