Problem Of [ with Sql Statement

Question

0.00/5 (No votes)

See more:

SQL-Server-2005

iam searching item table & i use like statment
example

SQL

declare @x nvarchar(1000)
select @x='ddd'

select * from item where lower(itemname) like lower(@x)+'%'

it work fien no problem
but if the item name contain [ it doesn't appear in the search
eban when i wrote this is statement no result

SQL

select * from item where itemname like '%[%'

so can any body help me

Posted 6-May-12 0:28am

md_refay

Updated 6-May-12 0:30am

Maciej Los

v2

Add a Solution

Comments

Maciej Los 6-May-12 6:30am

Code tags added

OriginalGriff 6-May-12 6:48am

Answer updated

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Accepted Answer · 2012-05-06T00:46:00

Solution 1

It's because LIKE is a simple Regex processor, and '[' introduces a sequence of characters:
...LIKE 'x[abc]x' would match any of 'xax', 'xbx' or 'xcx' but would not match 'xdx'

See here: http://www.w3schools.com/sql/sql_wildcards.asp[^]

I don't know how you get round it though...

[edit]
Oh yes I do:

SQL

SELECT * FROM item WHERE itemname LIKE '%[[]%'

[/edit]

Posted 6-May-12 0:46am

OriginalGriff

Updated 6-May-12 0:47am

v2

Comments

Maciej Los 6-May-12 6:53am

+5!

Mohamed Mitwalli 6-May-12 7:55am

+5