For some reson it shows 5 and not 5.5, I used float for that purpose. Why?

Question

1.00/5 (1 vote)

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#include <iostream>
using namespace std;
int main()
{
float va = 11 / 2;
cout << va << endl;
return 0;
}

What I have tried:

#include <iostream>
using namespace std;
int main()
{
    float va = 11 / 2;
    cout << va << endl;
    return 0;
}

Posted 10-May-20 1:08am

Member 14826587

Updated 10-May-20 1:14am

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phil.o · Accepted Answer · 2020-05-10T01:10:00

Solution 1

11 is an integer, 2 is an integer, their division is therefore an integer division. Try

C++

float va = (float)11 / 2

instead.

Posted 10-May-20 1:10am

phil.o

Patrice T · Accepted Answer · 2020-05-10T01:15:00

Quote:
For some reason it shows 5 and not 5.5, I used float for that purpose. Why?

The reason is very simple: in with C/C++, a division of integers is an'integer division' with integer result, thus 5 in your case, because 11 is 5*2+1.
The solution is to divide floats or cast to floats.
in your code, declaring va as float does not change the division.

C++

#include <iostream>
using namespace std;
int main()
{
    float va = 11.0 / 2.0;
    cout << va << endl;
    return 0;
}