How to set the length of Binary Number in C#

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I am developing a program where I need to generate a random binary number. each binary number should have fixed length of 6 in size eg. 55= "110111" size is 6 but 10="1010"
so to make its size equal to 6 I want to add zero on right and it should look like
10="001010" instead of "1010".
So,How to set the length of binary number????

Posted 9-May-12 11:41am

sonal_1785

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Sergey Alexandrovich Kryukov 9-May-12 17:51pm

Why? Do you understand that your strings are not numbers? How about using with data, not with strings representing numbers? What is the goal of it?
--SA

Sergey Alexandrovich Kryukov 9-May-12 17:53pm

Your problem does not seem to make any practical sense, but what prevents you from having all strings of the same length? You could start form 0-filled string of required length.
--SA

sonal_1785 9-May-12 18:16pm

My motive is to calculate Hamming distance. for that length of the string should be equal. eg
110011001
101010101XOR
011001100

2 solutions

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aidin Tajadod · Accepted Answer · 2012-05-09T13:08:00

Solution 2

I think it is what you want.

C#

Random rnd = new Random();
            int number = rnd.Next(64);
            string retVal = Convert.ToString(number, 2);
            retVal = retVal.PadLeft(6, '0');
            MessageBox.Show(retVal);

Posted 9-May-12 13:08pm

aidin Tajadod

Comments

sonal_1785 9-May-12 21:12pm

thanks for the help....this is exactly i was looking for.

aidin Tajadod 10-May-12 12:25pm

Happy to help.

Clifford Nelson · Accepted Answer · 2012-05-09T12:39:00

Solution 1

The following will give you the number of bits you need for a number:

C#

int n = 6;
var len =Math.Round (Math.Pow(n + 1, .5) + .5);

Just add one to get the length that will always start with a 0.

Posted 9-May-12 12:39pm

Clifford Nelson

Updated 9-May-12 12:40pm

v2