Array traversing by for loop

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I have an array suppose "ar" which has a number of elements.I want to travers or process the array elements according to a integer variable suppose "a" which can have 0 or 1 or 2 or 3 or 4 or or 5 or 6 and so on.....

Suppose ar has elements 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31...

What i want when a=0 then the loop process the element 1 of ar
If a=1 thn process the elements 2,3 of ar
If a=2 thn process the elements 4,5,6,7 of ar
if a=3 thn process the elements 8,9,10,11,12,13,14,15 of ar
If a=4 thn process the elements 16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31 of ar
and so on......

Please if any one can do this i m thankful to him

thanks a lot in advance.........

Please everyone code project is a community with the greatest minds i need to solve this problem urgently please help..........

Posted 23-Oct-12 18:45pm

VINAY SOROUT

Updated 23-Oct-12 19:23pm

v2

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Comments

Sergey Alexandrovich Kryukov 24-Oct-12 1:00am

Not a question. What did you try? What's the problem?
--SA

VINAY SOROUT 24-Oct-12 1:04am

Its a question sir. I am doing a multi level marketing project where i need this implementation.......

Sergey Alexandrovich Kryukov 24-Oct-12 10:25am

Even this is not a question. Do I need to explain what's a question? Just do your work by yourself, show your code, and explain where it works not as you expected, to get help. Right now, you want someone to do this boring work for you, without explanation of the purpose. For your evil marketing (yes, this is evil)? Then what this sequences do to your work?
OK, nobody will do you work for you anyway, I guess. What technical aspects you don't understand? We can help you.
--SA

VINAY SOROUT 24-Oct-12 13:36pm

furrrrrrrr f*** u i did it by my own i dont need people like you to help me.....

Sergey Alexandrovich Kryukov 24-Oct-12 15:12pm

Like me..? Now, that nice of you.
I can imagine how your anger improves you reputation.
--SA

Sushil Mate 24-Oct-12 1:33am

multi level marketing? its very simple? what's the big deal in this? its "Not a question" for greatest mind :)

VINAY SOROUT 24-Oct-12 1:41am

so the greatest mind like you are not going to solve this, because its not a your level question. sir may i know what is your level so that i will be careful while posting my questions............
people like you when cant solve a problem say this type of words......

Sushil Mate 24-Oct-12 1:48am

Don't get hyper, didn't mean to offend you. the question you are asking is not a big deal. what have you tried towards this problem. just posting your needs/requirements & asking for solution is not going to work here. greatest mind will give you advice/idea but they cant give you code. & seriously i don't count myself as greatest mind here. i was talking about SA who posted before me. so try to solve by your self & if you stuck somewhere let us know instead of getting into my level.
hope this helps :)

VINAY SOROUT 24-Oct-12 1:53am

sir i m trying to sole it from last 50 hours continuesly but i didnt get the solution so thats why i put this question here so that one of this community member can solve it and post the answer.......

Sushil Mate 24-Oct-12 1:56am

show us your code & other CPians will take you seriously.
update your question with your code.. & point out where you stuck

VINAY SOROUT 24-Oct-12 2:08am

i alredy point out my problem this question is my point where i stuck.....

6 solutions

Solution 1

Seems to me like in your simple for next you need to multiply a count variable by 2.
You have to declare the count variable outside the loop and initialise it to 1.
Inside the loop you have to use the count variable to do you processing of the elements in the array starting from the count and for the next count elements. So you'll need a second loop within the first loop.

Posted 23-Oct-12 21:09pm

Philip Stuyck

Solution 2

C#

var x = Convert.ToInt32(Math.Pow(2, a));
var result = new int[x];
for (var i = 0; i < x; i++)
    result[i] = x + i;

Posted 23-Oct-12 21:35pm

Clifford Nelson

Solution 3

This Code may help you

C#

for (int i = 0; i < arrayName.Length; i++)
        {
            for (int j = Convert.ToInt32(Math.Pow(2, i)); j < arrayName.Length; j++)
            {
                //write your Code here.
            }
        }

Philip Stuyck gave very good Idea.

Posted 23-Oct-12 21:46pm

Mac12334

Solution 4

First of all you must have a function to retrieve power of 2

public int powerto(int b)
   {
           int res=1;
           for (int i = 1; i <= b; i++)
           {

                   res = res * 2;

           }
           return res;
   }

get your array filled with required numbers from user.
(you can use dynamic array too.)

then use the code below to retrieve your series of no.

C#

a = Convert.ToInt16(Console.ReadLine());
          int from = o.powerto(a)-1;
          int to = from+from ;
          for (int p = from; p <= to; p++)
          {
              Console.WriteLine(ar[p]);
          }
            

          Console.ReadLine();

Posted 23-Oct-12 22:04pm

Akkywadhwa

Solution 5

You should see a pattern in the requirements, namely a value selects both the start of the to-be-processed sequence and its length:

start = 2^a -1
length = 2^a

Posted 23-Oct-12 22:44pm

CPallini

Updated 23-Oct-12 22:47pm

v2

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VINAY SOROUT · Accepted Answer · 2012-10-23T22:46:00

Solution 6

At last i did it correct solution of this is:
if a=0 do coding remeber this if a=0 we just simply process the first element of array

if a>0 than

int t=0;
for(int t1=1;t1<=a;t1++)
{
t=t+math.pow(2,t1-1);
}

now to get the elements of array

for(int f=t;f<=t*2;f++)
{
process ar[f];
}

its working properly thanks for all of your supports....

Posted 23-Oct-12 22:46pm

VINAY SOROUT

Comments

CPallini 24-Oct-12 4:50am

You don't need the first loop, since: 2^0 + 2^1 + .. + 2^n = 2^(n+1) - 1

VINAY SOROUT 24-Oct-12 5:01am

same thing doesnt matter thanks a lot