what the need of void in between the brackets?

Question

3.29/5 (4 votes)

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void getdata(void)

it also work with blank bracket then why?

Posted 28-May-12 8:01am

zerox 2

Updated 28-May-12 11:15am

CPallini

v2

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Sergey Alexandrovich Kryukov 28-May-12 14:09pm

Do you think there is only one language in the world, the one you are familiar with? :-) Tag it.
--SA

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Sergey Alexandrovich Kryukov · Accepted Answer · 2012-05-28T08:13:00

Solution 2

The simple answer is: "why not"? The empty list in round brackets is very natural, it means "no arguments" are passed to the function in question, "empty argument list". It's rather using void parameter is quite a perverted, historical syntax, which is going out of practice. Just think about, why its function(void); why not function(void, void)? :-) Why an empty list, that is, a list with zero elements, should be expressed as a list of one element? Very artificial syntax agreement, no wonder it's now used anywhere else and hardly used in modern C/C++ code.

—SA

Posted 28-May-12 8:13am

Sergey Alexandrovich Kryukov

Updated 28-May-12 8:17am

v3

Comments

OriginalGriff 28-May-12 14:22pm

That's not quite true for C
void foo();
is not the same as
void foo(void);
The former is a "acceptable" prototype for a function taking any parameters rather than a function taking no parameters (depreciated in C 1999)

Sergey Alexandrovich Kryukov 28-May-12 14:31pm

Thank you very much for this note. By the way, 1) OP did not specify the language, so this is all of somewhat abstract character, 2) this fact is yet another reason to avoid using foo(void).
--SA

OriginalGriff 28-May-12 14:35pm

Very true in both cases! :laugh:

Sergey Alexandrovich Kryukov 28-May-12 15:25pm

:-)
--SA

Andreas Gieriet 28-May-12 16:23pm

My 5 too.
Andi

Sergey Alexandrovich Kryukov 28-May-12 16:26pm

Thank you, Andi.
--SA

OriginalGriff · Accepted Answer · 2012-05-28T08:19:00

If you are using C++, then there is no difference, it is a "hangover" from the base language C

C++

void foo(void) {}

is the equivelent of

C++

void foo();

In that they both declare a function that takes no parameters.

However, in C the situation is a little different:

C++

void foo(void);

Declares a function that takes no parameters.

C++

void foo();

Declares a function that will take any parameters. (This usage was depreciated in the 1999 C spec).

Andreas Gieriet · Accepted Answer · 2012-05-28T08:12:00

Solution 1

You talk about C or C++, right?
The designers of the language decided to allow both variations of function declarations:

C++

SomeType F() { ... }

and

C++

SomeType F(void) { ... }

are equivalent.

Cheers
Andi

Posted 28-May-12 8:12am

Andreas Gieriet

Comments

Sergey Alexandrovich Kryukov 28-May-12 14:15pm

Of course, a 5. We were writing our answers at the same time, you might be curious enough to see mine...
--SA

Andreas Gieriet 28-May-12 16:20pm

Yeah. We happen to respond at similar times again ;-)
Cheers
Andi

what the need of void in between the brackets?

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