problem regarding order by

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i want to arrange the data according to financial year month ....and my financial years goes like this april,may ,june ,july and so on ......i want the order in this way

Posted 14-Jun-12 18:11pm

vijay bisht

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2 solutions

Solution 1

Use this:

SQL

SELECT --whatever
...
...
ORDER BY DECODE(month, 'April', 0, 'May', 1, 'June', 2, 'July', 3, 'August', 4, 'September', 5, 'October', 6, 'November', 7, 'December', 8, 'January', 9, 'February', 10, 'March', 11, 12)

If the month is stored as an integer (e.g. Jan=1, Feb=2,...):

SQL

SELECT --whatever
...
...
ORDER BY ((month + 9) % 12)

Posted 14-Jun-12 18:35pm

krumia

v2

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vijay bisht · Accepted Answer · 2012-06-14T19:09:00

SQL

BEGIN
select distinct(datename(month,date))  as AccountName,(CASE WHEN DATEPART(MM,date)=4 THEN 1
WHEN DATEPART(MM,date)=5 THEN 2
WHEN DATEPART(MM,date)=6 THEN 3
WHEN DATEPART(MM,date)=7 THEN 4
WHEN DATEPART(MM,date)=8 THEN 5
WHEN DATEPART(MM,date)=9 THEN 6
WHEN DATEPART(MM,date)=10 THEN 7
WHEN DATEPART(MM,date)=11 THEN 8
WHEN DATEPART(MM,date)=12 THEN 9
WHEN DATEPART(MM,date)=1 THEN 10
WHEN DATEPART(MM,date)=2 THEN 11
WHEN DATEPART(MM,date)=3 THEN 12

END )
as date from tableabc order by mn