Printing the product of even numbers fibonacci number

Question

0.00/5 (No votes)

See more:

Python

n1 = 1
n2 = 2
sum = 0
for i in range(1,4000000):
    nth = n1 + n2
    n1 = n2
    n2 = nth
    if n1%2 == 0:
        sum += n1
    elif n2%2 == 0:
        sum += n2
print("the even terms sum is",sum)

this is my approach. I use pycharm but in pycharm the run window prints nothing.I used an online ide and I was getting this:
"Time Limit Exceeded"

I am a beginner so please explain it in a little detail

What I have tried:

n1 = 1
n2 = 2
sum = 0
for i in range(1,4000000):
    nth = n1 + n2
    n1 = n2
    n2 = nth
    if n1%2 == 0:
        sum += n1
    elif n2%2 == 0:
        sum += n2
print("the even terms sum is",sum)

Posted 1-Jul-19 5:13am

Member 14517556

Updated 2-Jul-19 10:05am

Add a Solution

3 solutions

Solution 2

See The Python Tutorial — Python 3.7.4rc1 documentation[^]

Posted 1-Jul-19 6:33am

Richard MacCutchan

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

raddevus · Accepted Answer · 2019-07-02T10:06:00

I'll give you a quick 2nd answer to your follow-up comment.

The steps you want to take are:
1. move for loop into a function that takes min and max loop values
2. return the sum
3. call the function in an outer loop
4. each time the outer loop runs, print the sum value so you can see process running (with output) even though it will take a long time for the entire program to run.

I'm no Python wiz and this is untested code, but it'll look something like the following:
Loop will run 1-10, 11-20, 21-30, etc. to max (1000)

Python

loopMultiplier = 0;
localSum = 0;
// this is the outer loop that calls the function doFib() multiple times
// each time thru the outer loop you will get a print so you can see it running
for x in range (1, 1000)
    localSum += doFib((loopMultiplier *x) +1, loopMultiplier * x)
    loopMultiplier += 10
    print("the even terms sum is ",localSum)

def doFib(minVal, maxVal) : 
   n1 = 1
   n2 = 2
   sum = 0
    for i in range(minVal,maxVal):
        nth = n1 + n2
        n1 = n2
        n2 = nth
        if n1%2 == 0:
            sum += n1
        elif n2%2 == 0:
            sum += n2
    return sum

raddevus · Accepted Answer · 2019-07-01T05:21:00

Solution 1

It's doesn't do any printing until the for loop is done.
The print statement only runs after the for loop has iterated through 4 million times.

You are getting the

"Time Limit Exceeded"

message because it's taking a long time.

Have you tried a smaller number in the for loop to see if you get something?

Try:

Python

for i in range(1,200):

Posted 1-Jul-19 5:21am

raddevus

Comments

Member 14517556 1-Jul-19 23:50pm

Yeah! It worked but can we not use such big numbers. Is there any other method to do so. If you know one please share. Thank you for your answer