User already exits in sql server

Question

1.00/5 (2 votes)

See more:

User already exits in stored procedure ?

When enter duplicate username alert message is display User Name is already exits ?

Posted 6-Sep-12 2:08am

Giletwala Dhaval

Add a Solution

Comments

Abhinav S 6-Sep-12 8:14am

Tried anything?

[no name] 6-Sep-12 8:15am

Please improve your question. it is not clear.
You can also share some of your code.

ZurdoDev 6-Sep-12 8:16am

This is not clear at all. Just a guess, but check to see if the user exists in whatever your table is and if it does, return a message.

3 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Tejas Vaishnav · Answer 1 · 2012-09-06T02:19:00

you can check it by using select query with where condition on user name if it will return any record then you can say that your user name is already exists in database.

or if you have put any unique contain on username then while inserting same username in database then it will throw error for violating unique constrain. so on that error filtering with that error message you can say that your user is already exists in database.

Prasad_Kulkarni · Answer 2 · 2012-09-06T02:16:00

Have you tried google[^]

A simple search with your question gives 2,320,000 results, and many of those search results surely solve your problem.

Try something first, although you are a beginner. This is not at all appropriate Dhaval. Try something by your side first and then post your question if you get stuck'd somewhere.

Giletwala Dhaval · Answer 3 · 2012-09-07T23:52:00

SQL

IF Not Exists(SELECT fieldname FROM fieldmaster WHERE fieldname = @fieldname)
    insert into fieldmaster (fieldname, tooltip, label,labelalign, controltype, controlalign,
     [values], defaultvalues, minlength, maxlength, [required], [validation], isactive)
     values (@fieldname, @tooltip, @label, @labelalign, @controltype, @controlalign,
     @values, @defaultvalues, @minlength, @maxlength, @required, @validation, @isactive)
    END

SQL

BEGIN
    IF Exists (select id  from fieldmaster where fieldname = @fieldname)
    BEGIN
    Declare @ids as int = 0
    select @ids = id from fieldmaster where fieldname = @fieldname
    if(@id=@ids)
    BEGIN
    Update fieldmaster set fieldname = @fieldname, tooltip=@tooltip, label=@label, labelalign=@labelalign,
     controltype= @controltype, controlalign=@controlalign, [values]= @values, defaultvalues=@defaultvalues,
     minlength=@minlength, maxlength= @maxlength, [required]= @required, [validation] =@validation, isactive = @isactive where id = @id
    END
    END
    ELSE
    BEGIN
    Update fieldmaster set fieldname = @fieldname, tooltip=@tooltip, label=@label, labelalign=@labelalign,
     controltype= @controltype, controlalign=@controlalign, [values]= @values, defaultvalues=@defaultvalues,
     minlength=@minlength, maxlength= @maxlength, [required]= @required, [validation] =@validation, isactive = @isactive where id = @id
    END
    END

User already exits in sql server

3 solutions

Solution 2

Solution 1

Solution 3

Add your solution here

Preview 0