Simplifying Operator Overloading .

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C++

Hey

I have a class named Yup and it has one data member of type int(called number).
I have overloaded the cout and + operators.

cout<<object(type Yup)==> prints the number.
The object1+object2 adds the numbers of 2 objects.

In the main I have

Yup t(23),t1(27);

When I do this: Yup t2=t+t1; cout<<t2<<endl;==> I get 50;


When I do this: cout<<(t+t1)<<endl; ==> I get -87293...

How can i write it in one line?
How it is compiled?

ostream &operator<<( ostream &output, const Yup &num )
{
    output<<num.number;
    return output;
}

Yup &operator+(const Yup &tr1,const Yup &tr2 )
{
    Yup k(0);
    k.number=tr1.number+tr2.number;
    return k;
}