Display data from the selection of two listboxes

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Hi All,

Assume that we have two Listboxes, one includes Departments and the second includes all the people in a company.

Now, when I select a department from lstDept listbox and some people from lstPeople listbox, I want to show the selected items in a treeview or something else (with a good layout).

Does anybody knows how can I show that in a good layout?

Thank you.

Posted 6-Dec-11 2:58am

enginbilici

Updated 6-Dec-11 3:38am

RaisKazi

v3

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2 solutions

Solution 1

try this code:

C#

private void Form1_Load(object sender, EventArgs e)
        {
            listBox1.Items.Add("Development");
            listBox1.Items.Add("Testing");
            listBox1.Items.Add("HR");
            listBox1.Items.Add("Admin");
            listBox1.Items.Add("External Affairs");
            listBox2.Items.Add("EmpIDone");
            listBox2.Items.Add("EMpIDTWo");
            listBox2.Items.Add("EMptree");
        }

        private void listBox1_SelectedIndexChanged(object sender, EventArgs e)
        {


            bool isExists = false;

            foreach (TreeNode node in treeView1.Nodes)
            {
                if (node.Text == listBox1.SelectedItem.ToString())
                {
                    isExists = true;
                    return;
                }
            }

            if (!isExists)
            {
                treeView1.Nodes.Add(listBox1.SelectedItem.ToString());
            }

        }

        private void listBox2_Click(object sender, EventArgs e)
        {
            foreach (TreeNode node in treeView1.Nodes)
            {
                if (node.Text == listBox1.SelectedItem.ToString())
                {
                    TreeNode currentnode = node;
                    currentnode.Nodes.Add(listBox2.SelectedItem.ToString());
                }
            }
        }

Posted 6-Dec-11 5:41am

S V Saichandra

Comments

enginbilici 6-Dec-11 11:55am

Hi, first of all thank you for your interest.
treeView1.Nodes.Add(listBox1.SelectedItem.ToString()); ---> this line has throw an error and I have changed it to
-------
TreeNode node = new TreeNode();
node.Text = listBox1.SelectedItem.ToString();
TreeView1.Nodes.Add(node);
-------

TreeNode currentnode = node;
currentnode.Nodes.Add(listBox2.SelectedItem.ToString()); ---> this line has an error too but I could not solve it and I changed it to
--------
currentnode.ChildNode.Add(node);
--------

It does not throw any error but, It only adds the items of listbox1, does not adds listbox2 to nodes.
Thanks again...

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S V Saichandra · Accepted Answer · 2011-12-06T21:28:00

Asp.Net Listbox and Tree View Code Updated:
UI:

XML

<table>
    <tr>
    <td> <asp:ListBox ID="listBox1" runat="server" Height="192px"
        onselectedindexchanged="ListBox1_SelectedIndexChanged" Width="147px"
            AutoPostBack="True"></asp:ListBox></td>
    <td> <asp:ListBox ID="listBox2" runat="server" Height="190px"
        onselectedindexchanged="ListBox2_SelectedIndexChanged" Width="142px"
            AutoPostBack="True"></asp:ListBox></td>
    <td> <asp:TreeView ID="TreeView1" runat="server">
    </asp:TreeView></td>
    </tr>
    </table>

Csharp Code:

C#

  protected void Page_Load(object sender, EventArgs e)
    {
        if (!IsPostBack)
        {
            listBox1.Items.Add("Development");
            listBox1.Items.Add("Testing");
            listBox1.Items.Add("HR");
            listBox1.Items.Add("Admin");
            listBox1.Items.Add("External Affairs");
            listBox2.Items.Add("EmpIDone");
            listBox2.Items.Add("EMpIDTWo");
            listBox2.Items.Add("EMptree");
        }

    }

protected void ListBox1_SelectedIndexChanged(object sender, EventArgs e)
   {

       foreach (TreeNode node in TreeView1.Nodes)
       {
           if (node.Text == listBox1.SelectedItem.Text)
               isExists = true;
       }
       if (!isExists)
       {
           TreeView1.Nodes.Add(new TreeNode(listBox1.SelectedItem.Text));
       }
   }
   protected void ListBox2_SelectedIndexChanged(object sender, EventArgs e)
   {
       foreach (TreeNode node in TreeView1.Nodes)
       {
           if (node.Text == listBox1.SelectedItem.ToString())
           {
               TreeNode currentnode = node;
               currentnode.ChildNodes.Add(new TreeNode(listBox2.SelectedItem.Text));
           }
       }

   }